How I would improve this:
compile the regular expression. This is more efficient.
self.digit_extractor = re.compile('(\d+)')
then, use the findall method:
self.allNumbers = self.digit_extractor.findall(self.aString)
which will even work with multiline strings, but doesn't convert to integers.
Meftah Tayeb wrote:
hi my friend,
i have active python installed and the python-Win is Ready
but i have a Very Small problem:
i am blind, and i am using a Screen reader
this screen reader use the Microsoft Active Accessibiliti (MSAA) to find
informations about actual object in the screen
Allen Fowler wrote:
Hello,
I need to call an external command line .exe utility from my Python script.
What is the best way to capture the output (if any) and (optionally) direct
it to my normal standard output?
subprocess.Popen().communicate() will do it:
In [1]: import subprocess
In
simplest way to run external commands !
import os
cmd=/usr/bin/ssh 10.0.0.20 uptime
os.popen(cmd)
my cmd is just an example, use any cmd you want its output will be
displayed to you.
hope this helps
On Thu, Mar 13, 2008 at 12:05 PM, Kent Johnson [EMAIL PROTECTED] wrote:
Allen Fowler
Am Mittwoch, den 12.03.2008, 09:39 +0100 schrieb Meftah Tayeb:
hi my friend,
i have active python installed and the python-Win is Ready
but i have a Very Small problem:
i am blind, and i am using a Screen reader
this screen reader use the Microsoft Active Accessibiliti (MSAA) to find
Thank you for all the suggestions regarding my struggle to understand
classes, I will follow up on all the links provided and continue to search.
On Wed, Mar 12, 2008 at 5:12 PM, Ole Henning Jensen [EMAIL PROTECTED]
wrote:
Norm All wrote:
I am learning python and so far have done pretty
Hi, I'm in a Python class and we were given the assignment to create our own
graphic and my idea was to have a program that asks the user to click six
points and then create a circle using the six points they clicked. Once they've
done that I want eyes and a mouth to appear in the circle. I was
It appears to me that the following line would not work:
Circle = Oval(points)
The variable points is a list of six points, and I don't know how one
would define a circle or oval with 6 points. At the top part of your
program, an oval is defined using two points, which makes sense.
Maybe
Hi Norm. Jerol created a 3-part video series on Python Objects, he uses
IPython to talk about how and why they work:
http://showmedo.com/videos/series?name=IntroductionToPythonObjectsUsingIPython_JerolH
If you find his videos useful do please leave him a comment - authors love to
know that
Thank you for the help. :)
- Original Message
simplest way to run external commands !
import os
cmd=/usr/bin/ssh 10.0.0.20 uptime
os.popen(cmd)
my cmd is just an example, use any cmd you want its output will be displayed
to you.
hope this helps
[SNIP]
Allen Fowler wrote:
Thank you for the help. :)
- Original Message
simplest way to run external commands !
import os
cmd=/usr/bin/ssh 10.0.0.20 http://10.0.0.20 uptime
os.popen(cmd)
This is deprecated in python 2.5+. Use subrpocess instead of os.popen
to make sure your code
I am in an early lesson in A Byte of Python. Instead of writing a program
to find the area of a rectangle I thought it would be useful to write a
program to determine the length of the diagonal of a golden rectangle,
which would of course equal the sq root of the sum of the squares of
the width
Robert Childers wrote:
I am in an early lesson in A Byte of Python. Instead of writing a
program to find the area of a rectangle I thought it would be useful
to write a program to determine the length of the diagonal of a
golden rectangle, which would of course equal the sq root of the sum
On 14/03/2008, Robert Childers [EMAIL PROTECTED] wrote:
I am in an early lesson in A Byte of Python. Instead of writing a program
to find the area of a rectangle I thought it would be useful to write a
program to determine the length of the diagonal of a golden rectangle,
which would of
assert 4**0.5 == 2
More generally: nth root of x: x ** (1.0/n)
Or even more generally, take the 3rd root of the square of x:
x ** (2.0/3.0)
And when we are already extending the scope of the mailing list to math
basics:
1.0/(x**2) == x**-2
(negating the power gives the inverse.)
Andreas
On 14/03/2008, Scott Kerr [EMAIL PROTECTED] wrote:
Hello,
I am also new to python and programming. Since two have already posted that
you need to import math modules to do square roots, I am curious.
Why can you not use something like:
hypotenuse = hyp_squared**1/2
or
hypotenuse =
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