Hi TS,
there's a number of ways you can achieve this,
one is: expectMsgAnyOf(...) and then another expectMsgAnyOff with one
message (the received one) less from the expected collection,
another one is fishForMessage() where you implement a partial function
which can fish for the message you want to get - it you could return true
for any of the 2 messages for example.
On Sat, May 23, 2015 at 1:49 AM, TS test.tester1...@gmail.com wrote:
Let's take this code..
public void testIt() throws IOException {
new JavaTestKit(system) {{
final Props props = Props.create(MyActor.class);
final ActorRef subject = system.actorOf(props);
ByteString someBytes =
ByteString.fromArray(abcd.getBytes())
subject.tell(someBytes, getSelf());
//await response
Actor1 actor1 = expectMsgClass(Actor1.class);
Actor2 actor2 = expectMsgClass(Actor2.class);
}};
}
in myActor.java
actor1Ref and actor2Ref are ActorRef of Actor1 and Actor2 actors.
@Override
public void onReceive(Object message) {
if(message instanceof ByteString) {
// do something
getSender().tell(actor1Ref, getSelf());
// some more things
getSender().tell(actor2Ref, getSelf());
}
...
}
The order
Actor1 actor1 = expectMsgClass(Actor1.class);
Actor2 actor2 = expectMsgClass(Actor2.class);
seems to work and test passes. if actor1 message arrives late, the test
would fail I think.
Is there a way to say expectMsgClassesInNoParticularOrder(Actor1.class,
Actor2.class) ?
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Cheers,
Konrad 'ktoso' Malawski
Akka http://akka.io/ @ Typesafe http://typesafe.com/
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