output 1 because it is pointing to first position of the array..
5 is because (*h)++; --- here it is adding sizeof(int) to 1...
if u make h as short type , then it will add 2 to 1..
i don't know why exactly ..
On Sat, Sep 3, 2011 at 2:36 PM, Ankit Sablok
ankitsablok19091...@gmail.comwrote:
#includeiostream
#includecstdio
#includecctype
#includecstdlib
#includecstring
using namespace std;
int main()
{
int **h;
int a[2][2]={1,2,3,4};
h= (int **)a;
int i,j;
printf(\n%d,*h);
(*h)++;
printf(\n%d,*h);
getchar();
getchar();
return 0;
}
gives an output 1 and 5 why?
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