This is rather problem about javascript than PHP -
But I think that you need to use double quotes (escaped) to distinguish query and
variables in your javascript query:
Try out this, It work fine for me:
if(!isset($HTTP_SESSION_VARS['svUserAccess'])){
echo "Login";
} else {
echo "Logout";
w
That's the thing, everything works but the error message keeps coming up?
Runtime Error: Syntax Error
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And the error is??
> -Original Message-
> From: vernon [mailto:vernon@;comp-wiz.com]
> Sent: Sunday, November 03, 2002 9:28 PM
> To: [EMAIL PROTECTED]
> Subject: [PHP] Error in code - Seems simple enough
>
> I'm having trouble with the following code dispalying an error, which
I
> don't u
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