RE: [AMRadio] Re: capacitors for tank circuits
Sorry if this is doubled - I think I sent it with the wrong SMTP the first time so here it goes again. Yep, very good points Don. What I was mostly trying to say to Barrie was that tubes should be chosen first so as to acquire a ratio of plate current to plate voltage that will be used and then design the tank circuit around that. 400 Watts DC input can be achieved by 8 - 6146s in push pull parallel but because of the low voltage and high current the tank circuit would have a much larger amount of capacitance and less coil than a tank that is for a pair of 75ths at high voltage and less current. Also Barrie, when using the charts, you should be sure to choose the one for class C not the chart for linear operation. The tank Q is all together different. I used the example of the 8 - 6146s only as an example. If you were to try that you would have a difficult time finding a modulation XFMR to match the 900 ohm load that those tubes would represent to a modulator. John, WA5BXO -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of D. Chester Sent: Wednesday, April 16, 2008 11:42 AM To: amradio@mailman.qth.net Subject: [AMRadio] Re: capacitors for tank circuits > From: "John Coleman" <[EMAIL PROTECTED]> > The size of the spilt stator capacitor that you are looking for (will) > need to > be determined by the voltage and current that you intend to run, The > ratio of I:E determines the capacitance There are charts in the handbooks > for this purpose. Be sure to consider that you are doing push pull with a > balanced tank circuit as the required capacitance is only a quarter of > that > required for non-balanced. The voltage will determine the needed spacing > of > the plates. If you raise the tank capacitor above the chassis on > insulators > and connect the rotor to B+ you can get by with less spacing but you will > need to use and insulated coupler to the knob shaft and be sure the knob > shaft is grounded for safety. You can also accomplished the same thing by > using two large RF chokes, one per tube, and capacitive coupling the RF to > the tank circuit as is done in most PI net circuits. This way the plate > tank cap can be mounted to chassis and the RF choke at the center of the > tank coil can be grounded. The idea is to not have a DC + modulation > voltage across the plates of the tank capacitor but just RF voltage. > Capacitive coupling, as was just described, is a neat way to do this but > it > requires the very large long RF chokes and good coupling capacitors. For a balanced tank circuit, the capacitance is one fourth, but the voltage rating must be double that of single-ended. The reason for this is, that for a single-ended final, the tube is working into only half the balanced tank circuit, but the coil acts as a step-up autotransformer and the induced voltage across the other half of the coil is approximately equal to the voltage on the half that the tube works into, giving an rf voltage end-to-end that is twice that which is actually generated by the tube. It is exactly the same in the case of push-pull, since in class-C or even class-B service, only one tube is working into the tank circuit at a time, and each tube is working into one half of the tank circuit. Or you could think of it as each tube generating equal rf voltage, but the outputs of the two tubes are in series as they work into the tank circuit. But a capacitor with twice the voltage rating and one fourth the capacitance is equivalent to taking the original single-ended capacitor, splitting it in half, and wiring each of those halves in series. That is exactly what we mean by a split-stator capacitor. For example, take the BC-610, which runs the final at 2000 volts @ 250 mills. The tank capacitor is split stator with 150 pf per section. If the final were changed to unbalanced output, for example by substituting a 4-250 for the 250TH and converting to a pi-network, or by changing the grid tank to balanced and running the plate tank unbalanced, the final tank capacitor would need to be 300 pf in order to keep the tank circuit Q the same. That could easily be accomplished by wiring the two sections of the 150/150 split stator capacitor in parallel. The parallel connection gives 300 pf at approximately 7 kv rating. The series connection as used in the balanced tank, renders 75 pf at 14 kv rating. A single ended capacitor rated 75 pf @ 14 kv would be about the same size as the dual 150 @ 7 kv, and when new, the cost would have been about the same. The point is, for a given power level and plate voltage/plate current ratio, the physical size and cost of the tank capacitor is approximately the same, whether the tank is balanced or unbalanced. If a split stator capacitor is used, it can easily be connected up as a balanced or unbalanced tank. Of course, the number of turns in the balanced tank will be double that of the single ended one, si
RE: [AMRadio] Re: capacitors for tank circuits
Yep, very good points Don. What I was mostly trying to say to Barrie was that tubes should be chosen first so as to acquire a ratio of plate current to plate voltage that will be used and then design the tank circuit around that. 400 Watts DC input can be achieved by 8 - 6146s in push pull parallel but because of the low voltage and high current the tank circuit would have a much larger amount of capacitance and less coil than a tank that is for a pair of 75ths at high voltage and less current. Also Barrie, when using the charts, you should be sure to choose the one for class C not the chart for linear operation. The tank Q is all together different. I used the example of the 8 - 6146s only as an example. If you were to try that you would have a difficult time finding a modulation XFMR to match the 900 ohm load that those tubes would represent to a modulator. John, WA5BXO -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of D. Chester Sent: Wednesday, April 16, 2008 11:42 AM To: amradio@mailman.qth.net Subject: [AMRadio] Re: capacitors for tank circuits > From: "John Coleman" <[EMAIL PROTECTED]> > The size of the spilt stator capacitor that you are looking for (will) > need to > be determined by the voltage and current that you intend to run, The > ratio of I:E determines the capacitance There are charts in the handbooks > for this purpose. Be sure to consider that you are doing push pull with a > balanced tank circuit as the required capacitance is only a quarter of > that > required for non-balanced. The voltage will determine the needed spacing > of > the plates. If you raise the tank capacitor above the chassis on > insulators > and connect the rotor to B+ you can get by with less spacing but you will > need to use and insulated coupler to the knob shaft and be sure the knob > shaft is grounded for safety. You can also accomplished the same thing by > using two large RF chokes, one per tube, and capacitive coupling the RF to > the tank circuit as is done in most PI net circuits. This way the plate > tank cap can be mounted to chassis and the RF choke at the center of the > tank coil can be grounded. The idea is to not have a DC + modulation > voltage across the plates of the tank capacitor but just RF voltage. > Capacitive coupling, as was just described, is a neat way to do this but > it > requires the very large long RF chokes and good coupling capacitors. For a balanced tank circuit, the capacitance is one fourth, but the voltage rating must be double that of single-ended. The reason for this is, that for a single-ended final, the tube is working into only half the balanced tank circuit, but the coil acts as a step-up autotransformer and the induced voltage across the other half of the coil is approximately equal to the voltage on the half that the tube works into, giving an rf voltage end-to-end that is twice that which is actually generated by the tube. It is exactly the same in the case of push-pull, since in class-C or even class-B service, only one tube is working into the tank circuit at a time, and each tube is working into one half of the tank circuit. Or you could think of it as each tube generating equal rf voltage, but the outputs of the two tubes are in series as they work into the tank circuit. But a capacitor with twice the voltage rating and one fourth the capacitance is equivalent to taking the original single-ended capacitor, splitting it in half, and wiring each of those halves in series. That is exactly what we mean by a split-stator capacitor. For example, take the BC-610, which runs the final at 2000 volts @ 250 mills. The tank capacitor is split stator with 150 pf per section. If the final were changed to unbalanced output, for example by substituting a 4-250 for the 250TH and converting to a pi-network, or by changing the grid tank to balanced and running the plate tank unbalanced, the final tank capacitor would need to be 300 pf in order to keep the tank circuit Q the same. That could easily be accomplished by wiring the two sections of the 150/150 split stator capacitor in parallel. The parallel connection gives 300 pf at approximately 7 kv rating. The series connection as used in the balanced tank, renders 75 pf at 14 kv rating. A single ended capacitor rated 75 pf @ 14 kv would be about the same size as the dual 150 @ 7 kv, and when new, the cost would have been about the same. The point is, for a given power level and plate voltage/plate current ratio, the physical size and cost of the tank capacitor is approximately the same, whether the tank is balanced or unbalanced. If a split stator capacitor is used, it can easily be connected up as a balanced or unbalanced tank. Of course, the number of turns in the balanced tank will be double that of the single ended one, since 4 times the inductance is required to maintain resonance at the same frequency.OTOH, the wire s