Re: [Axapta-Knowledge-Village] Job Query

2006-12-11 Thread kumkum kirodiwal
Thanks Nitesh


kumkum


- Original Message 
From: Nitesh <[EMAIL PROTECTED]>
To: Axapta-Knowledge-Village@yahoogroups.com
Sent: Saturday, 9 December, 2006 2:55:23 PM
Subject: Re: [Axapta-Knowledge-Village] Job Query

Hi Kumkum,
>From the following code u can call another job...

static void runJob(Args _args)
{
TreeNode tr;
XInfo xInfo = new xInfo();
;
tr = xInfo.rootNode( );
tr = treeNode::findNode( "jobs").AOTfindC hild("Job2" ); //job2 is the Name
of the jobs which u want to call
tr.AOTrun();
}

Regards
Nitesh
On 12/8/06, kumkum kirodiwal  wrote:

> Dear All,
>
> I have a query,
>
> Can I call a job from other job.
>
> Regards
> kumkum
>
>
>  _ _ _ _ _ _
> Yahoo! India Answers: Share what you know. Learn something new
> http://in.answers. yahoo.com/
>
> [Non-text portions of this message have been removed]
>
> 
>

[Non-text portions of this message have been removed]






__
Yahoo! India Answers: Share what you know. Learn something new
http://in.answers.yahoo.com/

[Non-text portions of this message have been removed]



Re: [Axapta-Knowledge-Village] Job Query

2006-12-09 Thread Nitesh
Hi Kumkum,
>From the following code u can call another job...

static void runJob(Args _args)
{
TreeNode tr;
XInfo xInfo = new xInfo();
;
tr = xInfo.rootNode();
tr = treeNode::findNode("jobs").AOTfindChild("Job2"); //job2 is the Name
of the jobs which u want to call
tr.AOTrun();
   }

Regards
Nitesh
On 12/8/06, kumkum kirodiwal <[EMAIL PROTECTED]> wrote:

>   Dear All,
>
> I have a query,
>
> Can I call a job from other job.
>
> Regards
> kumkum
>
>
> __
> Yahoo! India Answers: Share what you know. Learn something new
> http://in.answers.yahoo.com/
>
> [Non-text portions of this message have been removed]
>
> 
>


[Non-text portions of this message have been removed]



[Axapta-Knowledge-Village] Job Query

2006-12-08 Thread kumkum kirodiwal
Dear All,

I have a query,

Can I call  a job from other job.

Regards
kumkum



__
Yahoo! India Answers: Share what you know. Learn something new
http://in.answers.yahoo.com/

[Non-text portions of this message have been removed]