[algogeeks]

2011-08-22 Thread code pool
main( )
{
char *q;
int j;
for (j=0; j3; j++) scanf(%s ,(q+j));
for (j=0; j3; j++) printf(%c ,*(q+j));
for (j=0; j3; j++) printf(%s ,(q+j));
}

Will the program give some o/p or error ???

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Re: [algogeeks] Re:

2011-08-22 Thread code pool
@ahishek i was thinking the same and even from one pdf i have read this but
it s showing error..confused..

On Tue, Aug 23, 2011 at 12:26 AM, sagar pareek sagarpar...@gmail.comwrote:

 it gives runtime error...
 coz u have to allocate memory to *q

 On Tue, Aug 23, 2011 at 12:02 AM, Abhishek 
 mailatabhishekgu...@gmail.comwrote:

 i think.. it will not produce error, but o/p 'may' be garbage values.
 since the memory locations adjacent to *q will be overwritten.

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 SAGAR PAREEK
 COMPUTER SCIENCE AND ENGINEERING
 NIT ALLAHABAD

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Re: [algogeeks] C output

2011-08-22 Thread code pool
10 as 3+22+8?3+2:2+8  510?5:10   ' + ' has more precedence then ?: as well
as  s o/p is 10..

correct me if i am wrong.

On Tue, Aug 23, 2011 at 12:50 AM, gmagog...@gmail.com
gmagog...@gmail.comwrote:

 output is 10 using gcc 4.5.2

 Yanan Cao



 On Mon, Aug 22, 2011 at 2:18 PM, sagar pareek sagarpar...@gmail.comwrote:

 Yeah its o/p is 10 :)


 On Tue, Aug 23, 2011 at 12:45 AM, Deepak Garg deepakgarg...@gmail.comwrote:

 its output is

 10


 On Tue, Aug 23, 2011 at 12:03 AM, rohit rajuljain...@gmail.com wrote:

 #includestdio.h

 #define max(a,b) (ab?a:b)


 int main()
 {

  int j=max(3+2,2+8);
  printf(%d,j);

return 0;
 }

why this program show output as 9 ? please help me

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 U.D.I.T

 Sent by Nokia OVI (c)

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 NIT ALLAHABAD

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[algogeeks]

2011-08-21 Thread code pool
Can anyone give me an example of big-endian compiler..???

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