Re: [algogeeks] Re: C aps ques

2010-12-14 Thread RAHUL KUJUR 
for 2nd problem:
statement inside the do-while is executed once. Now for the condition
checking inside the while loop. The condition i++5 is evaluated which turns
out to be true. So the rest of the part ++ch='F' is not evaluated and hence
letter A is printed six times. Now when the condition i++5 fails, then
the condition ++ch='F' would be evaluated which prints BCDEF. This is a
property of the logical OR. If the first condition evaluates to true, then
rest of the condition is not evaluated as it would always turn out to be
true. However, if the first condition is false then only the second
condition is checked to get the final output.

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Re: [algogeeks] Re: C aps ques

2010-12-14 Thread RAHUL KUJUR 
correct me if I am wrong.

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Re: [algogeeks] Re: C aps ques

2010-12-14 Thread Saurabh Koar 
Exactly!!

On 12/14/10, RAHUL KUJUR kujurismonu2...@gmail.com wrote:
 correct me if I am wrong.

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[algogeeks] Re: C aps ques

2010-12-13 Thread siva viknesh 
what's the output for following program?

#includestdio.h
int main()
{
 int i = 0;
 char ch = 'A';
 do{ printf(%c, ch);

 }
while (i++ 5|| ++ch = 'F');
 return 0;

 }

(a) ABCDEF (b) AA BCDEF

(c) A will be displayed infinitely

(d) None of the above

On Mon, Dec 13, 2010 at 10:39 PM, siva viknesh sivavikne...@gmail.comwrote:

 #includestdio.h
 int main()
 {
  int x = 5;
  printf(%d %d, x++, ++x);

  return 0;

  }

 for this output is 6 7 ... how evaluation proceeds??

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 Regards,
 $iva




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$iva

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