Like he said earlier , its a compiler implementation.
On Aug 12, 12:55 am, aditi garg wrote:
> @sagar: why doesnt it take place sequentially like 4*5*6*7??
> why do the frst two increments take place like dat??
>
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> On Fri, Aug 12, 2011 at 1:19 AM, sagar pareek wrote:
> > told u before
> > in turbo c it increments all values of x
> > x=3;
> > c=7*7*7*7;
> > c=2401
>
> > On Fri, Aug 12, 2011 at 1:16 AM, Puneet Chawla
> > wrote:
>
> >> In turbo it is showing o/p 2401 again still confused...
>
> >> On Fri, Aug 12, 2011 at 1:14 AM, sagar pareek wrote:
>
> >>> ok if we have the scenario like u stated then it will be done in gcc as
> >>> :-
> >>> x=3;
> >>> c=5*5*(++x)*(++x);
> >>> c=25*6*(++x);
> >>> c=150*7;
> >>> c=1050;
>
> >>> On Fri, Aug 12, 2011 at 1:10 AM, aditi garg
> >>> wrote:
>
> @sagar: bt i dint understand how is it done
> what if we had something like (++x)*(++x)*(++x)*(++x) thn how wud it be
> evaluated in gcc?
> and since it is giving diff ans on diff compilers that is wat i mean by
> being undefined...
>
> On Fri, Aug 12, 2011 at 1:05 AM, Puneet Chawla <
> puneetchawla...@gmail.com> wrote:
>
> > @Aditi i thnk sagar parteek is right ...in turbo compiler it's
> > incrementing and finally max of all values and multiply the value means
> > pre
> > increment->evaluate->postincrement
>
> > On Fri, Aug 12, 2011 at 1:02 AM, sagar pareek
> > wrote:
>
> >> well its always depends on compiler to compiler
> >> in turbo c it will first increment all x
> >> results in
> >> c=6*6*6
> >> c=216
>
> >> but in gcc it will be as explained by me above
>
> >> On Fri, Aug 12, 2011 at 12:56 AM, aditi garg <
> >> aditi.garg.6...@gmail.com> wrote:
>
> >>> i think it wud be undefined...the value is getting modified more than
> >>> once and hence violating the sequence points rule...plz corect me if
> >>> im
> >>> wrong...
>
> >>> On Fri, Aug 12, 2011 at 12:48 AM, Puneet Chawla <
> >>> puneetchawla...@gmail.com> wrote:
>
> In turbo compiler it's o/p is 216 and in dev it's 150..
> Help me out..
>
> On Fri, Aug 12, 2011 at 12:45 AM, sagar pareek <
> sagarpar...@gmail.com> wrote:
>
> > after expansion of macro
> > it will be c=(++x)*(++x)*(++x);
>
> > now it be solved as
> > c= 5*5*(++x);
> > c=25*6;
> > c=150
>
> > On Fri, Aug 12, 2011 at 12:38 AM, Puneet Chawla <
> > puneetchawla...@gmail.com> wrote:
>
> >> #define cube(x) (x)*(x)*(x)
> >> main()
> >> {
> >> int x=3,c;
> >> c=cube(++x);
> >> printf("%d",c);
>
> >> return 0;
> >> }
>
> >> will anyone please tell me why o/p is 150.?
>
> >> --
> >> With regards
> >>
> >> Puneet Chawla
>
> >> --
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> > --
> > **Regards
> > SAGAR PAREEK
> > COMPUTER SCIENCE AND ENGINEERING
> > NIT ALLAHABAD
>
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> --
> With regards
>
> Puneet Chawla
> Computer Engineering Student
> NIT Kurukshetra
>
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>
> >>> --
> >>> Aditi Garg
> >>> Undergraduate Student
> >>> Electronics & Communication Divison
> >>> NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
> >>> Sector 3, Dwarka
> >>> New Delhi
>
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