x27;t" (Unknown)
- Original Message -
From: "Jordan Morgan" <[EMAIL PROTECTED]>
To: "Nobody" <[EMAIL PROTECTED]>
Cc: "Diana Soares" <[EMAIL PROTECTED]>; "mysql" <[EMAIL PROTECTED]>
Sent: Friday, October 10, 2003 2:24 PM
Subj
nd binary and those who don't" (Unknown)
> - Original Message -
> From: "Diana Soares" <[EMAIL PROTECTED]>
> To: "Jordan Morgan" <[EMAIL PROTECTED]>
> Cc: "mysql" <[EMAIL PROTECTED]>
> Sent: Friday, October 10, 2003 8:5
oh thanks! I guess that's why I'm a newbie.
Diana Soares wrote:
> Look at:
>
> if ($tenureid=3)
>
> You're not comparing $tenureid with 3, you're assigning 3 to
> $ternureid... If you want to compare both values, you must use the
> operator "==" (and not only "=").
>
> On Fri, 2003-10-10 at 0
ot; <[EMAIL PROTECTED]>
To: "Jordan Morgan" <[EMAIL PROTECTED]>
Cc: "mysql" <[EMAIL PROTECTED]>
Sent: Friday, October 10, 2003 8:58 AM
Subject: Re: newbie select statement question
> Look at:
>
> if ($tenureid=3)
>
> You're not comparing $tenure
Look at:
if ($tenureid=3)
You're not comparing $tenureid with 3, you're assigning 3 to
$ternureid... If you want to compare both values, you must use the
operator "==" (and not only "=").
On Fri, 2003-10-10 at 05:43, Jordan Morgan wrote:
> Hi,
>
> I have the following statement:
>
> echo "$te
Hi,
I have the following statement:
echo "$tenureid";
if ($tenureid=3)
{
// get faculty employment record - award date
$sql = "select TD.Award_Date from TenureDescription TD LEFT JOIN
InstitutionEmployment IE on TD.TenureDescriptionID=IE.Tenure WHERE
IE.FacultyMember='$fid'";
$result = mysq
