I still struggling with this:
error massage:
> by(AlexETF,AlexETF$Industry,function(a) {filename = paste("C:/ab/",gsub("
> ","",a$Industry[1]),".txt",sep="")
+ print(filename)
+ write.table(a[,3,drop=FALSE],quote=FALSE,col.names=FALSE,row.names=FALSE)
+ }
+ )
[1] "C:/ab/Acc
Try this:
> t(apply(x, 1, function(r) table(factor(r, levels = seq_len(max(x))
1 2 3 4 5 6 7 8 9 10
[1,] 1 0 1 0 0 0 0 0 0 0
[2,] 0 2 0 0 0 0 0 0 0 0
[3,] 0 0 0 1 0 0 1 0 0 0
[4,] 0 0 0 0 0 1 0 1 0 0
[5,] 0 0 0 0 1 0 0 0 0 1
If you use aaply in the plyr package instead of apply then
r-help-boun...@r-project.org wrote on 01/25/2010 02:39:32 PM:
> x <- read.table(textConnection("col1 col2
> 3 1
> 2 2
> 4 7
> 8 6
> 5 10"), header=TRUE)
>
> I want to rewrite it as below:
>
> var1 var2 var3 var4 var5 var6 var7 var8 var9 var10
> 1 0 1 0 0 0 0
Thank you so much.
Lisa
--
View this message in context:
http://n4.nabble.com/Data-transformation-tp1289899p1289915.html
Sent from the R help mailing list archive at Nabble.com.
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Hi,
On Mon, Jan 25, 2010 at 5:39 PM, Lisa wrote:
>
> Dear all,
>
> I have a dataset that looks like this:
>
> x <- read.table(textConnection("col1 col2
> 3 1
> 2 2
> 4 7
> 8 6
> 5 10"), header=TRUE)
>
> I want to rewrite it as below:
>
> var1 var2 var3 var4 var5 var6 var7 var8 var9 var10
> 1
Well, I have no idea how to get from one to the other. There's
col1 and col2 but no var1 var2 var3, etc. I thought perhaps col1
was the row index and col2 was the column index, but that doesn't
match up either, and not all the cell values are 1.
So you will need to explain more clearly what you in
Dear all,
I have a dataset that looks like this:
x <- read.table(textConnection("col1 col2
3 1
2 2
4 7
8 6
5 10"), header=TRUE)
I want to rewrite it as below:
var1 var2 var3 var4 var5 var6 var7 var8 var9 var10
1 0 1 0 0 0 0 0 0 0
0 2
The same error for me:
"Not Found
The requested object does not exist on this server. The link you
followed is either outdated, inaccurate, or the server has been
instructed not to let you have it. Please inform the site
administrator of the referring page."
On Sun, Jan 24, 2010 at 3:14 PM, Pete
That's not the case for me:
Not Found
The requested object does not exist on this server. The link you
followed is either outdated, inaccurate, or the server has been
instructed not to let you have it.
Firefox 3.6
-Peter Ehlers
Velappan Periasamy wrote:
http://nseindia.com/content/equitie
http://nseindia.com/content/equities/scripvol/datafiles/01-01-2010-TO-23-01-2010RCOMXN.csv
the url is correct. it is not zipped file.
copy the url in the browser window you will get the
this ..
Symbol,Series,Date, Prev Close,Open Price,High Price,Low Price,Last
Price,Close Price,Average Pr
Your url is wrong. is missing ".zip" in the end.
See the code again.
On Sat, Jan 23, 2010 at 6:37 AM, Velappan Periasamy wrote:
> cannot open: HTTP status was '404 Not Found' while running the
> following commands
>
> f <- tempfile()
> download.file("http://nseindia.com/content/equities/scripvo
The same link works and dowloads data while copying and pasteing the
link in firebox address box.
the file is there and the server is active.
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PLEASE do read the posting gu
cannot open: HTTP status was '404 Not Found' while running the
following commands
f <- tempfile()
download.file("http://nseindia.com/content/equities/scripvol/datafiles/01-01-2010-TO-23-01-2010RCOMXN.csv";,
f)
myData <- read.csv(f)
On 1/19/10, Henrique Dallazuanna wrote:
> Try this:
>
> f <- t
Thank you Don for the code,
but I get the following error massage:
> by(AlexETF,AlexETF$Industry,function(a) {filename = paste("C:/ab/",gsub("
> ","",a$Industry[1]),".txt",sep="")
+ print(filename)
+ write.table(a[,3,drop=FALSE],quote=FALSE,col.names=FALSE,row.names=FALSE)
+ }
Does this example help?
a <- matrix(letters[1:12], ncol=3)
a
[,1] [,2] [,3]
[1,] "a" "e" "i"
[2,] "b" "f" "j"
[3,] "c" "g" "k"
[4,] "d" "h" "l"
write.table(a[,3,drop=FALSE],quote=FALSE,col.names=FALSE,row.names=FALSE)
i
j
k
l
At 4:11 PM -0800 1/21/10, Peter Rote wrote:
T
Thank you Dieter and Rolf,
I have solved the slash Problem, but I still struggling with the output
files.
I have tried this
by(AlexETF,AlexETF$Industry,function(a) {filename = paste("C:/ab/",gsub("
","",a$Industry[1]),".txt",sep="")
print(filename)
write.table(a,file=filename,c
Peter Rote wrote:
>
>
> but i still have a problem to write to file. The problem is the slash in
> file names (Aerospace/Defense Products & Services ). If i want it to
> C:/ab/
> so "C:/ab/AdvertisingAgencies.txt" is ok but
> "C:/ab/Aerospace/Defense-MajorDiversified.txt" is not
>
>
As Rol
A name such as ``Aerospace/Defense etc.'' is certainly not a legal
file name under unix-alike systems, and I suspect it would not
be even under Windoze. Even if it is, you shouldn't use it!
Change the name to ``Aerospace-Defense Products & Services''
or something like that, for goodness sake.
by the way how do i change the output
"1016" "Advertising Agencies" "CMM"
"1803" "Advertising Agencies" "FMCN"
"2427" "Advertising Agencies" "IPG"
"3093" "Advertising Agencies" "MWW"
"3372" "Advertising Agencies" "OMC"
"4809" "Advertising Agencies" "VCLK"
"4832" "Advertising Agencies" "VISN"
"500
Thank you Dieter,
but i still have a problem to write to file. The problem is the slash in
file names (Aerospace/Defense Products & Services ). If i want it to C:/ab/
so "C:/ab/AdvertisingAgencies.txt" is ok but
"C:/ab/Aerospace/Defense-MajorDiversified.txt" is not
> head(AlexETF)
Peter Rote wrote:
>
> I would like to to group the Ticker by Industry and create file names from
> the
> Industry Factor and export to a txt file.
>
> I have tried the folowing
>
> ind=finvizAllexETF$Industry
>
> ind is then "Aluminum" "Business Services" "Regional Airlines"
>
>
Dear All,
I would like to to group the Ticker by Industry and create file names from
the
Industry Factor and export to a txt file.
I have tried the folowing
ind=finvizAllexETF$Industry
ind is then "Aluminum" "Business Services" "Regional Airlines"
ind2=gsub(" " ,"",ind)
ind3
[1]
Try this:
f <- tempfile()
download.file("http://nseindia.com/content/historical/EQUITIES/2010/JAN/cm15JAN2010bhav.csv.zip";,
f)
myData <- read.csv(unzip(f))
On Tue, Jan 19, 2010 at 2:56 PM, Velappan Periasamy wrote:
> How to unzip this file?.
>
>> mydata <-
>> unzip("http://nseindia.com/content
How to unzip this file?.
> mydata <-
> unzip("http://nseindia.com/content/historical/EQUITIES/2010/JAN/cm15JAN2010bhav.csv.zip";)
Warning message:
In
unzip("http://nseindia.com/content/historical/EQUITIES/2010/JAN/cm15JAN2010bhav.csv.zip";)
:
error 1 in extracting from zip file
>
If you need an example of this look at the yacasInstall function in this file:
http://ryacas.googlecode.com/svn/trunk/R/yacasInstall.R
from the Ryacas package. It downloads, unzips and installs yacas and
associated files for Windows users.
On Tue, Jan 19, 2010 at 3:10 AM, Dieter Menne
wrote:
Dieter Menne wrote:
>
> Velappan Periasamy wrote:
>> I am not able to import zipped files from the following link.
>> How to get thw same in to R?.
>> mydata <-
>> read.csv("http://nseindia.com/content/historical/EQUITIES/2010/JAN/cm15JAN2010bhav.csv.zip";)
>>
>
> As Brian Ripley noted in
>
>
Velappan Periasamy wrote:
>
> I am not able to import zipped files from the following link.
> How to get thw same in to R?.
> mydata <-
> read.csv("http://nseindia.com/content/historical/EQUITIES/2010/JAN/cm15JAN2010bhav.csv.zip";)
>
As Brian Ripley noted in
http://markmail.org/message/7dsau
I am not able to import zipped files from the following link.
How to get thw same in to R?.
mydata <-
read.csv("http://nseindia.com/content/historical/EQUITIES/2010/JAN/cm15JAN2010bhav.csv.zip";)
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Thank you all. The 'list' works well, except makes a really big 'list', since
my data is 'huge'. But solves the problem anyway. Appreciate a lot!
Barry Rowlingson wrote:
>
> On Sun, Jan 10, 2010 at 7:16 AM, Berend Hasselman wrote:
>>
>>
>>
>> Zoho wrote:
>>>
>>> I've been stuck with this prob
?get
for (i in 1:20) {
df_i <- get(paste('df_', i, sep=''))
length(which(df_i[,7]==1))
##
}
On Sat, Jan 9, 2010 at 7:57 PM, Zoho wrote:
>
> I've been stuck with this problem for a whole afternoon. It's silly but
> totally pissed me off. I have a set of data frames with names in a
> sequ
On Sun, Jan 10, 2010 at 7:16 AM, Berend Hasselman wrote:
>
>
>
> Zoho wrote:
>>
>> I've been stuck with this problem for a whole afternoon. It's silly but
>> totally pissed me off. I have a set of data frames with names in a
>> sequence: df_1, df_2, df_3, ..., df_20. Now I want to access each data
I've been stuck with this problem for a whole afternoon. It's silly but
totally pissed me off. I have a set of data frames with names in a sequence:
df_1, df_2, df_3, ..., df_20. Now I want to access each data frame (read or
write) in a for loop, in a way something like this:
for (i in 1:20) {
Zoho wrote:
>
> I've been stuck with this problem for a whole afternoon. It's silly but
> totally pissed me off. I have a set of data frames with names in a
> sequence: df_1, df_2, df_3, ..., df_20. Now I want to access each data
> frame (read or write) in a for loop, in a way something like th
On 06.01.2010 03:14, Noli Sicad wrote:
Hi John
Thanks for your reply. I think I was posting properly the problem.
Here are the error, R script and console errors below.
Thanks. Noli
~~~
The error:
~~
Error in data.frame(CROP_ID = x[1, 1], CROPTYPE = x[1, 2], name =
colnames(x)[4:5],
Hi John
Thanks for your reply. I think I was posting properly the problem.
Here are the error, R script and console errors below.
Thanks. Noli
~~~
The error:
~~
Error in data.frame(CROP_ID = x[1, 1], CROPTYPE = x[1, 2], name =
colnames(x)[4:5], :
subscript out of bounds
~~~
I
Thank you for your kind help. Your R script works well.
Lisa
Dieter Menne wrote:
>
>
>
> Lisa wrote:
>>
>> I have a dataset that looks like this:
>>
>>> data
>> idcode1code2
>> 1 114
>> 2 123
>> 3 24
Lisa wrote:
>
> I have a dataset that looks like this:
>
>> data
> idcode1code2
> 1 114
> 2 123
> 3 244
> ..
>
> I want to change some numbers in the columns of “code1” and “code2” based
> on “indx”
Well, if nothing else, you have missing comma. :)
x01=y[,1]), x01=y[,1], x02=y[,2], x03=y[,3]
--
>
> fn <- function(x) {
> y <- t(x[,2])
> data.frame( Croptype=x[1,1], Period =x[1,2],
> name=colnames(x)[2],
> x01=y[,1])x01=y[,1], x02=y[,2], x03=y[,3] }
> <---Problem
> h
Dear all,
I have a question and need your help.
I have a dataset that looks like this:
> data
idcode1code2
1 114
2 123
3 244
4 315
5 324
6 4
Hi,
forests <- read.csv("C:\\Down2\\R_forestmgt\\forest_cut-Age.csv")
m <- forests
fn <- function(x) {
y <- t(x[,2])
data.frame( Croptype=x[1,1], Period =x[1,2], name=colnames(x)[2],
x01=y[,1])x01=y[,1], x02=y[,2], x03=y[,3] } <---Problem
here
m <- do.call( "rbind", lapply(split
Hi All,
is there a way to download data from metastock to R-software. most of my data
is in date,OHLC format downloaded from reuters to metastock software in my
local pc.
many thanks for the help.,
krishna
[[alternative HTML version deleted]]
Hi Jose,
Here is a suggestion using tapply():
R> x <- read.table(textConnection("Pepe 2
+ Pepe 3
+ Pepe 4
+ Jose 2
+ Jose 5
+ Manuel 4
+ Manuel 2"), header = FALSE)
R> closeAllConnections()
R> x
V1 V2
1 Pepe 2
2 Pepe 3
3 Pepe 4
4 Jose 2
5 Jose 5
6 Manuel 4
7 Manuel 2
R>
R>
On Dec 11, 2009, at 4:38 PM, Jose Narillos de Santos wrote:
Hi all,
Imagine I have a matrix and the first colum is a list that repeats
the same
names, I want to sum the second column on each unique name on first
column.
Imagine this:
Pepe 2
Pepe 3
Pepe 4
Jose 2
Jose 5
Manuel 4
Manuel 2
Hi all,
Imagine I have a matrix and the first colum is a list that repeats the same
names, I want to sum the second column on each unique name on first column.
Imagine this:
Pepe 2
Pepe 3
Pepe 4
Jose 2
Jose 5
Manuel 4
Manuel 2
I want to make a new matrix that calculates and recognizes that ther
try this:
myDat <- read.table(textConnection("group id
1 101
1 201
1 301
2 401
2 501
2 601
3 701
3 801
3 901"),header=TRUE)
closeAllConnections()
corr_mat <-as.matrix(read.table(textConnection("1 1 .5 0 0 0 0
0 0 0
2 .5 1 0 0 0 0 0 0 0
3 00 1.0 0 0 0 0 0
Hi List,
Here is some example data.
myDat <- read.table(textConnection("group id
1 101
1 201
1 301
2 401
2 501
2 601
3 701
3 801
3 901"),header=TRUE)
closeAllConnections()
corr_mat <-read.table(textConnection("1 1 .5 0 0 0 0 0 0 0
2 .5 1 0 0 0 0 0 0 0
3 00 1.0
This is probably far more discussion than the question warranted, but...
On Thu, Dec 3, 2009 at 11:14 PM, David Winsemius wrote:
>
> On Dec 3, 2009, at 10:52 PM, Gray Calhoun wrote:
>
>> The data import/export manual can elaborate on a lot of these; this is
>> all straightforward, although many p
On Thu, Dec 3, 2009 at 9:52 PM, John Filben wrote:
> Can R support data manipulation programming that is available in the SAS
> datastep? Specifically, can R support the following:
> - Read multiple dataset one record at a time and compare values from
> each; then base on if-then logic
On Dec 3, 2009, at 10:52 PM, Gray Calhoun wrote:
The data import/export manual can elaborate on a lot of these; this is
all straightforward, although many people would prefer to use a
relational database for some of the things you mentioned.
See Wickham's pithy response to this.
I'm not
awa
The data import/export manual can elaborate on a lot of these; this is
all straightforward, although many people would prefer to use a
relational database for some of the things you mentioned. I'm not
aware of a "goto" command in R, though (although I could be wrong).
--Gray
On Thu, Dec 3, 2009 a
Please refrain from posting HTML. The results can be incomprehensible:
On 2009.12.03 13:52:09, John Filben wrote:
> Can R support data manipulation programming that is available in the SAS
> datastep??? Specifically, can R support the following:
> -?? Read multiple dataset one rec
On Thu, Dec 3, 2009 at 3:52 PM, John Filben wrote:
> Can R support data manipulation programming that is available in the SAS
> datastep? Specifically, can R support the following:
> - Read multiple dataset one record at a time and compare values from
> each; then base on if-then logic
Can R support data manipulation programming that is available in the SAS
datastep? Specifically, can R support the following:
-Â Â Â Â Â Â Â Â Â Read multiple dataset one record at a time and compare
values from each; then base on if-then logic write to multiple output files
-Â Â Â Â Â Â Â Â Â
Announcing a new version of Deducer:
Deducer 0.2-1 is an intuitive, cross-platform graphical data analysis
system. It uses menus and dialogs to guide the user efficiently through
the data manipulation and analysis process, and has an excel like
spreadsheet for easy data frame visualization and edi
David,
Great! 'split' is something I didn't even look at. Owe you one.
Many thanks,
Dave
On 12/2/09 7:29 PM, "David Winsemius" wrote:
On Dec 2, 2009, at 7:02 PM, Robinson, David G wrote:
> My apologies for this question but I'm stuck and I'm sure that there
> must be
> an easy answer out th
Try this where [0-9]+ matches one or more digits and $ matches the end of
string. See http://gsubfn.googlecode.com for more.
library(gsubfn)
x <- c("v2FfaPre15", "v2FfaPre10", "v2FfaPre5", "v2Ffa2", "v2Ffa3",
"v2Ffa4")
strapply(x, "[0-9]+$", c, simplify = TRUE)
# or if you want a numeric resul
Try this:
gsub(".*[^0-9]", "", header)
On Thu, Dec 3, 2009 at 12:00 PM, oscar linares wrote:
> Dear Wiza[R]ds,
>
> I have a data.frame header that looks like this:
>
> v2FfaPre15 v2FfaPre10 v2FfaPre5 v2Ffa2 v2Ffa3 v2Ffa4
>
> I need it to look like this,
>
> 15 10 5 2
try this:
> x <- c('v2FfaPre15','v2FfaPre10','v2FfaPre5','v2Ffa2',
> 'v2Ffa3','v2Ffa4')
> sub("^.*?([0-9]+)$", "\\1", x, perl=TRUE)
[1] "15" "10" "5" "2" "3" "4"
>
On Thu, Dec 3, 2009 at 9:00 AM, oscar linares wrote:
> Dear Wiza[R]ds,
>
> I have a data.frame header that l
Dear Wiza[R]ds,
I have a data.frame header that looks like this:
v2FfaPre15v2FfaPre10v2FfaPre5v2Ffa2v2Ffa3v2Ffa4
I need it to look like this,
1510523 4
i.e., with v2FfaPre and v2Ffa stripped off
Any suggestions,
Thanks in advance!
--
Oscar
Oscar A.
On Dec 2, 2009, at 7:02 PM, Robinson, David G wrote:
My apologies for this question but I¹m stuck and I¹m sure that there
must be
an easy answer out there (and hope that someone will have mercy and
point me
in the right direction).
I have a data file that looks like:
1 77 3
1 8 1
1 7 2
1 1
My apologies for this question but I¹m stuck and I¹m sure that there must be
an easy answer out there (and hope that someone will have mercy and point me
in the right direction).
I have a data file that looks like:
1 77 3
1 8 1
1 7 2
1 1 5
1 42 7
1 0 2
1 23 1
2 83 9
2 8 2
2 6 5
2 23 3
3 11 3
3 8 1
uss how you would combine other demographic information, such as
birthdates, etc to further explore probabilities of a correct match.
Harold
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of David Winsemius
Sent: Wednesday, Nove
On Nov 18, 2009, at 1:21 PM, Dagan A WRIGHT wrote:
I am somewhat new to R although using and liking already. I am
curious if there are any probabilistic packages similar in function
to others such and Link King (http://www.the-link-king.com/). I am
looking for functions in SSN, First/Las
I am somewhat new to R although using and liking already. I am curious if
there are any probabilistic packages similar in function to others such and
Link King (http://www.the-link-king.com/). I am looking for functions in SSN,
First/Last name, date of birth, and a couple other indicators for
I forgot to mention that it's running Windows Server 2003 x64 OS version
On Mon, Nov 16, 2009 at 11:22 AM, helpme wrote:
> I'm stumped. When trying to connect to Oracle using the RODBC package I get
> an error:
> *[RODBC] Data source name not found and no default driver specified.
> ODBC connect
I'm stumped. When trying to connect to Oracle using the RODBC package I get
an error:
*[RODBC] Data source name not found and no default driver specified.
ODBC connect failed.*
I've read over all the posts and documentation manuals.
The system is Windows Server 2003 with R 2.81. and the latest dow
On Nov 12, 2009, at 10:57 PM, Douglas M. Hultstrand wrote:
Hello,
I am trying to create data frame subsets based on binned temperature
data. I have code working to create the bins (d.1 and d.2), but it
takes two steps, I was wondering if I could merge into one step.
See Below
d
n y
Hi Douglas,
Here is a suggestion:
subset(d, t >= 1 & t < 2)
See ?subset for more information.
HTH,
Jorge
On Thu, Nov 12, 2009 at 10:57 PM, Douglas M. Hultstrand <> wrote:
> Hello,
>
> I am trying to create data frame subsets based on binned temperature data.
> I have code working to create
Hello,
I am trying to create data frame subsets based on binned temperature
data. I have code working to create the bins (d.1 and d.2), but it
takes two steps, I was wondering if I could merge into one step. See Below
d
n year mo da hr t td tw rh kPa
1 1 1945 3 1 0 1.1 0.0 0
>> (x.n <- cast(x.m, id ~ var, function(.dat){
> + if (length(.dat) == 0) return(0) # test for no data; return
> zero if that is the case
> + mean(.dat)
> + }))
Or fill = 0.
Hadley
--
http://had.co.nz/
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h
That's what I want. Many thanks for your help.
Legen
jholtman wrote:
>
> Try this:
>
>> x <- read.table(textConnection("idcode1code2 p
> + 148 0.1
> + 157 0.9
> + 218 0.4
> + 262
Your script works very well. Thank you very much.
Legen
Henrique Dallazuanna wrote:
>
> Try this also:
>
> xtabs(rep(p, 2) ~ rep(id, 2) + sprintf("var%d", c(code1, code2)), data =
> x)
>
> On Wed, Nov 11, 2009 at 2:10 AM, legen wrote:
>>
>> Thank you for your kind help. Your script works v
Try this:
> x <- read.table(textConnection("idcode1code2 p
+ 148 0.1
+ 157 0.9
+ 218 0.4
+ 262 0.2
+ 243 0.6
+ 356 0.7
+
Try this also:
xtabs(rep(p, 2) ~ rep(id, 2) + sprintf("var%d", c(code1, code2)), data = x)
On Wed, Nov 11, 2009 at 2:10 AM, legen wrote:
>
> Thank you for your kind help. Your script works very well. Would you please
> show me how to change NaN to zero and column variables 1, 2, ..., 8 to var1,
Thank you for your kind help. Your script works very well. Would you please
show me how to change NaN to zero and column variables 1, 2, ..., 8 to var1,
var2, ..., var8? Thanks again.
Legen
jholtman wrote:
>
> Is this what you want:
>
>> x <- read.table(textConnection("idcode1code2
Is this what you want:
> x <- read.table(textConnection("idcode1code2 p
+ 148 0.1
+ 157 0.9
+ 218 0.4
+ 262 0.2
+ 243 0.6
+ 356
Dear all,
I have a dataset as below:
idcode1code2 p
148 0.1
157 0.9
218 0.4
262 0.2
243 0.6
356 0.7
37
Thanks a lot. Have a nice day!
Best,
Pat
On Wed, Oct 28, 2009 at 10:29 AM, Max Kuhn wrote:
> There are a few. I'm partial to the function in the caret package:
> createDataPartition. Also, there are functions there for
> pre-processing on training sets and applying it to new data sets.
>
> For
There are a few. I'm partial to the function in the caret package:
createDataPartition. Also, there are functions there for
pre-processing on training sets and applying it to new data sets.
For a somewhat dated summary of the packages, see:
http://www.jstatsoft.org/v28/i05
also:
http://c
Hi, Users,
I am a new user. I am trying to partition data into training and test. Is
there any R package or function that can partition dataset? Also, is there
any package do crossvalidation? Any help will be appreciated.
Best,
Pat
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___
Thank you ,Petr
It is a good answer,clearly.
thanks!
Petr Pikal wrote:
>
> Hi
>
>> data(gasoline)
>> str(gasoline)
> 'data.frame': 60 obs. of 2 variables:
> $ octane: num 85.3 85.2 88.5 83.4 87.9 ...
> $ NIR : AsIs [1:60, 1:401] -0.050193 -0.044227 -0.046867 -0.046705
> -0.050859 ...
Hi
> data(gasoline)
> str(gasoline)
'data.frame': 60 obs. of 2 variables:
$ octane: num 85.3 85.2 88.5 83.4 87.9 ...
$ NIR : AsIs [1:60, 1:401] -0.050193 -0.044227 -0.046867 -0.046705
-0.050859 ...
..- attr(*, "dimnames")=List of 2
.. ..$ : chr "1" "2" "3" "4" ...
.. ..$ : chr "90
Noah Silverman wrote:
Hi,
I have a process using svm from the e1071 library.
It's called a *package* which is probably installed in a *library* of
packages.
it works.
I want to try using the KSVM library instead. The same data used wiht
e1071 gives me an error with KSVM.
I guess y
thank you Don MacQueen , I will try it.
Don MacQueen wrote:
>
> At 4:57 AM -0700 10/23/09, bbslover wrote:
>>Steve Lianoglou-6 wrote:
>>>
>>> Hi,
>>>
>>> On Oct 22, 2009, at 2:35 PM, bbslover wrote:
>>>
Usage
data(gasoline)
Format
A data frame with 60 observations on t
I have try it, past can add to wanted letter, but can not past the colume
names. May be I should learn it hard.
Don MacQueen wrote:
>
> At 4:57 AM -0700 10/23/09, bbslover wrote:
>>Steve Lianoglou-6 wrote:
>>>
>>> Hi,
>>>
>>> On Oct 22, 2009, at 2:35 PM, bbslover wrote:
>>>
Usage
d
I have read that one ,I want to this method to be used to my data.but I donot
know how to put my data into R.
James W. MacDonald wrote:
>
>
>
> bbslover wrote:
>>
>>
>> Steve Lianoglou-6 wrote:
>>> Hi,
>>>
>>> On Oct 22, 2009, at 2:35 PM, bbslover wrote:
>>>
Usage
data(gasoline)
>
At 4:57 AM -0700 10/23/09, bbslover wrote:
Steve Lianoglou-6 wrote:
Hi,
On Oct 22, 2009, at 2:35 PM, bbslover wrote:
Usage
data(gasoline)
Format
A data frame with 60 observations on the following 2 variables.
octane
a numeric vector. The octane number.
NIR
a matrix with 401 columns
Hi,
I have a process using svm from the e1071 library. it works.
I want to try using the KSVM library instead. The same data used wiht
e1071 gives me an error with KSVM.
My data is a data.frame.
sample code:
svm_formula <- formula(y ~ a + B + C)
svm_model <- ksvm(formula, data=train_data
bbslover wrote:
Steve Lianoglou-6 wrote:
Hi,
On Oct 22, 2009, at 2:35 PM, bbslover wrote:
Usage
data(gasoline)
Format
A data frame with 60 observations on the following 2 variables.
octane
a numeric vector. The octane number.
NIR
a matrix with 401 columns. The NIR spectrum
and I see the
Steve Lianoglou-6 wrote:
>
> Hi,
>
> On Oct 22, 2009, at 2:35 PM, bbslover wrote:
>
>> Usage
>> data(gasoline)
>> Format
>> A data frame with 60 observations on the following 2 variables.
>> octane
>> a numeric vector. The octane number.
>> NIR
>> a matrix with 401 columns. The NIR spectrum
>
On 10/23/2009 10:07 PM, William Simpson wrote:
Thanks Jim. BTW the times in x and y are in ascending order (time of
occurrence).
If I do it this way, how do I actually read the data in and store in
the file? Toy code, please.
Hi Bill,
This seems a bit like some heartbeat data that I had to de
On 10/23/2009 10:07 PM, William Simpson wrote:
Thanks Jim. BTW the times in x and y are in ascending order (time of
occurrence).
If I do it this way, how do I actually read the data in and store in
the file? Toy code, please.
Hi Bill,
This seems a bit like some heartbeat data that I had to
OK thanks, I look at sleep and get it
Bill
On Fri, Oct 23, 2009 at 12:21 PM, Peter Dalgaard
wrote:
> William Simpson wrote:
>>> As I understand it, they don't come in pairs anyway.
>> Correct.
>>
>>> For the same reason
>>> a data frame is just the wrong kind of data structure. If you don't want
William Simpson wrote:
>> As I understand it, they don't come in pairs anyway.
> Correct.
>
>> For the same reason
>> a data frame is just the wrong kind of data structure. If you don't want
>> separate data files, you can use one file with two columns where the
>> second column is (say) 1 for the
Thanks Jim. BTW the times in x and y are in ascending order (time of
occurrence).
If I do it this way, how do I actually read the data in and store in
the file? Toy code, please.
Bill
>
> Hi Bill,
>
> xy<-list(x=1:10,y=1:100)
>
> Note that this cheerfully ignores how you are going to figure out
> As I understand it, they don't come in pairs anyway.
Correct.
> For the same reason
> a data frame is just the wrong kind of data structure. If you don't want
> separate data files, you can use one file with two columns where the
> second column is (say) 1 for the x and 2 for the y.
Could you ex
The way you do it is to compute the cross-intensity function (you can
google this; a key name is David Brillinger). The general problem is
that of system identification for point processes.
Bill
On Fri, Oct 23, 2009 at 10:31 AM, Jim Lemon wrote:
> On 10/23/2009 07:58 PM, William Simpson wrote:
>
Jim Lemon wrote:
> On 10/23/2009 07:58 PM, William Simpson wrote:
>> I am running an expt that presents a point process input x and
>> measures a point process output y. The times of each event are
>> recorded. The lengths of the data records of x and y are necessarily
>> different, and can be diff
On 10/23/2009 07:58 PM, William Simpson wrote:
I am running an expt that presents a point process input x and
measures a point process output y. The times of each event are
recorded. The lengths of the data records of x and y are necessarily
different, and can be different by a factor of 10. I wo
I am running an expt that presents a point process input x and
measures a point process output y. The times of each event are
recorded. The lengths of the data records of x and y are necessarily
different, and can be different by a factor of 10. I would like to
save these data after each experiment
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