yes, i use the 2th way
<[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> Hi
>
> The second style can be used:
>j = range(20)
> print j
> L = [x for x in j if x > 10]
> j = L
>
> There are another method such poping the item based on last index to 0:
> for i in range(len(j)-1,
yes. i understand now.
but i use another trick.
list is in vary size, so i do not wanna copy it.
"Jim" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> MaHahaXixi wrote:
> >>>>j = range(20)
> >>>>print j
> >
> > [0, 1, 2
SORRY, my inattention
"Fredrik Lundh" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> "MaHahaXixi" <[EMAIL PROTECTED]> wrote:
>
> > for python, i am a newbie, but i did not found the warning of such usage
> > from the python tutori
yes. i think it does so.
it take me the whole afternoon to find out the bug (mine)
i change:
for i in range(len(j) -1, -1, -1):
d = j[i]
if d <= 10:
j.remove(d)
the real code is not so simple,so j[11:] will not work for me.
but, i think phthon could found that i remove the current e
>>> j = range(20)
>>> print j
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19]
>>> for k in j:
if k <= 10:
j.remove(k)
>>> print j
[1, 3, 5, 7, 9, 11, 12, 13, 14, 15, 16, 17, 18, 19]
>>>
Python 2.3.4 (#53, May 25 2004, 21:17:02) [MSC v.1200 32 bit (Intel)] on
win32
Type