so it means after sequence point the post increment is done...after ht
epost increment is incremented and value is reflected...m i ryt?
On Fri, Oct 26, 2012 at 8:43 PM, Saurabh Kumar srbh.ku...@gmail.com wrote:
You're right , || all introduce a sequence point. In first case
evaluation proceeds like this:
j = (i++, i++);
*i++* Post increment the i (i is now 11)
*j = i++* Post increment the i (j is assigned 11 and i is now 12)
In second case, the whole of rvalue for = operator will be evaluated
first...
j = a++ 1;
*a++ *a is Post incremented (a is now 1 but return value is 0)
*0 1* = 0 (which gets assigned to j)
Hence, j = 0, a = 1
On 26 October 2012 18:54, rahul sharma rahul23111...@gmail.com wrote:
Guys plz tell that postincremented variable is incremented after
sequence or after ;
as we have || comma and ; as sequence point
so say we have
int i=10;
int j=(i++,i++);
firstly i++ goes and as comma comes so ++ post inc. takes place and take
to 11 ..now when next time the postincremented is done later after ; and
firstly the value 11 is assigned to j
so after this statement we have j=11,i=12
but if i write
int a=0;
int j=a++1;
so when comes so postincrement takes place and assign this to j...so
at the point we reach acc. to me a=1..But a remains 0 as this expression
goes to false...can anybody tell me y so happens..when does the value in
postincremented is incremented...i am sure about comm and ;...but what in
case of and ||these are also sequence point...y post increment
doesnt take place when we reach ...please explain..
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