Re: [algogeeks] Re: Queue problem

2012-07-24 Thread Priyanka Raju
The answer is single queue...

If we fill the queue fully and then dequeue and try again to enqueue... We
will get the error.. This is because when we dequeue,we move the front
pointer of the queue but not the rear pointer.. But enqueue is at rear
end.. The condition for enqueue also checks the rear pointer alone


Thank you

Priyanka

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Re: [algogeeks] Re: adobe written round que

2011-09-17 Thread priyanka raju
*

*
*#include fstream
#include iostream
using namespace std;
bool flag=false;
void check(int i)
{
int sum=0;
char n[5];
itoa(i,n,10);
for(int j=0;j5  n[j] != '\0';j++)
{
char p = n[j];
sum += atoi(p);
}
if(sum==3 || sum==6 || sum==9)
flag = true;
else if(sum9)
check(sum);
}

void main()
{
int i;
coutEnter the number : ;
cini;
check(i);
if(flag == true)
couti is divisible by '3'endl;
else
couti is not divisible by '3'endl;
}*

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Re: [algogeeks] Re: C Trick

2011-08-24 Thread priyanka raju
int a,b,max,min;
max=(a+b+abs(a-b))/2;
min=(a+b-abs(a-b))/2;


-- 
cheers
priyanka

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Re: [algogeeks] C Trick

2011-08-24 Thread priyanka raju
It will work...
a=3
b=-2
max=(a+b+abs(a-b))/2
so
max=(3-2+abs(3-(-2)))/2
   =(1+abs(5))/2
=(1+5)/2
=3
Same in case of min
-- 
cheers
priyanka

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Re: [algogeeks] Front/end operations

2011-08-01 Thread priyanka raju
wat about a double ended queue?




cheers
priyanka

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Re: [algogeeks] Re: FB intern

2011-07-31 Thread priyanka raju
tats bcos...
if it is a^21...
it will be (a^21/2)*(a^21/2)*(a^21mod2)
= (a^10)*(a^10)*(a^1)
correct me if i'm wrong
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cheers
priyanka

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[algogeeks]

2011-07-31 Thread priyanka raju
write a c program to print the following

   *
   *   *
*  *   *
*  *
*
-- 
cheers
priyanka

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