Hello,
Where can I find info about the operator %%?
Never used it but when I search for it I gives no result.
Thanks,
André
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do
Hello,
I have two dataframes:
dat1-data.frame(x=c(1.0,1.2,3.2,4.0,5.1),y=c(23,17,12,27,8))
dat2-data.frame(x=seq(0,6,by=0.1),y=rep(0,60)))
I want to replace the corresponding rows of dat2 with the ones of dat1.
I tried:
for(i in 1:nrow(dat1))
{
dat2[dat2$x==dat1[i,1],2]-dat1[i,2]
}
But I
Hello,
With which package can I build a yield curve using swap data with the
bootstrapping method?
Thanks for the reaction,
André
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
Hello,
Is it possible to convert a string to a variable?
I have a set of names:
stocks
[1] ACCELL AHOLD AJAXARCADIS BALLAST
BAM.GROEP
[7] BESIBETER.BED BINCKBANK.NVBOSKALIS
CATE CROWN.V.GELDER
And a data frame with stockquotes.
With a for-loop
Hello,
Can someone give me hint to change a data.frame.
I want to split a column in more columns depending on the value of a other
column.
Thanks for the reaction,
Andre
Example:
dat
x1 x2
1 1 a
2 1 b
3 1 c
4 2 d
5 2 e
6 2 f
7 3 g
8 3 h
9 3 i
in
dur
d1 d2 d3
1 a d g
Hello,
I searched the internet but i didn't find the answer for the next problem:
I want to do a glm on a csv file consisting of 25 columns and 4 mln rows.
Not all the columns are relevant. My problem is to read the data into R.
Manipulate the data and then do a glm.
I've tried with:
Hello,
I have a dataframe with data such as:
dat$BEGINDATUM[3]
[1] 13-09-2007
dat$BEGINDATUM[4]
[1] 01-11-2007
class(dat$BEGINDATUM[3])
[1] factor
Now I need to make calculation with these dates.
But I get these result:
as.date(as.character(dat$BEGINDATUM[3]))
[1] NA
Hi,
I have a data.frame with factors in columns like
startdate enddate
27SEP2005 01JAN2006
How can I calculate the duration between those two dates and move this in a
extra column in the data.frame.
Thanks,
André
[[alternative HTML version deleted]]
Hi,
Sorry for this simple question but I searched the internet and can't find
the answer.
From a date I want the year extracted:
data$start[1
[1] 2006-11-01
Thanks for the answer,
Andre
[[alternative HTML version deleted]]
__
Hi,
Suppose I have a dataframe like:
data
yx
1 1 2008
2 1 2008
3 0 2008
4 0 2009
5 1 2009
Now I want to know how much 1 corresponds with 2008 and how much with
2009, the answers are 3 and 1.
How can I achieve this? Thanks for the anwer.
André
Hi,
I want to eliminate an element of a list:
list - seq(1,5,1)
s - sample(list,1)
lets say s=3
Now I want to remove 3 from the list: list2 = {1,2,4,5}
Can someone give me a tip?
Thanks,
André
[[alternative HTML version deleted]]
__
11 matches
Mail list logo