Re: [android-beginners] Re: StringToFloat code
That or the constructor that takes a string - but anything over making your own
parser...
On 19 Jun 2010, at 22:12, Raymond Rodgers wrote:
> I think he was specifically referring to the parseFloat() function... This is
> a direct link to a slightly different version of the api he referenced...
> http://java.sun.com/javase/7/docs/api/java/lang/Float.html#parseFloat(java.lang.String)
>
> Raymond
> On 06/19/2010 01:38 PM, kille6525 wrote:
>> Oh yah i just tried the valueOf(String string) and it made my program
>> hate the two buttons one button caculates my two inputs and the other
>> finishes but when i added that in it didnt like any of them. Weird
>>
>> On Jun 19, 9:05 am, Mikey wrote:
>>
>>> What was wrong with this:
>>>
>>> http://java.sun.com/j2se/1.4.2/docs/api/java/lang/Float.html
>>>
>>> On 19 Jun 2010, at 17:02, kille6525 wrote:
>>>
>>>
Ok since the EditText.getText. will only allow you to get a string i
made a small program to get the string and convert it to a float. It
was a pain to do. You could change the return to an int or double but
i made this for floats...
Here is the horrible code...
>>>
public float StringToFloat(String text)
{
//Used for the for loops
int i = 0;
//The number your go to return
float number = 0;
//Used to specify if your before the decimal or after
int numtodec = 1;
//Size of the int. 123.6 sizeofint = 3
int sizeofint = -1;
//Gets the length of the String
int size = text.length();
//Sets an array of characters equ to the string
char string[] = text.toCharArray();
//Gets the size of the sizeofint and sizeofdec
for(i = 0; i< size; ++i)
{
if(string[i] == '.')
{
numtodec = 0;
continue;
}
if(numtodec == 1)
++sizeofint;
}
//resets the num to dec
numtodec = 1;
//Stores the number
for(i = 0; i< size; ++i)
{
if(string[i] == '.')
{
numtodec = 0;
continue;
}
int hold = string[i] - 48;
double hold2;
if(numtodec == 1)
hold2 =
java.lang.Math.pow(10.0,(double)(sizeofint - i));
else
hold2 =
java.lang.Math.pow(10.0,(double)(sizeofint+1 - i));
number += hold*hold2;
}
return number;
}
>>>
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>>
>
>
> --
> Raymond Rodgers
> http://www.badlucksoft.com/
>
> --
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Re: [android-beginners] Re: StringToFloat code
I think he was specifically referring to the parseFloat() function...
This is a direct link to a slightly different version of the api he
referenced...
http://java.sun.com/javase/7/docs/api/java/lang/Float.html#parseFloat(java.lang.String)
Raymond
On 06/19/2010 01:38 PM, kille6525 wrote:
Oh yah i just tried the valueOf(String string) and it made my program
hate the two buttons one button caculates my two inputs and the other
finishes but when i added that in it didnt like any of them. Weird
On Jun 19, 9:05 am, Mikey wrote:
What was wrong with this:
http://java.sun.com/j2se/1.4.2/docs/api/java/lang/Float.html
On 19 Jun 2010, at 17:02, kille6525 wrote:
Ok since the EditText.getText. will only allow you to get a string i
made a small program to get the string and convert it to a float. It
was a pain to do. You could change the return to an int or double but
i made this for floats...
Here is the horrible code...
public float StringToFloat(String text)
{
//Used for the for loops
int i = 0;
//The number your go to return
float number = 0;
//Used to specify if your before the decimal or after
int numtodec = 1;
//Size of the int. 123.6 sizeofint = 3
int sizeofint = -1;
//Gets the length of the String
int size = text.length();
//Sets an array of characters equ to the string
char string[] = text.toCharArray();
//Gets the size of the sizeofint and sizeofdec
for(i = 0; i< size; ++i)
{
if(string[i] == '.')
{
numtodec = 0;
continue;
}
if(numtodec == 1)
++sizeofint;
}
//resets the num to dec
numtodec = 1;
//Stores the number
for(i = 0; i< size; ++i)
{
if(string[i] == '.')
{
numtodec = 0;
continue;
}
int hold = string[i] - 48;
double hold2;
if(numtodec == 1)
hold2 = java.lang.Math.pow(10.0,(double)(sizeofint
- i));
else
hold2 =
java.lang.Math.pow(10.0,(double)(sizeofint+1 - i));
number += hold*hold2;
}
return number;
}
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Re: [android-beginners] Saving contents of a Spinner with onSaveInstanceState
On Sat, Jun 19, 2010 at 1:36 PM, -DC- wrote:
> I've got an app that uses a Spinner tied to an Adapter. I want to be
> able to save its contents when onSaveInstanceState is called, but am
> not sure which put method of the Bundle class I can use to do this?
>
> protected void onSaveInstanceState(Bundle outState) {
> //TODO: Figure out how to save mDirectories (spinner)
> outState.putString("mStatus", mStatus.getText().toString());
> outState.putString("mPath", mPath.getText().toString());
> // outState.putSerializable("mDirectories", mDirectories); <--
> Spinner object
> outState.putStringArray("links", links);
> outState.putInt("linksPointer", linksPointer);
> super.onSaveInstanceState(outState);
> }
You do not want to put a Spinner in the onSaveInstanceState() Bundle.
Besides the fact that it is impossible, doing so would cause your new
activity to hold onto a reference to that Spinner, which holds onto a
reference to your old activity, which will cause a substantial memory
leak.
Your Spinner's contents are set via some sort of Adapter. You should
be making sure your new Activity can re-create that Adapter. Then, put
either getItemSelectedId() or getItemSelectedPosition() in the Bundle,
so you can restore the selection in the new Activity.
--
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CommonsWare
mmur...@commonsware.com
http://commonsware.com
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[android-beginners] Re: StringToFloat code
Oh yah i just tried the valueOf(String string) and it made my program
hate the two buttons one button caculates my two inputs and the other
finishes but when i added that in it didnt like any of them. Weird
On Jun 19, 9:05 am, Mikey wrote:
> What was wrong with this:
>
> http://java.sun.com/j2se/1.4.2/docs/api/java/lang/Float.html
>
> On 19 Jun 2010, at 17:02, kille6525 wrote:
>
> > Ok since the EditText.getText. will only allow you to get a string i
> > made a small program to get the string and convert it to a float. It
> > was a pain to do. You could change the return to an int or double but
> > i made this for floats...
> > Here is the horrible code...
>
> > public float StringToFloat(String text)
> > {
> > //Used for the for loops
> > int i = 0;
> > //The number your go to return
> > float number = 0;
> > //Used to specify if your before the decimal or after
> > int numtodec = 1;
> > //Size of the int. 123.6 sizeofint = 3
> > int sizeofint = -1;
> > //Gets the length of the String
> > int size = text.length();
> > //Sets an array of characters equ to the string
> > char string[] = text.toCharArray();
> > //Gets the size of the sizeofint and sizeofdec
> > for(i = 0; i < size; ++i)
> > {
> > if(string[i] == '.')
> > {
> > numtodec = 0;
> > continue;
> > }
> > if(numtodec == 1)
> > ++sizeofint;
> > }
> > //resets the num to dec
> > numtodec = 1;
> > //Stores the number
> > for(i = 0; i < size; ++i)
> > {
> > if(string[i] == '.')
> > {
> > numtodec = 0;
> > continue;
> > }
> > int hold = string[i] - 48;
> > double hold2;
> > if(numtodec == 1)
> > hold2 =
> > java.lang.Math.pow(10.0,(double)(sizeofint - i));
> > else
> > hold2 =
> > java.lang.Math.pow(10.0,(double)(sizeofint+1 - i));
> > number += hold*hold2;
> > }
> > return number;
> > }
>
> > --
> > You received this message because you are subscribed to the Google
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[android-beginners] Saving contents of a Spinner with onSaveInstanceState
I've got an app that uses a Spinner tied to an Adapter. I want to be
able to save its contents when onSaveInstanceState is called, but am
not sure which put method of the Bundle class I can use to do this?
protected void onSaveInstanceState(Bundle outState) {
//TODO: Figure out how to save mDirectories (spinner)
outState.putString("mStatus", mStatus.getText().toString());
outState.putString("mPath", mPath.getText().toString());
//outState.putSerializable("mDirectories", mDirectories); <--
Spinner object
outState.putStringArray("links", links);
outState.putInt("linksPointer", linksPointer);
super.onSaveInstanceState(outState);
}
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[android-beginners] Re: StringToFloat code
There is no string to float function to do it for you. Now i dont have
it to where it will check for a negative or positive sign but in my
app there is none for now...
On Jun 19, 9:05 am, Mikey wrote:
> What was wrong with this:
>
> http://java.sun.com/j2se/1.4.2/docs/api/java/lang/Float.html
>
> On 19 Jun 2010, at 17:02, kille6525 wrote:
>
> > Ok since the EditText.getText. will only allow you to get a string i
> > made a small program to get the string and convert it to a float. It
> > was a pain to do. You could change the return to an int or double but
> > i made this for floats...
> > Here is the horrible code...
>
> > public float StringToFloat(String text)
> > {
> > //Used for the for loops
> > int i = 0;
> > //The number your go to return
> > float number = 0;
> > //Used to specify if your before the decimal or after
> > int numtodec = 1;
> > //Size of the int. 123.6 sizeofint = 3
> > int sizeofint = -1;
> > //Gets the length of the String
> > int size = text.length();
> > //Sets an array of characters equ to the string
> > char string[] = text.toCharArray();
> > //Gets the size of the sizeofint and sizeofdec
> > for(i = 0; i < size; ++i)
> > {
> > if(string[i] == '.')
> > {
> > numtodec = 0;
> > continue;
> > }
> > if(numtodec == 1)
> > ++sizeofint;
> > }
> > //resets the num to dec
> > numtodec = 1;
> > //Stores the number
> > for(i = 0; i < size; ++i)
> > {
> > if(string[i] == '.')
> > {
> > numtodec = 0;
> > continue;
> > }
> > int hold = string[i] - 48;
> > double hold2;
> > if(numtodec == 1)
> > hold2 =
> > java.lang.Math.pow(10.0,(double)(sizeofint - i));
> > else
> > hold2 =
> > java.lang.Math.pow(10.0,(double)(sizeofint+1 - i));
> > number += hold*hold2;
> > }
> > return number;
> > }
>
> > --
> > You received this message because you are subscribed to the Google
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Re: [android-beginners] Re: Comparing data retrieved from SQL query
And just as safe method for avoiding NPE, its good practice to do the
following...
if("text".equals(queryString))
//do stuff
On Fri, Jun 18, 2010 at 10:50 AM, Tollas wrote:
> Worked great! Thanks!
>
> On Jun 18, 11:12 am, Justin Anderson wrote:
> > You cannot use == for comparing strings. You have to use the equals
> method:
> >
> > if (queryString.equals("text"))
> > //do stuff
> >
> > --
> > There are only 10 types of people in the world...
> > Those who know binary and those who don't.
> > --
> >
> > On Fri, Jun 18, 2010 at 9:57 AM, Tollas wrote:
> > > I am retrieving data from a SQL query. The data retrieves fine. If I
> > > place the data in a TextView field, I see the text.
> > > When I try to compare it in an "IF" statement, however, the statement
> > > sees the data as false, even if it should be true.
> > > If I set the variable to a good value (not getting data from the SQL
> > > query) the IF statement works fine.
> >
> > > Example
> >
> > > String queryString = c.getString(c.getColumnIndex("table_query"));
> >
> > > if (queryString == "text"){
> > > // do this
> > > }
> >
> > > I have checked my data. If I query the database for table_query =
> > > 'text' I receive results.
> > > This is happening for 5 different fields where a comparison is made,
> > > each with a different variable and if statement.
> >
> > > --
> > > You received this message because you are subscribed to the Google
> > > Groups "Android Beginners" group.
> >
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> > >http://stackoverflow.com/questions/tagged/android
> >
> > > To unsubscribe from this group, send email to
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>
> >
> > > For more options, visit this group at
> > >http://groups.google.com/group/android-beginners?hl=en
>
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Re: [android-beginners] StringToFloat code
What was wrong with this:
http://java.sun.com/j2se/1.4.2/docs/api/java/lang/Float.html
On 19 Jun 2010, at 17:02, kille6525 wrote:
> Ok since the EditText.getText. will only allow you to get a string i
> made a small program to get the string and convert it to a float. It
> was a pain to do. You could change the return to an int or double but
> i made this for floats...
> Here is the horrible code...
>
>
>public float StringToFloat(String text)
>{
> //Used for the for loops
>int i = 0;
> //The number your go to return
>float number = 0;
> //Used to specify if your before the decimal or after
>int numtodec = 1;
> //Size of the int. 123.6 sizeofint = 3
>int sizeofint = -1;
> //Gets the length of the String
>int size = text.length();
> //Sets an array of characters equ to the string
>char string[] = text.toCharArray();
> //Gets the size of the sizeofint and sizeofdec
>for(i = 0; i < size; ++i)
>{
>if(string[i] == '.')
>{
>numtodec = 0;
>continue;
>}
> if(numtodec == 1)
> ++sizeofint;
>}
> //resets the num to dec
>numtodec = 1;
> //Stores the number
>for(i = 0; i < size; ++i)
>{
>if(string[i] == '.')
>{
>numtodec = 0;
>continue;
>}
> int hold = string[i] - 48;
> double hold2;
> if(numtodec == 1)
> hold2 =
> java.lang.Math.pow(10.0,(double)(sizeofint - i));
> else
> hold2 =
> java.lang.Math.pow(10.0,(double)(sizeofint+1 - i));
> number += hold*hold2;
>}
>return number;
>}
>
> --
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[android-beginners] StringToFloat code
Ok since the EditText.getText. will only allow you to get a string i
made a small program to get the string and convert it to a float. It
was a pain to do. You could change the return to an int or double but
i made this for floats...
Here is the horrible code...
public float StringToFloat(String text)
{
//Used for the for loops
int i = 0;
//The number your go to return
float number = 0;
//Used to specify if your before the decimal or after
int numtodec = 1;
//Size of the int. 123.6 sizeofint = 3
int sizeofint = -1;
//Gets the length of the String
int size = text.length();
//Sets an array of characters equ to the string
char string[] = text.toCharArray();
//Gets the size of the sizeofint and sizeofdec
for(i = 0; i < size; ++i)
{
if(string[i] == '.')
{
numtodec = 0;
continue;
}
if(numtodec == 1)
++sizeofint;
}
//resets the num to dec
numtodec = 1;
//Stores the number
for(i = 0; i < size; ++i)
{
if(string[i] == '.')
{
numtodec = 0;
continue;
}
int hold = string[i] - 48;
double hold2;
if(numtodec == 1)
hold2 =
java.lang.Math.pow(10.0,(double)(sizeofint - i));
else
hold2 =
java.lang.Math.pow(10.0,(double)(sizeofint+1 - i));
number += hold*hold2;
}
return number;
}
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Re: [android-beginners] Layout Tabhost with Header?
Thanks Mark, When I tried nesting inside a layout I got a null pointer exception. I was convinced that the TabHost could not be used within another layout (maybe I was wrong). I figured out a different solution - I replaced the title bar entirely. This is ultimately a better solution for what I was trying to do. j On Sat, Jun 19, 2010 at 10:35 AM, Mark Murphy wrote: > On Sat, Jun 19, 2010 at 10:25 AM, Jason Van Anden > wrote: > > Can someone tell me if its possible to add a header layout over tabs in > > 1.5? If so, how? > > Put the TabHost within another layout. > > > When I attempt to nest a TabHost within another layout - > > things go terribly wrong. > > It is difficult to help you without more details about "terribly wrong". > > -- > Mark Murphy > CommonsWare > mmur...@commonsware.com > http://commonsware.com > > -- > You received this message because you are subscribed to the Google > Groups "Android Beginners" group. > > NEW! Try asking and tagging your question on Stack Overflow at > http://stackoverflow.com/questions/tagged/android > > To unsubscribe from this group, send email to > android-beginners+unsubscr...@googlegroups.com > For more options, visit this group at > http://groups.google.com/group/android-beginners?hl=en > -- You received this message because you are subscribed to the Google Groups "Android Beginners" group. NEW! Try asking and tagging your question on Stack Overflow at http://stackoverflow.com/questions/tagged/android To unsubscribe from this group, send email to android-beginners+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/android-beginners?hl=en
Re: [android-beginners] Layout Tabhost with Header?
On Sat, Jun 19, 2010 at 10:25 AM, Jason Van Anden wrote: > Can someone tell me if its possible to add a header layout over tabs in > 1.5? If so, how? Put the TabHost within another layout. > When I attempt to nest a TabHost within another layout - > things go terribly wrong. It is difficult to help you without more details about "terribly wrong". -- Mark Murphy CommonsWare mmur...@commonsware.com http://commonsware.com -- You received this message because you are subscribed to the Google Groups "Android Beginners" group. NEW! Try asking and tagging your question on Stack Overflow at http://stackoverflow.com/questions/tagged/android To unsubscribe from this group, send email to android-beginners+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/android-beginners?hl=en
[android-beginners] Layout Tabhost with Header?
Hi All, Can someone tell me if its possible to add a header layout over tabs in 1.5? If so, how? When I attempt to nest a TabHost within another layout - things go terribly wrong. Thanks, i++ -- You received this message because you are subscribed to the Google Groups "Android Beginners" group. NEW! Try asking and tagging your question on Stack Overflow at http://stackoverflow.com/questions/tagged/android To unsubscribe from this group, send email to android-beginners+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/android-beginners?hl=en
[android-beginners] LIVE SEX CAMS ! http://www.LiveHappyStrip.com
LIVE SEX CAMS ! http://www.LiveHappyStrip.com -- You received this message because you are subscribed to the Google Groups "Android Beginners" group. NEW! Try asking and tagging your question on Stack Overflow at http://stackoverflow.com/questions/tagged/android To unsubscribe from this group, send email to android-beginners+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/android-beginners?hl=en
Re: [android-beginners] Local TCP/IP server
On Sat, Jun 19, 2010 at 8:31 AM, Alessandro Pellizzari wrote: > before I start banging my head against the wall, I would like to know if > the software I have in mind is technically possible on Android. > > I would like to code a local tcp/ip server, listening on an high port > (say... 8080 or 12345) only on the localhost interface (127.0.0.1). > Is it possibile? Sure. In this area, Android works pretty similar to standard Java. > And also, is it possible to start my "service provider" automatically > whenever some app tries to connect to that port (via a notification, for > example)? There is no equivalent of inetd or xinetd for Android SDK applications, if you are thinking of something like those Linux daemons. > Or must I start my server everytime I need it, manually? For some definition of "manually", yes. The service will need to be running to serve data over your port. Bear in mind that there is probably a better solution for whatever business problem you are trying to solve with a localhost-only TCP server. -- Mark Murphy CommonsWare mmur...@commonsware.com http://commonsware.com -- You received this message because you are subscribed to the Google Groups "Android Beginners" group. NEW! Try asking and tagging your question on Stack Overflow at http://stackoverflow.com/questions/tagged/android To unsubscribe from this group, send email to android-beginners+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/android-beginners?hl=en
[android-beginners] Local TCP/IP server
Hi all, before I start banging my head against the wall, I would like to know if the software I have in mind is technically possible on Android. I would like to code a local tcp/ip server, listening on an high port (say... 8080 or 12345) only on the localhost interface (127.0.0.1). Is it possibile? I found near to nothing on the Internet. And also, is it possible to start my "service provider" automatically whenever some app tries to connect to that port (via a notification, for example)? Or must I start my server everytime I need it, manually? Thank you very much. Bye. -- You received this message because you are subscribed to the Google Groups "Android Beginners" group. NEW! Try asking and tagging your question on Stack Overflow at http://stackoverflow.com/questions/tagged/android To unsubscribe from this group, send email to android-beginners+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/android-beginners?hl=en
