Navneet,
Your answer is correct, it would have been great if you could have explained
it for others.
I myself took good time to understand it...
Here is the answer
http://exploreriddles.blogspot.com/2011/06/interview-questions-puzzle.html
To maximize the chances of retrieving Red Ball, it is mandatory to reduce
the chances of retrieving Blue ball.
To reduce the chances.
1. It is possible to put all the black ball in one jar. It will reduce the
probability of retrieving black ball to half.
2. Now to reduce the probability of withdrawing Blue balls, need to maximize
number of red balls in the jar with blue balls. Maximum red balls we have is
50.
So based on above 2 points...
one jar can have 1 Red ball, and other will contain rest 99 balls.
So probability of choosing red ball is
(Probability of Choosing Jar 1)*(Probability of Choosing Red Ball From jar
1) + (Probability of Choosing Jar 2)*(Probability of Choosing Red Ball From
jar 2)
(1/2)*(1) + (1/2)(49/99)
Thanks Regards
Vishal Jain
MNo: +91-9540611889
Tweet @jainvis
Blog @ jainvish.blogspot.com
Success taste better when target achieved is bigger.
P *We have a responsibility to the environment.*
*Before printing this e-mail or any other document, let's ask
ourselves whether we need a hard copy.*
On Tue, Jun 14, 2011 at 7:47 PM, Navneet Gupta navneetn...@gmail.comwrote:
Put one red ball in one jar and rest 99 balls in other jar.
Probability in that case is 1/2*1 + 1/2*49//99
On Tue, Jun 14, 2011 at 7:45 PM, Vishal Jain jainv...@gmail.com wrote:
Folks,
This question was asked during a screening process of a product based
company. Please answer.
http://exploreriddles.blogspot.com/2011/06/interview-questions-puzzle.html
Thanks Regards
Vishal Jain
Success taste better when target achieved is bigger.
P *We have a responsibility to the environment.*
*Before printing this e-mail or any other document, let's ask ourselves
whether we need a hard copy.*
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