On Wed, Sep 26, 2012 at 3:36 PM, maxbre wrote:
> sorry for my slow reply, this is what I worked out so far…
>
> my reproducible example and the code
>
> test<-structure(list(site = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 2L,
> 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 3L,
> 3L, 3L, 3
sorry for my slow reply, this is what I worked out so far…
my reproducible example and the code
test<-structure(list(site = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 2L,
2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 3L,
3L, 3L, 3L, 3L, 3L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L,
4L
deepayan, is that what you mean?
but still the problem persists: nor correct neither contiguous labelling!
I must probably reconsider everything from scratch: I'm bit confused now...
test$samp.time.new <- with(test, reorder(samp.time:site, as.numeric(site)))
s<-strsplit(levels(test$samp.time.new
thank you all for your helpful replies
to bert
the problem with relation ="same" is the plotting along y axis of all
categories ("samp.time") for all groups ("sites"); instead, I need to
plot along y axis just the categories for each group effectively having
a corresponding observation
to dann
On Thu, Sep 20, 2012 at 7:48 PM, maxbre wrote:
> my reproducible example
>
> test<-structure(list(site = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 2L,
> 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 3L,
> 3L, 3L, 3L, 3L, 3L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L,
> 4L, 4L, 4L, 4L, 4L,
Is result3 what you are looking for?
test<-structure(list(site = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 2L,
2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 3L,
3L, 3L, 3L, 3L, 3L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L,
4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 5L), .Label = c
I don't entirely understand what you want as an alternative. What is
wrong with relation ="same", the default?
In any case, it sounds like you'll need to write your own panel
function. If you look at panel.dotplot(), you'll see it's fairly
straightforward, so modification should not be difficult.
my reproducible example
test<-structure(list(site = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 2L,
2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 3L,
3L, 3L, 3L, 3L, 3L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L,
4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 5L), .Label = c("A",
"B",
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