Hi Patrick,
The range operator, `..`, only works in lexer rules, not in parser rules as
you're doing. Capitalize the `letter` rule to make it a lexer rule:
grammar failuretest;
start: letter+;
Letter: 'A' .. 'B'; // or did you mean 'A'..'Z'?
and then try again.
Regards,
Bart.
On Sat, Nov 5, 2011 at 1:41 PM, Patrick Zimmermann <patr...@zakweb.de>wrote:
> Hello,
>
> I'm new to this mailing list, so hello everyone.
>
> I currently try to create a grammar to parse a textual wiki syntax.
> I'm using ANTLR 3.4 and the Java generator.
>
> I've reached a situation where ANTLR creates empty ifs in the generated
> Java
> code and I boiled it down to the following grammar:
>
> grammar failuretest;
> start: letter+;
> letter: 'A' .. 'B';
>
> The resulting Java code contains the following statements:
> ...
> if ( () ) {
> ...
> if ( ) {
> ...
>
> As far as I know this is no legal Java. And the grammar looks fine to me,
> apart
> from that the second rule should probably be a lexer rule.
>
> So could this actually be a bug in antlr?
>
>
> Many thanks in advance,
> Patrick Zimmermann
>
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