number.of.years.using.R * runif(1)
[1] 1.064863
I waited this many hours before responding:)
First, let me say thank you very much to the R team for ...the software
...the help-list ...other intangibles. I am a relatively new R user and I
am struggling in my own way to learn R. I follow the
This may not have things in the order you want but you can see if it gets
close to what you want:
x - matrix(1:16,ncol=4)
x
[,1] [,2] [,3] [,4]
[1,]159 13
[2,]26 10 14
[3,]37 11 15
[4,]48 12 16
y - x[row(x) col(x)]
y
[1] 5 9 10 13 14
I believe in the earlier discussion it was Spencer Graves that pointed out
that there is earlier work by DuMouchel using design information but not
weights as predictors.
The reference for the use of design weights as predictors is:
Start insert from earlier email
9. Pfeffermann, D. , Skinner,
I don't know how careful about coercing type you need to be.
Something like TRUE %in% outer(v,v,|) may work for you but simpler
functions that do arithmetic and coerce the answer back to logical [e.g.,
as.logical(max(v))] might suffice.
xt - c(T,T,T)
xf - c(T,F,F)
outer(xt, xf, |)
[,1]
It has to do with the topology of the web - if you are web-wise closer to
the responder than the original sender you can receive the answer before the
question - even if both answer and question go only to the list.
I learned this suscribed to SAS-L when I was at UF - I was downstream from
Bob
I may be confused, but I think what you described will produce greater than
472 million permutations. I think your second permutation 1 2 4 | 3 5 6 |
7 8 9 | 10 11 12 YES-2nd permutation shows that you want more than
just a permutation of entire blocks.
There are a total of 12! (12
Han-Lin
I don't think I have seen a reply so I will suggest that maybe you could try
a different approach than what you are thinking about doing. I believe the
current best practice is to use the weights as a covariate in a regression
model - and bytheway - the weights are the inverse of the
I would like to run a linear *mixed effects* model and also to use
(sample) weighting ...
I've been trying to do this for 2 decades :)
See
9. Pfeffermann, D. , Skinner, C. J. , Holmes, D. J. , Goldstein, H. , and
Rasbash, J. (1998), ``Weighting for unequal selection probabilities in
multilevel
Construct a new weight within the stratum as the sample weight
multiplied by the frequency
The correct formula for the new weights can be found in Chapter 6 of Shao
and Tu (1996) The Jackknife and the Bootstrap, Springer
Also in:
Keith Rust Jon Rao have an overview article in Statistical
Does anyone know why they're called random deviates, as opposed to random
numbers?
Others will probably give you some technical reason about random numbers can
be considered as random deviates from a mean (I think at least the 1875
Galton paper at http://www.mugu.com/galton/ uses similar
First: Thanks to everyone who develops R, maintains r-help, and participates
in the list :)
This is a silly follow up question.
From Andy Liaw:
dat - data.frame(y=rnorm(10), x1=rnorm(10), x2=rnorm(10))
(Silly question - if the answer is on the lm or formula help page I didn't
get it:)
Why
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