Re: [algogeeks] Re: Needed recursive sol

2011-10-02 Thread rahul sharma
@rahul tiwari..i have that soln...i think u cnt get questionhw do we knw
the number of terms?/

On Sun, Oct 2, 2011 at 2:09 PM, Rahul Tiwari rahultiwari6...@gmail.comwrote:

 working code :

 #includestdio.h

  int fib(int n)
 {
if(n==1) return 0;
if(n==2) return 1;
return fib(n-1)+fib(n-2);
 }

 int main()
 {
int n,i,sum=0;

printf(enter no of terms\t );
scanf(%d,n);
printf(fibonacci series = \t );
for(i=1;i=n;i++)
{
printf(%d\t,fib(i));
sum+=fib(i);
}

printf(\nsum upto %d terms = %d\n,n,sum);
return 0;
 }



 rahul

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Re: [algogeeks] Re: Needed recursive sol

2011-10-01 Thread rahul sharma
gr 8 soln...thnx

2011/10/2 akanksha akanksha.271...@gmail.com

 int sum(int f0,int f1)
 {
if(f1=1000)
{
int x= sum(f1,f0+f1);
if(f1%2==0) x+=f1;
return x;
}
else
return 0;
 }

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Re: [algogeeks] Re: Needed recursive sol

2011-10-01 Thread Siddhartha Banerjee
there must be a non brute force approach too rite???

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Re: [algogeeks] Re: Needed recursive sol

2011-10-01 Thread rahul sharma
yea...first sol is brute force...but this is not..that is posted by
akanshai think...but not sure...the question wants only
recursivehoope sumone may come with sumthng new

On Sun, Oct 2, 2011 at 10:35 AM, Siddhartha Banerjee 
thefourrup...@gmail.com wrote:

 there must be a non brute force approach too rite???

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Re: [algogeeks] Re: Needed recursive sol

2011-10-01 Thread shady
this is bruteforce. You are calculating all fib. numbers.

On Sun, Oct 2, 2011 at 10:38 AM, rahul sharma rahul23111...@gmail.comwrote:

 yea...first sol is brute force...but this is not..that is posted by
 akanshai think...but not sure...the question wants only
 recursivehoope sumone may come with sumthng new


 On Sun, Oct 2, 2011 at 10:35 AM, Siddhartha Banerjee 
 thefourrup...@gmail.com wrote:

 there must be a non brute force approach too rite???

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Re: [algogeeks] Re: Needed recursive sol

2011-10-01 Thread Marcelo Amorim Menegali
Using Wladimir's formulas, you have:

F(0) + F(1) + F(2) + F(3) + F(4) + F(5) + F(6) + ... + F(3n-2) + F(3n-1) +
F(3n) = F(3n+2) - 1
F(0) +(F(1) + F(2))+ F(3) +(F(4) + F(5))+ F(6) + ... +(F(3n-2) + F(3n-1))+
F(3n) = F(3n+2) - 1
F(0) + 2F(3) + 2F(6) + ... + 2F(3n) = F(3n+2) - 1

Since F(0) = 0,
F(0) + F(3) + F(6) + ... + F(3n) = (F(3n+2) - 1)/2


Marcelo Menegali

On Sun, Oct 2, 2011 at 2:10 AM, shady sinv...@gmail.com wrote:

 this is bruteforce. You are calculating all fib. numbers.


 On Sun, Oct 2, 2011 at 10:38 AM, rahul sharma rahul23111...@gmail.comwrote:

 yea...first sol is brute force...but this is not..that is posted by
 akanshai think...but not sure...the question wants only
 recursivehoope sumone may come with sumthng new


 On Sun, Oct 2, 2011 at 10:35 AM, Siddhartha Banerjee 
 thefourrup...@gmail.com wrote:

 there must be a non brute force approach too rite???

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