quite workable, but not suitable for final version.
If you want both Word and PDF versions to look good, there is no
perfect solution. You could try generating the graphics as PNG,
which will look good (but not great) in both places. That
approach will likely increase file sizes considerably.
Hope
exist, in which case could someone give me some other idea
of how to accomplish this goal?
Thanks,
Mike
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PLEASE do read the posting guide http://www.R-project.org/po
Hi,
I'm having difficulties with Unicode characters with R 2.7.0 on Windows
XP SP2. I'd like to use a delta character, which I'd also like to mix
with other formatted output using paste() or sprintf(). On my system, I
can successfully do this with a static string:
print("\u0394Q = 2.2 L/s")
[EMAIL PROTECTED] wrote:
> Could someone help me on the following:
> SAS has DUD (Does not Use Derivatives) for nonlinear regression.
>
> Does "R" has a similar capability?
>
nls()
--
Mike Prager, NOAA, Beaufort, NC
* Opinions expressed are personal and not represe
)+1;
data[5,1:40]=runif(40)+3;
data[5,81:100]=runif(20)+5;
data[9,1:20]=runif(20)+2;
data[9,31:60]=runif(30)+4;
data[9,71:90]=runif(20)+6;
Many
thanks!
/Mike
On Fri, May 16, 2008 at 4:52 PM, mike Ad. wrote:
> Dear group,
>
> I have hundreds
> of independent data sets, ea
d a statistics method to automatically
pick out the data sets which have group pattern, or specifically found data
sets have certain number of groups, e.g. 2, 3, 4.
Are there
any functions or packages that could solve this issue, or any other suggestions?
Many Thanks!
/M
I've got a data frame having numerical data by zip code:
ZIP DATA
94111 12135.545
93105 321354.65654
94111 545.555
94706 558858.66
... ...
I'm using this function to group records by ZIP and calculate the median of
DATA:
aggregate(d$DATA, list(Zip = d$ZIP), F
od to calculate
the
standard errors - and I'm not sure what that method is or how to do it in R.
The gamlss package produces the closest results - but even those are still
not
exactly the same.
Mike
-Original Message-
From: Ted Harding [mailto:[EMAIL PROTECTED]
Sent: Wednesday, May 14, 20
plain this and point me in the right direction? I'd really
appreciate it.
Thank you,
Mike Ryckman
Department of Political Science
University of Arizona
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PLEASE do re
mpt yields the following error:
library('nlme')
lme(
x ~ gender*con*int*tone*cue
, random = ~ 1 | sub*age
, data = a
)
Error in getGroups.data.frame(dataMix, groups) :
Invalid formula for groups
I would be very grateful for any suggestions.
Cheers,
Mike
--
Mike L
s) ... :-)
I used filters for a while. Now, I read the R list through the
gmane Usenet interface. It appears to me to be a newsgroup,
rather than a huge collection of emails. I find that much
easier. See http://gmane.org/
--
Mike Prager, NOAA, Beaufort, NC
* Opinions expressed are personal a
GVKEY NPERMNO GIC year
10001 12994 10001 55102010 2007
10002 19049 10002 40101015 2007
10009 16739 10009 40101010 1999
Has this been made into a proper data frame. How come the row numbers are
not 1,2,3,4...?
Thank you so much, and I would really appreciate any help!
Thanks for the help. I tried out the one promising lead, curfit.free.knot,
and it doesn't work for linear or quadratic splines. The documentation says
it should, but when I specify a linear spline, it returns a cubic.
On 5/1/08, Spencer Graves <[EMAIL PROTECTED]> wrote:
>
> RSiteSearch('fr
around the knot locations to minimize the loss function.
Mike
[[alternative HTML version deleted]]
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s give the
appearance of more precision than is really represented.
--
Mike Prager, NOAA, Beaufort, NC
* Opinions expressed are personal and not represented otherwise.
* Any use of tradenames does not constitute a NOAA endorsement.
__
R-help@r-project.or
(mydf, mydf$TIME), function(x){coefficients(summary(glm(X ~ A +
B, data = x, family=binomial)))})
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On
Behalf Of Mike H. Ryu
Sent: Tuesday, April 29, 2008 7:27 AM
To: r-help@r-project.org
Subject: [R] Running regression (lm
n the regression for each month, but I need
to know how I would combine the regression results together into a matrix
possibly.
Thank you!
Mike
---
m = max(data$TIME)
# define regmatrix
for(i in 1:m){
g=runreg(data, i)
# attach g to regmatrix
}
r
ll persist
across script runs and even sessions.
You may need to change the code to suit your own needs.
Does that help?
Mike
> [...]
> But the end of your response hits on the key issue: when I create
> several graphs, I would like to be able to use PgUp/PgDn or some other
> keyst
not use
xs <- seq(min(x1), max(x1), length = 100) instead of
xs <- with(m, seq(min(x1), max(x1), length = 100)) ?
Second, what is the function geom_line()? I couldn't find it.
Thanks,
Mike
On 4/23/08, hadley wickham <[EMAIL PROTECTED]> wrote:
>
> On Wed, Apr 23, 2008 at
The code I wrote does this using predict() which is useful for modeling
approaches like GAMs.
Mike
On Wed, Apr 23, 2008 at 8:47 PM, hadley wickham <[EMAIL PROTECTED]> wrote:
> On Wed, Apr 23, 2008 at 7:31 PM, Mike Dugas <[EMAIL PROTECTED]> wrote:
> > Thanks for the help. Th
Thanks for the help. That explains why my time testing showed no
difference. Is there any way to speed up the program? It is unbearably
slow if I increase the number of loops.
Mike
On Wed, Apr 23, 2008 at 6:23 PM, hadley wickham <[EMAIL PROTECTED]> wrote:
> On Wed, Apr 23, 2008 a
, 1112, byrow=T)
a[2,] <- apply(b,2,FUN=function(x)
{mean(predict(lm1,cbind(m[,-match("x1",names(m))],x1=x))) })
plot(a[1,],a[2,],xlab="x1",ylab="Response",type="l",main="Partial Dependence
Plot")
Mike Dugas
[[alternative HTML version
$x1))/ +
min(m$x1),c(0:)*0-9)
for(i in c(0:))
{
a[2,i+1] <-
mean(predict(lm1,cbind(m[,-match("x1",names(m))],x1=a[1,i+1])))
}
plot(a[1,],a[2,],xlab="x1",ylab="Response",type="l",main="Partial Dependence
Plot")
Many thanks,
# cancel redirection
options(width = tmp.wid) # restore linewidth
return(invisible(NULL)) # return (nothing) from
function
}
##
--
Mike Prager, NOAA, Beaufort, NC
* Opinions expressed are personal and not represented otherwise.
* An
ut this isn't urgent enough to have prodded me into writing
> it before now.
A finite size would be nice. I've been using this code in
scripts:
graphics.off()
windows(record = TRUE)
.SavedPlots <- NULL
Not exactly the same thing, but it limits memory use.
Are there side effects th
Hello everyone,
I know I can save a snapshot an rgl device, but currently it only appears to
do png format. Is there some way of exporting a high-quality picture more
fit for publication?
Thanks,
Mike
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https
require(lattice)
?levelplot
--
Mike Prager, NOAA, Beaufort, NC
* Opinions expressed are personal and not represented otherwise.
* Any use of tradenames does not constitute a NOAA endorsement.
__
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https://stat.ethz.ch/ma
all simulations. Can anyone help me with this?
Take a look at help pages of the following functions: mean,
apply, abline.
--
Mike Prager, NOAA, Beaufort, NC
* Opinions expressed are personal and not represented otherwise.
* Any use of tradenames does not constitu
asy
to modify my example to fit your question.
If you search the group archives, you should be able to find it.
The thread title was "background color in scatterplots".
MHP
--
Mike Prager, NOAA, Beaufort, NC
* Opinions expressed are perso
ngth(vrefs2), s = 0.15)
# Add the colors to the plot:
for (i in 2:length(vrefs2)){
polygon(c(vrefs2[(i-1):i], vrefs2[i:(i-1)]),
c(rep(pdims[3],2), rep(pdims[4],2)), col = cols[i],
border = NA)
}
# Draw the reference lines, points, and box:
abline(v = vrefs)
points(a, b, lwd = 1.5)
box()
Ayman,
It is difficult to say without seeing some code, but your output
seems to be not a list in the R sense but a collection of
vectors, each of length 1. The best way to put the values into a
vector probably is to assign them to the elements of the vector
during your computations.
Mike Prager
models. Psychometrika,
49, 37-47.
Regards,
Mike
--
-
Mike W.L. Cheung Phone: (65) 6516-3702
Department of Psychology Fax: (65) 6773-1843
National University of Singapore
http://courses.nus.edu.sg/course
I'm afraid I'm
not seeing it. I'd appreciate if anyone could point me in the right
direction. ( I have no trouble writing my own simple latex code and
converting it to pdf using pdftex in miktex).
Thanks,
Mike Babyak
Department of Psychiatry and Behavioral Science
Duke Univ
to an R Core person that my version of
> print.data.frame() be adopted as the
> system version, but was politely declined.
Rolf--
Clearly, and appropriately, R development is not a democratic
process. Still, if a vote were held, I would support your
version. I have also needed to suppress r
d
serve two purposes: making read.table() work on the data set and
making it easier for humans to check the data file more easily.
Second, you could look at read.fortran() -- a function that
takes a lightly modified Fortran format specification as an
argument. That seems even better for your
Hi all,
My initial searches on this yielded bupkis; I'm looking to access the
pixel-by-pixel data (preferably as a matrix, 0 for black, 1 for white)
of rendered letters(given a specific font, size, and dpi. Any
suggestions as to how to achieve this?
Mike
--
Mike Lawrence
Graduate St
;- i + 1
}
else{
garbage <- garbage+1
}
cat("i = ",i,"garbage = ",garbage,"\n")
}
-Original Message-----
From: Peter Dalgaard [mailto:[EMAIL PROTECTED]
Sent: Thursday, December 27, 2007 5:36 PM
To: Mike Jones
Cc: [EMAIL
7
initial i = 9
second i = 9
initial i = 10
second i = 10
> -Original Message-
> From: Mike Jones
> Sent: Thursday, December 27, 2007 4:35 PM
> To: '[EMAIL PROTECTED]'
> Subject: Conditionally incrementing a loop counter
>
> Hi,
> I
7;t seem to manually adjust i
because from what I understand, R creates 100 long vector and uses that
to "loops thru" and I'm not sure how to get at the index of that vector.
Any suggestions? Thanks in advance.
Mike Jones
Westat
1650 Research Blvd. RE401
R
essional use of
LaTeX.
At its root, this is a rather deep question: how open-source,
largely volunteer-developed software can survive over the long
term, while continuing to improve and maintain high standards.
We are rather early in the history of free software development
to know the answer.
"Edna Bell" <[EMAIL PROTECTED]> wrote:
> Hi R Gurus!
>
> This is definitely off topic, but I thought I'd try: what is the way
> to put in url's into a Latex file, please?
In future, you might want to post such questions in group
comp.text.tex
Mik
t;- NULL # Deletes any existing plot history
windows(record = TRUE, ...)
You might also be interested in the savePlot function, well
described in the R help files.
--
Mike Prager, NOAA, Beaufort, NC
* Opinions expressed are personal and not represented otherwise.
* Any use
viewed only a single package. I think basing reviews
> around a specific topic/methodology would be more useful than basing
> them around a single package.
I agree: Such articles would be welcome resources if published
either in JSS or in R-News.
--
Mike Prager, NOAA, Beaufort, NC
* Opini
Federico Calboli <[EMAIL PROTECTED]> wrote:
>
> I would like to output the results of a function into a text file,
> legible as a such. The function produces a summary quite like:
>
Take a look at the sink() function. Does that do what you need?
--
Mike Prager,
tax (and other) help by Googling than to pull the
reference manual off the shelf or start up an online help file.
--
Mike Prager, NOAA, Beaufort, NC
* Opinions expressed are personal and not represented otherwise.
* Any use of tradenames does not constitute a NOAA endorsement.
__
can't want to use lattice, because I have hundreds of plots.
So, to keep it simple, let's say I am plotting 3 series of boxplots
like,
boxplot(data1~groups,...)
boxplot(data2~groups,...)
boxplot(data3~groups,...)
Is there a way to get these into a single pdf file?
Thanks in advance...
Yes, that's exactly it!
Many thanks, it all comes back to me now! It's the darn do.call that I can
never remember somehow. I know I've reinvented this wheel several times --
you'd think I'd learn. Sigh.
Again, my thanks!
Regards,
Mike
On Nov 7, 2007 2:35 PM, jim
t I mean"? My doit function gets more and more ugly the more
summary statistics I add, and I worry about the "merge" with hundreds
of thousands of rows.
I'm almost sure I've seen a solution to what I know is a simple
problem, but I guess my search skills are as bad as my &q
re.
I agree with the suggestions made so far. Also, consider buying
or borrowing a copy of "Introductory Statistics with R" by Peter
Dalgaard. It is well written and brief.
--
Mike Prager, NOAA, Beaufort, NC
* Opinions expressed are personal and not represented otherwise.
* Any use of traden
Posting this for posterity and to demonstrate that a speed-up of 2
orders of magnitude is indeed possible! I can now run 1e5 monte carlo
experiments in the time the old code could only run 1e3. The final
change was to replace my use of cor() with .Internal(cor()), which
avoids some checks t
Had a realization this morning that I think achieves ceiling
performance and thought I'd share with the list. I was previously
generating sample data per participant and then calculating a mean,
but of course this could be simplified by simply getting a single
value from the sampling distri
Seems there were some line break issues when pasting the code, trying
again with a different commenting style:
#start a timer
start = proc.time()[1]
#set the true correllation
rho = .5
#set the number of Subjects
Ns = 100
#for each subject, set a number of observations in A
a.No = 1:100
#for
for B and grab the mean
}
sim.r[i] = cor(a,b) #store the observed correlation between A and B
}
print(proc.time()[1]-start) #show the total time this took
--
Mike Lawrence
Graduate Student, Department of Psychology, Dalhousie University
Website: http://memetic.c
--
>
> Ravi Varadhan, Ph.D.
>
> Assistant Professor, The Center on Aging and Health
>
> Division of Geriatric Medicine and Gerontology
>
> Johns Hopkins University
>
> Ph: (410) 502-2619
>
> Fax: (410) 614-9625
>
> Email: [EMAIL PROTECTED]
>
> Webpage: htt
iptions
as above (I'm exploring a large number of 'black boxes'). I do know
that the maximum must occur between -1 and 1 for all however. Please
advise on how I might use optimize more usefully.
Mike
--
Mike Lawrence
Graduate Student, Department of Psychology, Dalhousie Unive
stephen bond <[EMAIL PROTECTED]> wrote:
> Does R have any functions for C/Fortran style text formatting when a
> number needs to be output right-justified in a fixed length field?
>
> say '%2d %3d %5.3f'
?formatC
--
Mike Prager, NOAA, Beaufort, NC
* Opinions ex
I think the function you need is 'help.search'; try:
help.search("binomial")
and look for something obvious in the 'stats' package. A good deal quicker
and easier than posting to an internet forum!
Cheers, Mike.
cathelf wrote:
>
> Dear all,
>
> I
10,] -0.1937206 -0.564203311
> cor(a)
[,1] [,2]
[1,] 1.0 0.5
[2,] 0.5 1.0
But I'm looking to create data where the variables are non-normally
distributed (i.e. somewhat skewed). Any suggestions?
Mike
--
Mike Lawrence
Graduate Student, Department of Psychology, Dalhousie Un
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