Re: Help with Deserialization of complex object with Java Webservice
Probably you have to write a metod in your client to deserialize that
object, and you need to do your class Alert implementing serializable.
ES: public class Alert implements serializable{
attributes...
public Allert(){}
}
Remember you have to do a class with an empty constructor.
Then befor you use the metod Invoke you ha to do this:
QName qnameAlert = new QName(urn:nameWebService, Alert);
Class classeAlert = Alert.class;
call.registerTypeMapping(classeAlert, qnameAlert,
BeanSerializerFactory.class,
BeanDeserializerFactory.class);
BeanSerializer/DeserializerFactory.class make for you serialization and
deserialization.
Bye.
Il giorno mar, 28/07/2009 alle 16.47 -0700, guitarro17 ha scritto:
Let me explain.
I have this object:
public class Alert {
private String name;
private String approximateStartDate;
private String startDate;
private String stopDate;
...
}
And in my webservice, I have this method:
public Alert[] getAlerts() throws Exception{
VectorAlert vetorAlerts = new VectorAlert();
vetorAlerts = leitor.readAlerts();
Alert[] Alerts = new Alert[vetorAlerts.size()];
for(int i=0; ivetorAlerts.size(); i++){
Alerts[i]=vetorAlerts.get(i);
}
return Alerts;
}
But When I'm trying to access this with J2SE, just like this:
Call call = (Call) new Service().createCall();
call.setTargetEndpointAddress(local);
call.setOperationName(getAlerts);
Object[] param = null;
Alert alerts[] = (Alert[])call.invoke(param);
I'm getting this error:
Unable to find required classes (javax.activation.DataHandler and
javax.mail.internet.MimeMultipart). Attachment support is disabled.
- Exception:
org.xml.sax.SAXException: SimpleDeserializer encountered a child element,
which is NOT expected, in something it was trying to deserialize.
at
org.apache.axis.encoding.ser.SimpleDeserializer.onStartChild(SimpleDeserializer.java:145)
...
I have no idea what I need to do to solve this problem =(
Re: Help with Deserialization of complex object with Java Webservice
Sorry, i don't know.
Il giorno mer, 29/07/2009 alle 06.07 -0700, guitarro17 ha scritto:
Thank you!
But, in J2ME, What I need to do? Same?
In my client I have this:
public void testWebService() throws Exception {
SoapSerializationEnvelope envelope = new
SoapSerializationEnvelope(SoapEnvelope.VER11);
SoapObject soapObject = new SoapObject(url,getAlerts);
envelope.addMapping(url, Alert, new Alert().getClass());
envelope.setOutputSoapObject(soapObject);
HttpTransport transport = new HttpTransport(url);
transport.call(getAlerts,envelope);
//HERE IS THE PROBLEM...
Vector ret = (Vector)envelope.getResponse();
}
WARN Please initialize the log4j system properly
Hi, i've used axis2 wsdl2java tool to create a client from an application i've deployed. I get this error when i try to run the client: log4j:WARN No appenders could be found for logger (org.apache.axis2.description.AxisService). log4j:WARN Please initialize the log4j system properly. What should i do? Thanks a lot and sorry for my english.
Re: WARN Please initialize the log4j system properly
Il giorno ven, 24/07/2009 alle 15.26 -0700, Shasta Willson ha scritto: On Fri, Jul 24, 2009 at 3:20 PM, Carmelocrmsa...@gmail.com wrote: Hi, i've used axis2 wsdl2java tool to create a client from an application i've deployed. I get this error when i try to run the client: log4j:WARN No appenders could be found for logger (org.apache.axis2.description.AxisService). log4j:WARN Please initialize the log4j system properly. What should i do? Thanks a lot and sorry for my english. The long story : http://logging.apache.org/log4j/1.2/manual.html The short story : http://www.mobilefish.com/developer/log4j/log4j.html Step 10 is about configuring log4j.properties, which is likely what you need to do. - Shasta Thank you so much! It is easy and it works! Bye. Carmelo.
