ya through down pointer we can print..coz each time i m making fwd as
NULL
On Dec 20, 2:33 pm, Rishi Agrawal rishi.b.agra...@gmail.com wrote:
See inline ..
On Sat, Dec 18, 2010 at 12:09 PM, siva viknesh sivavikne...@gmail.comwrote:
Given a linked list structure where every node represents a linked list
and contains two pointers of its type:
(i) pointer to next node in the main list.
(ii) pointer to a linked list where this node is head.
Write a C function to flatten the list into a single linked list.
Eg.
If the given linked list is
1 -- 5 -- 7 -- 10
| | |
2 6 8
| |
3 9
|
4
then convert it to
1 - 2 - 3 - 4 - 5 - 6 - 9 - 7 - 8 -10
My solution - not tested :
struct node
{
int data;
struct node *fwd; //pointer to next node in the main list.
struct node *down; //pointer to a linked list where this node is head.
}*head,*temp,*temp2;
temp=head;
while(temp-fwd!=NULL)
{
temp2=temp-fwd;
while(temp-down!=NULL)
{
temp=temp-down;
}
temp-down=temp2;
// how will the code access the flattened linked list by down or by fwd ? In
this case there in no particular pointer by which the code can access the
linked list. Try to write a function to print the flattened linked list.
temp-fwd=NULL;
temp=temp2;
}
plz notify me if anything...other solutions and optimizations are welcome
--
Regards,
$iva
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Regards,
Rishi Agrawal
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