1. Insert the node(order of insertion is irrelevant) in any order according
to the binary search tree properties.
2. Compare the j value of node with its parent recursively (bottom up) and
then perform rotations to restore the Heap property.
On Thu, Jun 9, 2011 at 12:38 AM, mukesh tiwari mukeshtiwari.ii...@gmail.com
wrote:
What you explained is the property of Treap data structure . You can
have a look at wiki [ http://en.wikipedia.org/wiki/Treap ] or you can
search google for treap.
On Jun 8, 8:15 pm, Akshata Sharma akshatasharm...@gmail.com wrote:
A rooted binary tree with keys in its nodes has the binary search tree
property (BST property) if, for every node, the keys in its left
subtree are smaller than its own key, and the keys in its right
subtree are larger than its own key. It has the heap property if, for
every node, the keys of its children are all smaller than its own key.
You are given a set of n binary tree nodes that each contain an
integer i and an integer j. No two i values are equal and no two j
values are equal. We must assemble the nodes into a single binary tree
where the i values obey the BST property and the j values obey the
heap property. If you pay attention only to the second key in each
node, the tree looks like a heap, and if you pay attention only to the
first key in each node, it looks like a binary search tree.Describe a
recursive algorithm for assembling such a tree
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