Re: [algogeeks] Re: MS interview

2012-08-24 Thread GAURAV CHAWLA
@all .. i suggested him the hashing method... but was not convinced... he
might be expecting something else..   something like tries.. etc..

@ Karthikeyan Muthu... can u explain it in detail  with some ex ...

On Thu, Aug 23, 2012 at 11:28 PM, Karthikeyan Muthu 
keyankarthi1...@gmail.com wrote:

 i would suggest using tires data structure, basically a n-nary tree to
 store the dictionary. Entire algo is as follows:

 1) Create a trie http://en.wikipedia.org/wiki/Trie representing the
 dictionary.
 2) create a aux array for the search key. as count [ key[i] ] ++;
 3) Start a recursion from the root of the trie and pick a path if (count [
 path ]  0 )
   3rd step ensures that we traverse only those valid paths (ie valid
 words, this would reduce n! checking of all combinations).


 On Thu, Aug 23, 2012 at 8:23 PM, Ashish Goel ashg...@gmail.com wrote:

 yes, that is correct.
 O(mn) to form multimap and then O(m) to tell all anagram groups

 Best Regards
 Ashish Goel
 Think positive and find fuel in failure
 +919985813081
 +919966006652


 On Thu, Aug 23, 2012 at 5:11 PM, kings dns.bhar...@gmail.com wrote:

 Dear GC,

 The efficient data structure in my opinion is Hash Table.

 1. For a given word in the dictionary we need to form an anagram
 dictionary i.e. take a given word sort it which forms the key for the
 hashtable , then start forming the different anagrams for that word and
 insert it into the hash table with the corresponding key.

 2. Once the hash table is ready for the given word sort it find the key
 and print all the anagarams i.e. values associated to that key. we will get
 all the anagrams for a given word.

 Coming to time complexity...

 sorting of a word can be done in a O(nlogn).
 building of anagram will take O(n).
 hash complexity O(n) worst case.
 so total time complexity is O(nlogn) for whole execrcise.

 Thanks
 Bhargava


 On Wednesday, 22 August 2012 23:39:02 UTC+5:30, GC wrote:

 Ques..

 Given a m-word dictionary ... and a n-sized word... .. now suggest DS
 for dictionary such that you can find out all the anagrams of the given
 word present in dictionary...


 --
 Regards,
 G C



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GAURAV CHAWLA
+919992635751
+919654127192

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[algogeeks] Re: MS interview

2012-08-23 Thread kings
Dear GC,

The efficient data structure in my opinion is Hash Table.

1. For a given word in the dictionary we need to form an anagram dictionary 
i.e. take a given word sort it which forms the key for the hashtable , then 
start forming the different anagrams for that word and insert it into the 
hash table with the corresponding key.

2. Once the hash table is ready for the given word sort it find the key and 
print all the anagarams i.e. values associated to that key. we will get all 
the anagrams for a given word.

Coming to time complexity...

sorting of a word can be done in a O(nlogn).
building of anagram will take O(n).
hash complexity O(n) worst case.
so total time complexity is O(nlogn) for whole execrcise.

Thanks
Bhargava


On Wednesday, 22 August 2012 23:39:02 UTC+5:30, GC wrote:

 Ques.. 

 Given a m-word dictionary ... and a n-sized word... .. now suggest DS for 
 dictionary such that you can find out all the anagrams of the given word 
 present in dictionary...


 -- 
 Regards,
 G C





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Re: [algogeeks] Re: MS interview

2012-08-23 Thread Ashish Goel
yes, that is correct.
O(mn) to form multimap and then O(m) to tell all anagram groups
Best Regards
Ashish Goel
Think positive and find fuel in failure
+919985813081
+919966006652


On Thu, Aug 23, 2012 at 5:11 PM, kings dns.bhar...@gmail.com wrote:

 Dear GC,

 The efficient data structure in my opinion is Hash Table.

 1. For a given word in the dictionary we need to form an anagram
 dictionary i.e. take a given word sort it which forms the key for the
 hashtable , then start forming the different anagrams for that word and
 insert it into the hash table with the corresponding key.

 2. Once the hash table is ready for the given word sort it find the key
 and print all the anagarams i.e. values associated to that key. we will get
 all the anagrams for a given word.

 Coming to time complexity...

 sorting of a word can be done in a O(nlogn).
 building of anagram will take O(n).
 hash complexity O(n) worst case.
 so total time complexity is O(nlogn) for whole execrcise.

 Thanks
 Bhargava


 On Wednesday, 22 August 2012 23:39:02 UTC+5:30, GC wrote:

 Ques..

 Given a m-word dictionary ... and a n-sized word... .. now suggest DS for
 dictionary such that you can find out all the anagrams of the given word
 present in dictionary...


 --
 Regards,
 G C



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Re: [algogeeks] Re: MS interview

2012-08-23 Thread Karthikeyan Muthu
i would suggest using tires data structure, basically a n-nary tree to
store the dictionary. Entire algo is as follows:

1) Create a trie http://en.wikipedia.org/wiki/Trie representing the
dictionary.
2) create a aux array for the search key. as count [ key[i] ] ++;
3) Start a recursion from the root of the trie and pick a path if (count [
path ]  0 )
  3rd step ensures that we traverse only those valid paths (ie valid
words, this would reduce n! checking of all combinations).

On Thu, Aug 23, 2012 at 8:23 PM, Ashish Goel ashg...@gmail.com wrote:

 yes, that is correct.
 O(mn) to form multimap and then O(m) to tell all anagram groups

 Best Regards
 Ashish Goel
 Think positive and find fuel in failure
 +919985813081
 +919966006652


 On Thu, Aug 23, 2012 at 5:11 PM, kings dns.bhar...@gmail.com wrote:

 Dear GC,

 The efficient data structure in my opinion is Hash Table.

 1. For a given word in the dictionary we need to form an anagram
 dictionary i.e. take a given word sort it which forms the key for the
 hashtable , then start forming the different anagrams for that word and
 insert it into the hash table with the corresponding key.

 2. Once the hash table is ready for the given word sort it find the key
 and print all the anagarams i.e. values associated to that key. we will get
 all the anagrams for a given word.

 Coming to time complexity...

 sorting of a word can be done in a O(nlogn).
 building of anagram will take O(n).
 hash complexity O(n) worst case.
 so total time complexity is O(nlogn) for whole execrcise.

 Thanks
 Bhargava


 On Wednesday, 22 August 2012 23:39:02 UTC+5:30, GC wrote:

 Ques..

 Given a m-word dictionary ... and a n-sized word... .. now suggest DS
 for dictionary such that you can find out all the anagrams of the given
 word present in dictionary...


 --
 Regards,
 G C



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[algogeeks] Re: MS interview:

2011-07-27 Thread geek forgeek
anyone??

On Tue, Jul 26, 2011 at 11:36 PM, geek forgeek geekhori...@gmail.comwrote:

 Function to display the directory structure in a user friendly way taking
 root dir as arg
 for a general OS. You may assume and state some basic APIs available in
 that OS


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Re: [algogeeks] Re: MS interview:

2011-07-27 Thread sunny agrawal
There is a Book: Advance Programming in Unix Environment by Richard Stevens
in Chapter 2 i think there is a code that does the job of directory Listing
for given Directory

this is the code - for directory listing

*#include dirent.h
int main(int argc, char *argv[])
{
DIR *dp;
struct dirent *dirp;
if (argc != 2)
err_quit(usage: ls directory_name);
if ((dp = opendir(argv[1])) == NULL)
err_sys(can't open %s, argv[1]);
while ((dirp = readdir(dp)) != NULL)
printf(%s\n, dirp-d_name);
closedir(dp);
exit(0);
}*


for this Question u just need to change this code and use recursion for
directory inside Directories
there are some attributes that are used to identify some object as file,
directory, root directory and parent directory. so in recursion u will take
care for those

On Wed, Jul 27, 2011 at 12:13 PM, geek forgeek geekhori...@gmail.com
wrote:
 anyone??

 On Tue, Jul 26, 2011 at 11:36 PM, geek forgeek geekhori...@gmail.com
 wrote:

 Function to display the directory structure in a user friendly way taking
 root dir as arg
 for a general OS. You may assume and state some basic APIs available in
 that OS

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-- 
Sunny Aggrawal
B-Tech IV year,CSI
Indian Institute Of Technology,Roorkee

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Re: [algogeeks] Re: MS Interview

2011-06-13 Thread Ashish Goel
suppose numbers are 11,12,13,15 then you get some xor_val for xor of all
these numbers
after this

for (int i=11;i=15;i++) xor_val ^=i;

now xor_val is 14



Best Regards
Ashish Goel
Think positive and find fuel in failure
+919985813081
+919966006652


On Sun, Jun 12, 2011 at 9:24 PM, Supraja Jayakumar suprajasank...@gmail.com
 wrote:

 Hi

 But does this work on bigger numbers ?

 I mean with [11-15] say 14 is missing.

 It is:

 1011
 1100
 1101
 
 
 0101
 ---
 which is 5 ?

 Supraja J


 On Sat, Jun 11, 2011 at 8:14 AM, Wladimir Tavares 
 wladimir...@gmail.comwrote:

 You can use the same idea:

 Suppose you want to find out what the missing number in the list [1 .. 5]
 :
   1 = 001
   2 = 010
   3 = 011
   4 = 100
   5 = 101
 XOR = 001

 If the number 4 is missing:
   XOR = 001
   1 = 001
   2 = 010
   3 =
 011
   4 = 100
5 = 101
   3 = 011
 XOR = 011


 Wladimir Araujo Tavares
 *Federal University of Ceará

 *




 On Thu, Jun 9, 2011 at 8:34 AM, Ashim Kapoor ashimkap...@gmail.comwrote:

 Could someone illustrate the XOR for question 2. I am a beginner to this.

 Many thanks!


 On Thu, Jun 9, 2011 at 4:58 PM, Piyush Sinha 
 ecstasy.piy...@gmail.comwrote:

 Xoring it twice ...once with the elements in the file and then from i=1
 to 4,000,000,000..the answer left is the missing number

 On Thu, Jun 9, 2011 at 4:46 PM, Dumanshu duman...@gmail.com wrote:

 I dont think numbers are sorted in the 1st question. btw
 @sunny: how will xor-ing give the ans? for 1st ques?


 On Jun 9, 3:34 pm, sunny agrawal sunny816.i...@gmail.com wrote:
  yes, but using xor no need of ULL :)
 
  2011/6/9 • » νιρυℓ « • vipulmehta.1...@gmail.com

 
 
 
 
 
 
 
 
 
   Sum wont overflow, ULL range will include sum.
 
   On Thu, Jun 9, 2011 at 3:52 PM, sunny agrawal 
 sunny816.i...@gmail.comwrote:

 
   sum can overflow
   Xor method can also be applied to Q1. no need of numbers to be
 sorted.
 
   2011/6/9 • » νιρυℓ « • vipulmehta.1...@gmail.com

 
   For 1.
   sum the numbers in the file, subtract it from sum of first 4
 billion
   numbers.
 
   On Thu, Jun 9, 2011 at 3:44 PM, Navneet Gupta 
 navneetn...@gmail.comwrote:

 
   The answer to second question is simple. XORing all the elements
   should do it for you.
 
On Thu, Jun 9, 2011 at 3:15 PM, Dumanshu duman...@gmail.com
 wrote:
Q1. I  have a file in which there are supposed to be 4 billion
numbers,
starting from 1 to 4,000,000,000 but unfortunately one number
 is
missing,
i.e there are only 3,999,999,999 numbers, I need to find the
 missing
number.
 
Q2.  I have an array consisting of 2n+1 elements. n elements
 in it are
married, i.e they occur twice in the array, however there is
 one
element
which only appears once in the array. I need to find that
 number in a
single pass using constant memory. {assume all are positive
 numbers}
Eg :- 3 4 1 3 1 7 2 2 4
Ans:- 7
 
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   Vipul
 
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   B-Tech IV year,CSI
   Indian Institute Of Technology,Roorkee
 
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   Vipul
 
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Re: [algogeeks] Re: MS Interview

2011-06-12 Thread Supraja Jayakumar
Hi

But does this work on bigger numbers ?

I mean with [11-15] say 14 is missing.

It is:

1011
1100
1101


0101
---
which is 5 ?

Supraja J

On Sat, Jun 11, 2011 at 8:14 AM, Wladimir Tavares wladimir...@gmail.comwrote:

 You can use the same idea:

 Suppose you want to find out what the missing number in the list [1 .. 5]:
   1 = 001
   2 = 010
   3 = 011
   4 = 100
   5 = 101
 XOR = 001

 If the number 4 is missing:
   XOR = 001
   1 = 001
   2 = 010
   3 =
 011
   4 = 100
   5 = 101
   3 = 011
 XOR = 011


 Wladimir Araujo Tavares
 *Federal University of Ceará

 *




 On Thu, Jun 9, 2011 at 8:34 AM, Ashim Kapoor ashimkap...@gmail.comwrote:

 Could someone illustrate the XOR for question 2. I am a beginner to this.

 Many thanks!


 On Thu, Jun 9, 2011 at 4:58 PM, Piyush Sinha ecstasy.piy...@gmail.comwrote:

 Xoring it twice ...once with the elements in the file and then from i=1
 to 4,000,000,000..the answer left is the missing number

 On Thu, Jun 9, 2011 at 4:46 PM, Dumanshu duman...@gmail.com wrote:

 I dont think numbers are sorted in the 1st question. btw
 @sunny: how will xor-ing give the ans? for 1st ques?


 On Jun 9, 3:34 pm, sunny agrawal sunny816.i...@gmail.com wrote:
  yes, but using xor no need of ULL :)
 
  2011/6/9 • » νιρυℓ « • vipulmehta.1...@gmail.com

 
 
 
 
 
 
 
 
 
   Sum wont overflow, ULL range will include sum.
 
   On Thu, Jun 9, 2011 at 3:52 PM, sunny agrawal 
 sunny816.i...@gmail.comwrote:

 
   sum can overflow
   Xor method can also be applied to Q1. no need of numbers to be
 sorted.
 
   2011/6/9 • » νιρυℓ « • vipulmehta.1...@gmail.com

 
   For 1.
   sum the numbers in the file, subtract it from sum of first 4
 billion
   numbers.
 
   On Thu, Jun 9, 2011 at 3:44 PM, Navneet Gupta 
 navneetn...@gmail.comwrote:

 
   The answer to second question is simple. XORing all the elements
   should do it for you.
 
On Thu, Jun 9, 2011 at 3:15 PM, Dumanshu duman...@gmail.com
 wrote:
Q1. I  have a file in which there are supposed to be 4 billion
numbers,
starting from 1 to 4,000,000,000 but unfortunately one number
 is
missing,
i.e there are only 3,999,999,999 numbers, I need to find the
 missing
number.
 
Q2.  I have an array consisting of 2n+1 elements. n elements in
 it are
married, i.e they occur twice in the array, however there is
 one
element
which only appears once in the array. I need to find that
 number in a
single pass using constant memory. {assume all are positive
 numbers}
Eg :- 3 4 1 3 1 7 2 2 4
Ans:- 7
 
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   --
   --Navneet
 
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   Regards,
   Vipul
 
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   --
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   B-Tech IV year,CSI
   Indian Institute Of Technology,Roorkee
 
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   Vipul
 
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  --
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  B-Tech IV year,CSI
  Indian Institute Of Technology,Roorkee

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Re: [algogeeks] Re: MS Interview

2011-06-11 Thread Ashim Kapoor
Could someone illustrate the XOR for question 2. I am a beginner to this.

Many thanks!

On Thu, Jun 9, 2011 at 4:58 PM, Piyush Sinha ecstasy.piy...@gmail.comwrote:

 Xoring it twice ...once with the elements in the file and then from i=1 to
 4,000,000,000..the answer left is the missing number

 On Thu, Jun 9, 2011 at 4:46 PM, Dumanshu duman...@gmail.com wrote:

 I dont think numbers are sorted in the 1st question. btw
 @sunny: how will xor-ing give the ans? for 1st ques?


 On Jun 9, 3:34 pm, sunny agrawal sunny816.i...@gmail.com wrote:
  yes, but using xor no need of ULL :)
 
  2011/6/9 • » νιρυℓ « • vipulmehta.1...@gmail.com

 
 
 
 
 
 
 
 
 
   Sum wont overflow, ULL range will include sum.
 
   On Thu, Jun 9, 2011 at 3:52 PM, sunny agrawal 
 sunny816.i...@gmail.comwrote:

 
   sum can overflow
   Xor method can also be applied to Q1. no need of numbers to be
 sorted.
 
   2011/6/9 • » νιρυℓ « • vipulmehta.1...@gmail.com

 
   For 1.
   sum the numbers in the file, subtract it from sum of first 4 billion
   numbers.
 
   On Thu, Jun 9, 2011 at 3:44 PM, Navneet Gupta 
 navneetn...@gmail.comwrote:

 
   The answer to second question is simple. XORing all the elements
   should do it for you.
 
On Thu, Jun 9, 2011 at 3:15 PM, Dumanshu duman...@gmail.com
 wrote:
Q1. I  have a file in which there are supposed to be 4 billion
numbers,
starting from 1 to 4,000,000,000 but unfortunately one number is
missing,
i.e there are only 3,999,999,999 numbers, I need to find the
 missing
number.
 
Q2.  I have an array consisting of 2n+1 elements. n elements in
 it are
married, i.e they occur twice in the array, however there is one
element
which only appears once in the array. I need to find that number
 in a
single pass using constant memory. {assume all are positive
 numbers}
Eg :- 3 4 1 3 1 7 2 2 4
Ans:- 7
 
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Re: [algogeeks] Re: MS Interview

2011-06-11 Thread Wladimir Tavares
Suppose you want to find out what the missing number in the list [1 .. 5]:
  1 = 001
  2 = 010
  3 = 011
  4 = 100
  5 = 101
XOR = 001

If the number 4 is missing:
  XOR = 001
  1 = 001
  2 = 010
  3 = 011
  5 = 101
XOR = 100

You can see that the method works by properties of the XOR (you can see it?)
.

The same is true when only a number is doubled (Right?).
Wladimir Araujo Tavares
*Federal University of Ceará

*




On Fri, Jun 10, 2011 at 5:13 PM, Dumanshu duman...@gmail.com wrote:

 @kunal... yeah it will work. thnx :)

 On Jun 10, 11:41 pm, Kunal Patil kp101...@gmail.com wrote:
  @ Dumanshu:
  With memory restriction also XOR method works.. :)
  In this case difference is just that you will be working with
 400/ X
  number of files..where X is size of the RAM...just maintain a variable
  Curr_XOR_value and go on XORing it with element read from the file.
  When you are done with reading all those numbers from 400/ X
  files..
  (Curr_XOR_value) * XOR*  (expected_XOR_value for 1 to 400) ...
  will give missing number...

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Re: [algogeeks] Re: MS Interview

2011-06-11 Thread Wladimir Tavares
You will use three properties of XOR on two issues:
A XOR A = 0
A XOR B XOR B = A (commutativity)
A XOR (B XOR C) = (A XOR B) XOR C (Associativity)


Wladimir Araujo Tavares
*Federal University of Ceará

*




On Thu, Jun 9, 2011 at 8:28 AM, Piyush Sinha ecstasy.piy...@gmail.comwrote:

 Xoring it twice ...once with the elements in the file and then from i=1 to
 4,000,000,000..the answer left is the missing number


 On Thu, Jun 9, 2011 at 4:46 PM, Dumanshu duman...@gmail.com wrote:

 I dont think numbers are sorted in the 1st question. btw
 @sunny: how will xor-ing give the ans? for 1st ques?

 On Jun 9, 3:34 pm, sunny agrawal sunny816.i...@gmail.com wrote:
  yes, but using xor no need of ULL :)
 
  2011/6/9 • » νιρυℓ « • vipulmehta.1...@gmail.com
 
 
 
 
 
 
 
 
 
   Sum wont overflow, ULL range will include sum.
 
   On Thu, Jun 9, 2011 at 3:52 PM, sunny agrawal 
 sunny816.i...@gmail.comwrote:
 
   sum can overflow
   Xor method can also be applied to Q1. no need of numbers to be
 sorted.
 
   2011/6/9 • » νιρυℓ « • vipulmehta.1...@gmail.com
 
   For 1.
   sum the numbers in the file, subtract it from sum of first 4 billion
   numbers.
 
   On Thu, Jun 9, 2011 at 3:44 PM, Navneet Gupta 
 navneetn...@gmail.comwrote:
 
   The answer to second question is simple. XORing all the elements
   should do it for you.
 
On Thu, Jun 9, 2011 at 3:15 PM, Dumanshu duman...@gmail.com
 wrote:
Q1. I  have a file in which there are supposed to be 4 billion
numbers,
starting from 1 to 4,000,000,000 but unfortunately one number is
missing,
i.e there are only 3,999,999,999 numbers, I need to find the
 missing
number.
 
Q2.  I have an array consisting of 2n+1 elements. n elements in
 it are
married, i.e they occur twice in the array, however there is one
element
which only appears once in the array. I need to find that number
 in a
single pass using constant memory. {assume all are positive
 numbers}
Eg :- 3 4 1 3 1 7 2 2 4
Ans:- 7
 
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[algogeeks] Re: MS Interview

2011-06-10 Thread Dumanshu
Nothing is specified but lets take it as 2MB ram

On Jun 10, 10:14 am, hary rathor harry.rat...@gmail.com wrote:
 dumnanshu
  you should first mention memory size in your computer  so that i could know
 that how many number i can have in main memory at time

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[algogeeks] Re: MS Interview

2011-06-10 Thread sarath prasath
ex-or operation on all the elements give you the answer.


On Jun 9, 5:45 am, Dumanshu duman...@gmail.com wrote:
 Q1. I  have a file in which there are supposed to be 4 billion
 numbers,
 starting from 1 to 4,000,000,000 but unfortunately one number is
 missing,
 i.e there are only 3,999,999,999 numbers, I need to find the missing
 number.

 Q2.  I have an array consisting of 2n+1 elements. n elements in it are
 married, i.e they occur twice in the array, however there is one
 element
 which only appears once in the array. I need to find that number in a
 single pass using constant memory. {assume all are positive numbers}
 Eg :- 3 4 1 3 1 7 2 2 4
 Ans:- 7

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Re: [algogeeks] Re: MS Interview

2011-06-10 Thread Kunal Patil
@ Dumanshu:
With memory restriction also XOR method works.. :)
In this case difference is just that you will be working with 400/ X
number of files..where X is size of the RAM...just maintain a variable
Curr_XOR_value and go on XORing it with element read from the file.
When you are done with reading all those numbers from 400/ X
files..
(Curr_XOR_value) * XOR*  (expected_XOR_value for 1 to 400) ...
will give missing number...

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[algogeeks] Re: MS Interview

2011-06-10 Thread Dumanshu
@kunal: could u plz explan ur XOR approach by using a small set of
numbers. lets say we have numbers from 1 to 5 and one number is
missing. so u mean 1 XOR 2 XOR 4 XOR 5 would give me 3???

On Jun 10, 11:41 pm, Kunal Patil kp101...@gmail.com wrote:
 @ Dumanshu:
 With memory restriction also XOR method works.. :)
 In this case difference is just that you will be working with 400/ X
 number of files..where X is size of the RAM...just maintain a variable
 Curr_XOR_value and go on XORing it with element read from the file.
 When you are done with reading all those numbers from 400/ X
 files..
 (Curr_XOR_value) * XOR*  (expected_XOR_value for 1 to 400) ...
 will give missing number...

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[algogeeks] Re: MS Interview

2011-06-10 Thread Dumanshu
@kunal... yeah it will work. thnx :)

On Jun 10, 11:41 pm, Kunal Patil kp101...@gmail.com wrote:
 @ Dumanshu:
 With memory restriction also XOR method works.. :)
 In this case difference is just that you will be working with 400/ X
 number of files..where X is size of the RAM...just maintain a variable
 Curr_XOR_value and go on XORing it with element read from the file.
 When you are done with reading all those numbers from 400/ X
 files..
 (Curr_XOR_value) * XOR*  (expected_XOR_value for 1 to 400) ...
 will give missing number...

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[algogeeks] Re: MS Interview

2011-06-09 Thread Dumanshu
I dont think numbers are sorted in the 1st question. btw
@sunny: how will xor-ing give the ans? for 1st ques?

On Jun 9, 3:34 pm, sunny agrawal sunny816.i...@gmail.com wrote:
 yes, but using xor no need of ULL :)

 2011/6/9 • » νιρυℓ « • vipulmehta.1...@gmail.com









  Sum wont overflow, ULL range will include sum.

  On Thu, Jun 9, 2011 at 3:52 PM, sunny agrawal 
  sunny816.i...@gmail.comwrote:

  sum can overflow
  Xor method can also be applied to Q1. no need of numbers to be sorted.

  2011/6/9 • » νιρυℓ « • vipulmehta.1...@gmail.com

  For 1.
  sum the numbers in the file, subtract it from sum of first 4 billion
  numbers.

  On Thu, Jun 9, 2011 at 3:44 PM, Navneet Gupta 
  navneetn...@gmail.comwrote:

  The answer to second question is simple. XORing all the elements
  should do it for you.

  On Thu, Jun 9, 2011 at 3:15 PM, Dumanshu duman...@gmail.com wrote:
   Q1. I  have a file in which there are supposed to be 4 billion
   numbers,
   starting from 1 to 4,000,000,000 but unfortunately one number is
   missing,
   i.e there are only 3,999,999,999 numbers, I need to find the missing
   number.

   Q2.  I have an array consisting of 2n+1 elements. n elements in it are
   married, i.e they occur twice in the array, however there is one
   element
   which only appears once in the array. I need to find that number in a
   single pass using constant memory. {assume all are positive numbers}
   Eg :- 3 4 1 3 1 7 2 2 4
   Ans:- 7

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Re: [algogeeks] Re: MS Interview

2011-06-09 Thread Piyush Sinha
Xoring it twice ...once with the elements in the file and then from i=1 to
4,000,000,000..the answer left is the missing number

On Thu, Jun 9, 2011 at 4:46 PM, Dumanshu duman...@gmail.com wrote:

 I dont think numbers are sorted in the 1st question. btw
 @sunny: how will xor-ing give the ans? for 1st ques?

 On Jun 9, 3:34 pm, sunny agrawal sunny816.i...@gmail.com wrote:
  yes, but using xor no need of ULL :)
 
  2011/6/9 • » νιρυℓ « • vipulmehta.1...@gmail.com
 
 
 
 
 
 
 
 
 
   Sum wont overflow, ULL range will include sum.
 
   On Thu, Jun 9, 2011 at 3:52 PM, sunny agrawal sunny816.i...@gmail.com
 wrote:
 
   sum can overflow
   Xor method can also be applied to Q1. no need of numbers to be sorted.
 
   2011/6/9 • » νιρυℓ « • vipulmehta.1...@gmail.com
 
   For 1.
   sum the numbers in the file, subtract it from sum of first 4 billion
   numbers.
 
   On Thu, Jun 9, 2011 at 3:44 PM, Navneet Gupta navneetn...@gmail.com
 wrote:
 
   The answer to second question is simple. XORing all the elements
   should do it for you.
 
On Thu, Jun 9, 2011 at 3:15 PM, Dumanshu duman...@gmail.com
 wrote:
Q1. I  have a file in which there are supposed to be 4 billion
numbers,
starting from 1 to 4,000,000,000 but unfortunately one number is
missing,
i.e there are only 3,999,999,999 numbers, I need to find the
 missing
number.
 
Q2.  I have an array consisting of 2n+1 elements. n elements in it
 are
married, i.e they occur twice in the array, however there is one
element
which only appears once in the array. I need to find that number
 in a
single pass using constant memory. {assume all are positive
 numbers}
Eg :- 3 4 1 3 1 7 2 2 4
Ans:- 7
 
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[algogeeks] Re: MS Interview

2011-06-09 Thread ankit arun
part 1 can be solved in O(1) complexity.. first adding all the numbers
and then subtracting it from 4,000,000,000 will give the result.

On Jun 9, 2:45 pm, Dumanshu duman...@gmail.com wrote:
 Q1. I  have a file in which there are supposed to be 4 billion
 numbers,
 starting from 1 to 4,000,000,000 but unfortunately one number is
 missing,
 i.e there are only 3,999,999,999 numbers, I need to find the missing
 number.

 Q2.  I have an array consisting of 2n+1 elements. n elements in it are
 married, i.e they occur twice in the array, however there is one
 element
 which only appears once in the array. I need to find that number in a
 single pass using constant memory. {assume all are positive numbers}
 Eg :- 3 4 1 3 1 7 2 2 4
 Ans:- 7

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Re: [algogeeks] Re: MS Interview

2011-06-09 Thread Freak Algo

Is not it O(n)?

--- On Thu, 9/6/11, ankit arun talk.ankit...@gmail.com wrote:

From: ankit arun talk.ankit...@gmail.com
Subject: [algogeeks] Re: MS Interview
To: Algorithm Geeks algogeeks@googlegroups.com
Date: Thursday, 9 June, 2011, 11:49 AM

part 1 can be solved in O(1) complexity.. first adding all the numbers
and then subtracting it from 4,000,000,000 will give the result.

On Jun 9, 2:45 pm, Dumanshu duman...@gmail.com wrote:
 Q1. I  have a file in which there are supposed to be 4 billion
 numbers,
 starting from 1 to 4,000,000,000 but unfortunately one number is
 missing,
 i.e there are only 3,999,999,999 numbers, I need to find the missing
 number.

 Q2.  I have an array consisting of 2n+1 elements. n elements in it are
 married, i.e they occur twice in the array, however there is one
 element
 which only appears once in the array. I need to find that number in a
 single pass using constant memory. {assume all are positive numbers}
 Eg :- 3 4 1 3 1 7 2 2 4
 Ans:- 7

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