Hi
I had to use a glm instead of my basic lm on some data due to unconstant
variance.
now, when I plot the model over the data, how can I easily get the 95%
confidence interval that sormally coming from:
> yv <- predict(modelVar,list(aveLength=xv),int="c")
> matlines(x
Hi Barry,
Sorry for not being clear.
"Not work" == "Doesn't add the text to the ylab"
My initial example was intended with no line breaks.
Here it is again with variations:
plot(1)
title(ylab = expression(paste("test
ln
On Tue, Sep 28, 2010 at 10:03 AM, Tal Galili wrote:
> Hello,
>
> It seems that there is a problem when plotting an expression in the ylab of
> a plot in case it is too long.
>
> Example:
>
> plot(1)
> title(ylab = "test
> looo
Hello,
It seems that there is a problem when plotting an expression in the ylab of
a plot in case it is too long.
Example:
plot(1)
title(ylab = "test
looong
") # work
plot(1)
title(ylab = expression(paste("test (% of 360" *d
On Mon, 27 Sep 2010, bo...@hsu-hh.de wrote:
Dear R-help list members,
I have the following question concerning the strucchange()-package: is it
possible to get the boundaries for one-sided (upper / lower) CUSUM and MOSUM
tests?
Not out of the box, at least not exactly. You can do this:
lib
Le 28/09/10 08:43, Dmitrij Kudriavcev a écrit :
Hello All,
A simple question.
I get some return from the R in my C++ program (via Rcpp package). The
result come, as SEXP and it should be a simple numeric variable.
How to convert it to double?
The code, what i use:
stringstream ss;
ss<< "p<
What Titus wants to do is akin to retrieving capturing groups from a
Matcher object in Java. I also thought there must be an existing,
elegant solution to this some time ago and searched for it, including
looking at the sources (albeit with not much expertise) but came up
blank.
I also looked at t
On 09/28/2010 02:34 AM, Jonas Josefsson wrote:
I have a two-column table as follows where age is in the 1st column and
the number of individuals is in the 2nd.
age;no
1;21
2;31
3;9
4;12
5;6
Can I use mean() and sd() to calculate the mean and standard deviation
from this or do I have to manuall
Thank you Peter for your help.
I had tried hclust before but I made the mistake of using the D matrix above
instead of a dist object. Hence
library(flashClust)
d <- as.dist(D)
# Clustering using hclust
hc <- hclust(d, method = "median",members=NULL)
# Clustering using flashClust
fc
Hello All,
A simple question.
I get some return from the R in my C++ program (via Rcpp package). The
result come, as SEXP and it should be a simple numeric variable.
How to convert it to double?
The code, what i use:
stringstream ss;
ss << "p <- predict(fit_ar11, n.ahead = 2, doplot=FALSE);"
Thanks
I eventually tracked down the problem to something unrelated to this
question (one out of the millions of character strings happened to be
"NA" by chance, which of course was parsed as a missing value, breaking
the code a long way downstream.)
Richard
On 28/09/2010 04:01, Michael
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