Re: [algogeeks] char *arr and char arr[]

[sunny agrawal]

you can not change that
it will give error if you will try to change
if want to modify
you should declare it as
char a[] = pilani

On Sat, Jun 25, 2011 at 12:47 PM, oppilas . jatka.oppimi...@gmail.comwrote:

 I was reading about how char *arr is different from char arr[].
 Now, as in char *arr=Pilani,
 arr stores the base address of the memory block reserved for Pilani.
 How, can I change the any character at that particular memory block?
 arr[0] ='T' gives error.

 #includeiostream
 using namespace std;
 int main(){
char *p=Pilani;
   // p[0]='K'// does not work.
   // *(p[0])='s'; //does not work;
coutp[0]  (void *)p  \n;
return 0;
 }

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-- 
Sunny Aggrawal
B-Tech IV year,CSI
Indian Institute Of Technology,Roorkee

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Re: [algogeeks] char *arr and char arr[]

[hary rathor]

sol 1 :

#includeiostream
using namespace std;
int main(){
   char arr[]=Pilani,*p=arr;
 p[0]='K';// does not work.
*(p[0])='s'; //does not work;
   coutp[0]  (void *)p  \n;
   return 0;
}

sol 2 :
#includeiostream
using namespace std;
int main(){
   char *p=(char *)Pilani;
 p[0]='K';// does not work.
*(p[0])='s'; //does not work;
   coutp[0]  (void *)p  \n;
   return 0;
}

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Re: [algogeeks] char *arr and char arr[]

[sameer.mut...@gmail.com]

May i know the reason please?

On Sat, Jun 25, 2011 at 1:06 PM, hary rathor harry.rat...@gmail.com wrote:

 sol 1 :

 #includeiostream
 using namespace std;
 int main(){
char arr[]=Pilani,*p=arr;
  p[0]='K';// does not work.
  *(p[0])='s'; //does not work;
coutp[0]  (void *)p  \n;
return 0;
 }

 sol 2 :
 #includeiostream
 using namespace std;
 int main(){
char *p=(char *)Pilani;
  p[0]='K';// does not work.
 *(p[0])='s'; //does not work;
coutp[0]  (void *)p  \n;
return 0;
 }

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