Re: access files inside AAR - File Path! not Resource / URL

2008-12-12 Thread Seem 

I still have problems to access my resources.

Is it necessary to add the additional folders inside my .aar explicitely to
the classpath?



Seem wrote:
 
 Just to clarify, I have a similar problem like this:
 http://www.nabble.com/Accessing-a-file-in-AAR-to16787898.html#a16898376
 
 but I do not understand his mentioned solution.
 
 Should I use the getResourceAsStream(), create a temporary file from the
 inputstream, get the file path und use it with my 3rd party methods?
 
 
 
 
 
 Deepal Jayasinghe wrote:
 
 
 Yes, I tried this, but there is still the problem, that I need a file
 Path
 and not a resource/URL to invoke File file = new File(file Path) for
 further
 operations.

 and this was not a solution to get the correct Path:
 getClass().getClassLoader().getResource(conf/config.xml).getPath();


 if(!file.exists()) {...system.out
   
 I do not think you can do something like this,
 What you can do is get the input stream and read it and do your job.
 
 If you get not-null value for getResource(), then that is mean you can
 access your resource.
 
 Thank you!
 Deepal
 brought me this:
 cannot find file
 file:/C:/Programme/Tomcat/work/Catalina/localhost/axis2/_axis2/axis230466Service.aar!/conf/config.xml





 Deepal Jayasinghe wrote:
   
 Have a look at following article, which provides a way to access your
 resources inside the service archive file.

 http://wso2.org/library/259

 Deepal
 
 I have an unsolved problem accessing a file which is inside my
 aar-folder.
 Unfortunately I need a file Path for a 3rd Party function and not a
 Resource
 or an URL. Do you have any advices how to get the right path to the
 file?

 My folder structure is like this

 /META-INF
 /bin (Service classes)
 /conf/config.xml



   
   
 -- 
 Thank you!


 http://blogs.deepal.org



 

   
 
 -- 
 Thank you!
 
 
 http://blogs.deepal.org
 
 
 
 
 

-- 
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Sent from the Axis - User mailing list archive at Nabble.com.

access files inside AAR - File Path! not Resource / URL

2008-12-11 Thread Seem 

I have an unsolved problem accessing a file which is inside my aar-folder.
Unfortunately I need a file Path for a 3rd Party function and not a Resource
or an URL. Do you have any advices how to get the right path to the file?

My folder structure is like this

/META-INF
/bin (Service classes)
/conf/config.xml



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View this message in context: 
http://www.nabble.com/access-files-inside-AAR---File-Path%21-not-Resource---URL-tp20958031p20958031.html
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Re: access files inside AAR - File Path! not Resource / URL

2008-12-11 Thread Deepal Jayasinghe 
Have a look at following article, which provides a way to access your
resources inside the service archive file.

http://wso2.org/library/259

Deepal
 I have an unsolved problem accessing a file which is inside my aar-folder.
 Unfortunately I need a file Path for a 3rd Party function and not a Resource
 or an URL. Do you have any advices how to get the right path to the file?

 My folder structure is like this

 /META-INF
 /bin (Service classes)
 /conf/config.xml



   

-- 
Thank you!


http://blogs.deepal.org

Re: access files inside AAR - File Path! not Resource / URL

2008-12-11 Thread Seem 

Yes, I tried this, but there is still the problem, that I need a file Path
and not a resource/URL to invoke File file = new File(file Path) for further
operations.

and this was not a solution to get the correct Path:
getClass().getClassLoader().getResource(conf/config.xml).getPath();


if(!file.exists()) {...system.out

brought me this:
cannot find file
file:/C:/Programme/Tomcat/work/Catalina/localhost/axis2/_axis2/axis230466Service.aar!/conf/config.xml





Deepal Jayasinghe wrote:
 
 Have a look at following article, which provides a way to access your
 resources inside the service archive file.
 
 http://wso2.org/library/259
 
 Deepal
 I have an unsolved problem accessing a file which is inside my
 aar-folder.
 Unfortunately I need a file Path for a 3rd Party function and not a
 Resource
 or an URL. Do you have any advices how to get the right path to the file?

 My folder structure is like this

 /META-INF
 /bin (Service classes)
 /conf/config.xml



   
 
 -- 
 Thank you!
 
 
 http://blogs.deepal.org
 
 
 

-- 
View this message in context: 
http://www.nabble.com/access-files-inside-AAR---File-Path%21-not-Resource---URL-tp20958031p20958833.html
Sent from the Axis - User mailing list archive at Nabble.com.

Re: access files inside AAR - File Path! not Resource / URL

2008-12-11 Thread Deepal Jayasinghe 

 Yes, I tried this, but there is still the problem, that I need a file Path
 and not a resource/URL to invoke File file = new File(file Path) for further
 operations.

 and this was not a solution to get the correct Path:
 getClass().getClassLoader().getResource(conf/config.xml).getPath();


 if(!file.exists()) {...system.out
   
I do not think you can do something like this,
What you can do is get the input stream and read it and do your job.

If you get not-null value for getResource(), then that is mean you can
access your resource.

Thank you!
Deepal
 brought me this:
 cannot find file
 file:/C:/Programme/Tomcat/work/Catalina/localhost/axis2/_axis2/axis230466Service.aar!/conf/config.xml





 Deepal Jayasinghe wrote:
   
 Have a look at following article, which provides a way to access your
 resources inside the service archive file.

 http://wso2.org/library/259

 Deepal
 
 I have an unsolved problem accessing a file which is inside my
 aar-folder.
 Unfortunately I need a file Path for a 3rd Party function and not a
 Resource
 or an URL. Do you have any advices how to get the right path to the file?

 My folder structure is like this

 /META-INF
 /bin (Service classes)
 /conf/config.xml



   
   
 -- 
 Thank you!


 http://blogs.deepal.org



 

   

-- 
Thank you!


http://blogs.deepal.org

Re: access files inside AAR - File Path! not Resource / URL

2008-12-11 Thread Seem 

Just to clarify, I have a similar problem like this:
http://www.nabble.com/Accessing-a-file-in-AAR-to16787898.html#a16898376

but I do not understand his mentioned solution.

Should I use the getResourceAsStream(), create a temporary file from the
inputstream, get the file path und use it with my 3rd party methods?





Deepal Jayasinghe wrote:
 
 
 Yes, I tried this, but there is still the problem, that I need a file
 Path
 and not a resource/URL to invoke File file = new File(file Path) for
 further
 operations.

 and this was not a solution to get the correct Path:
 getClass().getClassLoader().getResource(conf/config.xml).getPath();


 if(!file.exists()) {...system.out
   
 I do not think you can do something like this,
 What you can do is get the input stream and read it and do your job.
 
 If you get not-null value for getResource(), then that is mean you can
 access your resource.
 
 Thank you!
 Deepal
 brought me this:
 cannot find file
 file:/C:/Programme/Tomcat/work/Catalina/localhost/axis2/_axis2/axis230466Service.aar!/conf/config.xml





 Deepal Jayasinghe wrote:
   
 Have a look at following article, which provides a way to access your
 resources inside the service archive file.

 http://wso2.org/library/259

 Deepal
 
 I have an unsolved problem accessing a file which is inside my
 aar-folder.
 Unfortunately I need a file Path for a 3rd Party function and not a
 Resource
 or an URL. Do you have any advices how to get the right path to the
 file?

 My folder structure is like this

 /META-INF
 /bin (Service classes)
 /conf/config.xml



   
   
 -- 
 Thank you!


 http://blogs.deepal.org



 

   
 
 -- 
 Thank you!
 
 
 http://blogs.deepal.org
 
 
 

-- 
View this message in context: 
http://www.nabble.com/access-files-inside-AAR---File-Path%21-not-Resource---URL-tp20958031p20959233.html
Sent from the Axis - User mailing list archive at Nabble.com.