[beagleboard] Re: detecting interrupt on GPIO in kernel module

2018-02-11 Thread rakshithp . 46

use of gpio_int_name 
On Tuesday, 26 August 2014 19:38:01 UTC+5:30, Siddarth Sharma wrote:
>
> I am toggling the input into a GPIO line on my BeagleBone from high to low 
> every 500 ms using an Atmel uC. I have registered a handler for this in my 
> Linux Kernel Module, but the handler is not being called for some reason.
>
> My module code is -
>
> #define GPIO 54
> #define GPIO_INT_NAME  "gpio_int"
>
> #define GPIO_HIGH gpio_get_value(GPIO)
> #define GPIO_LOW (gpio_get_value(GPIO) == 0)
> short int irq_any_gpio= 0;
> int count =0;
>
> enum { falling, rising } type; 
> static irqreturn_t r_irq_handler(int irq, void *dev_id)
>  {
>   count++;
> printk(KERN_DEBUG "interrupt received (irq: %d)\n", irq);
> if (irq == gpio_to_irq(GPIO)) 
> {
>
> type = GPIO_LOW ? falling : rising;
>
> if(type == falling)
> {
> printk("gpio pin is low\n");
> }
> else
> printk("gpio pin is high\n");
>
> }
>
> return IRQ_HANDLED;
> }
>
>
> void r_int_config(void) {
>
>if (gpio_request(GPIO, GPIO_INT_NAME )) 
>{
>   printk("GPIO request failure: %s\n", GPIO_INT_NAME );
>   return;
>}
>
>if ( (irq_any_gpio = gpio_to_irq(GPIO)) < 0 ) {
>   printk("GPIO to IRQ mapping failure %s\n",GPIO_INT_NAME );
>   return;
>}
>
>printk(KERN_NOTICE "Mapped int %d\n", irq_any_gpio);
>
>if (request_irq(irq_any_gpio,(irq_handler_t ) r_irq_handler, 
> IRQF_TRIGGER_HIGH, GPIO_INT_NAME, NULL)) 
>{
>   printk("Irq Request failure\n");
>   return;
>}
>
>return;
> }
>
> void r_int_release(void) {
>
>free_irq(gpio_to_irq(GPIO), NULL);
> gpio_free(GPIO);;
>return;
> }
>
> int init_module(void)
> {
> printk("<1>Hello World\n"); 
> r_int_config();
> return 0;
> }
>
> On calling insmod interrupt_test.ko, i get the following message
>
> [   76.594543] Hello World
>   
> [   76.597137] Mapped int 214  
>
> But now when I start toggling the input into this gpio pin, the interrupt 
> handler doesn't get called and the message - "interrupt received" is not 
> being displayed.
>
> How do I solve this ? What's causing the problem?
>

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Re: [beagleboard] Re: detecting interrupt on GPIO in kernel module

2014-09-09 Thread neo
Hi Kavita

A generic question regarding interrupts.
If i register an interrupt using request_threaded_irq() or request_irq() 
will that be listed in /proc/interrupts ?

On Tuesday, September 9, 2014 11:17:19 AM UTC+5:30, kavitha wrote:


 Does cat /proc/interrupts give show anything for 214.

 Check whether It is going to architecture specific impelemtation of 
 gpio_to_irq


 On Tue, Sep 9, 2014 at 8:26 AM, neo star prag@gmail.com javascript:
  wrote:

 Hi 

 I see that some function definitions are missing in your code. Can you 
 share those as well, so that i too can try and figure out the problem.
 Especially the functions like gpio_to_irq() ...
 Thanks.


 On Tuesday, August 26, 2014 7:38:01 PM UTC+5:30, Siddarth Sharma wrote:

 I am toggling the input into a GPIO line on my BeagleBone from high to 
 low every 500 ms using an Atmel uC. I have registered a handler for this in 
 my Linux Kernel Module, but the handler is not being called for some reason.

 My module code is -

 #define GPIO 54
 #define GPIO_INT_NAME  gpio_int

 #define GPIO_HIGH gpio_get_value(GPIO)
 #define GPIO_LOW (gpio_get_value(GPIO) == 0)
 short int irq_any_gpio= 0;
 int count =0;

 enum { falling, rising } type; 
 static irqreturn_t r_irq_handler(int irq, void *dev_id)
  {
   count++;
 printk(KERN_DEBUG interrupt received (irq: %d)\n, irq);
 if (irq == gpio_to_irq(GPIO)) 
 {

 type = GPIO_LOW ? falling : rising;

 if(type == falling)
 {
 printk(gpio pin is low\n);
 }
 else
 printk(gpio pin is high\n);

 }

 return IRQ_HANDLED;
 }


 void r_int_config(void) {

if (gpio_request(GPIO, GPIO_INT_NAME )) 
{
   printk(GPIO request failure: %s\n, GPIO_INT_NAME );
   return;
}

if ( (irq_any_gpio = gpio_to_irq(GPIO))  0 ) {
   printk(GPIO to IRQ mapping failure %s\n,GPIO_INT_NAME );
   return;
}

printk(KERN_NOTICE Mapped int %d\n, irq_any_gpio);

if (request_irq(irq_any_gpio,(irq_handler_t ) r_irq_handler, 
 IRQF_TRIGGER_HIGH, GPIO_INT_NAME, NULL)) 
{
   printk(Irq Request failure\n);
   return;
}

return;
 }

 void r_int_release(void) {

free_irq(gpio_to_irq(GPIO), NULL);
 gpio_free(GPIO);;
return;
 }

 int init_module(void)
 {
 printk(1Hello World\n); 
 r_int_config();
 return 0;
 }

 On calling insmod interrupt_test.ko, i get the following message

 [   76.594543] Hello World  
 
 [   76.597137] Mapped int 214  

 But now when I start toggling the input into this gpio pin, the 
 interrupt handler doesn't get called and the message - interrupt received 
 is not being displayed.

 How do I solve this ? What's causing the problem?

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Re: [beagleboard] Re: detecting interrupt on GPIO in kernel module

2014-09-09 Thread kavitha bk
Yes it does show in cat /proc/interrupts
It doesnot matter you use request_threaded_irq or request_irq

request_irq(unsigned int irq, irq_handler_t handler, unsigned long flags,
const char *name, void *dev)
Here the handler will be run in interrupt context

and

request_threaded_irq(unsigned int irq, irq_handler_t handler,
 irq_handler_t thread_fn,
 unsigned long flags, const char *name, void *dev);


In threaded IRQ
 irq_handler_t handle - Interrupt context
  irq_handler_t thread_fn- Process context
This is the only difference.


Thanks
Kavitha





On Wed, Sep 10, 2014 at 8:03 AM, neo prag.in...@gmail.com wrote:

 Hi Kavita

 A generic question regarding interrupts.
 If i register an interrupt using request_threaded_irq() or request_irq()
 will that be listed in /proc/interrupts ?

 On Tuesday, September 9, 2014 11:17:19 AM UTC+5:30, kavitha wrote:


 Does cat /proc/interrupts give show anything for 214.

 Check whether It is going to architecture specific impelemtation of 
 gpio_to_irq


 On Tue, Sep 9, 2014 at 8:26 AM, neo star prag@gmail.com wrote:

 Hi

 I see that some function definitions are missing in your code. Can you
 share those as well, so that i too can try and figure out the problem.
 Especially the functions like gpio_to_irq() ...
 Thanks.


 On Tuesday, August 26, 2014 7:38:01 PM UTC+5:30, Siddarth Sharma wrote:

 I am toggling the input into a GPIO line on my BeagleBone from high to
 low every 500 ms using an Atmel uC. I have registered a handler for this in
 my Linux Kernel Module, but the handler is not being called for some 
 reason.

 My module code is -

 #define GPIO 54
 #define GPIO_INT_NAME  gpio_int

 #define GPIO_HIGH gpio_get_value(GPIO)
 #define GPIO_LOW (gpio_get_value(GPIO) == 0)
 short int irq_any_gpio= 0;
 int count =0;

 enum { falling, rising } type;
 static irqreturn_t r_irq_handler(int irq, void *dev_id)
  {
   count++;
 printk(KERN_DEBUG interrupt received (irq: %d)\n, irq);
 if (irq == gpio_to_irq(GPIO))
 {

 type = GPIO_LOW ? falling : rising;

 if(type == falling)
 {
 printk(gpio pin is low\n);
 }
 else
 printk(gpio pin is high\n);

 }

 return IRQ_HANDLED;
 }


 void r_int_config(void) {

if (gpio_request(GPIO, GPIO_INT_NAME ))
{
   printk(GPIO request failure: %s\n, GPIO_INT_NAME );
   return;
}

if ( (irq_any_gpio = gpio_to_irq(GPIO))  0 ) {
   printk(GPIO to IRQ mapping failure %s\n,GPIO_INT_NAME );
   return;
}

printk(KERN_NOTICE Mapped int %d\n, irq_any_gpio);

if (request_irq(irq_any_gpio,(irq_handler_t ) r_irq_handler, 
 IRQF_TRIGGER_HIGH, GPIO_INT_NAME, NULL))
{
   printk(Irq Request failure\n);
   return;
}

return;
 }

 void r_int_release(void) {

free_irq(gpio_to_irq(GPIO), NULL);
 gpio_free(GPIO);;
return;
 }

 int init_module(void)
 {
 printk(1Hello World\n);
 r_int_config();
 return 0;
 }

 On calling insmod interrupt_test.ko, i get the following message

 [   76.594543] Hello World
 [   76.597137] Mapped int 214

 But now when I start toggling the input into this gpio pin, the
 interrupt handler doesn't get called and the message - interrupt received
 is not being displayed.

 How do I solve this ? What's causing the problem?

  --
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 ---
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Re: [beagleboard] Re: detecting interrupt on GPIO in kernel module

2014-09-09 Thread neo
Hi Kavita

Thanks for clarifying 

On Wednesday, September 10, 2014 10:00:06 AM UTC+5:30, kavitha wrote:

 Yes it does show in cat /proc/interrupts
 It doesnot matter you use request_threaded_irq or request_irq

 request_irq(unsigned int irq, irq_handler_t handler, unsigned long flags,
 const char *name, void *dev)
 Here the handler will be run in interrupt context

 and

 request_threaded_irq(unsigned int irq, irq_handler_t handler,
  irq_handler_t thread_fn,
  unsigned long flags, const char *name, void *dev);


 In threaded IRQ
  irq_handler_t handle - Interrupt context
   irq_handler_t thread_fn- Process context
 This is the only difference.


 Thanks
 Kavitha





 On Wed, Sep 10, 2014 at 8:03 AM, neo prag@gmail.com javascript: 
 wrote:

 Hi Kavita

 A generic question regarding interrupts.
 If i register an interrupt using request_threaded_irq() or request_irq() 
 will that be listed in /proc/interrupts ?

 On Tuesday, September 9, 2014 11:17:19 AM UTC+5:30, kavitha wrote:


 Does cat /proc/interrupts give show anything for 214.

 Check whether It is going to architecture specific impelemtation of 
 gpio_to_irq


 On Tue, Sep 9, 2014 at 8:26 AM, neo star prag@gmail.com wrote:

 Hi 

 I see that some function definitions are missing in your code. Can you 
 share those as well, so that i too can try and figure out the problem.
 Especially the functions like gpio_to_irq() ...
 Thanks.


 On Tuesday, August 26, 2014 7:38:01 PM UTC+5:30, Siddarth Sharma wrote:

 I am toggling the input into a GPIO line on my BeagleBone from high to 
 low every 500 ms using an Atmel uC. I have registered a handler for this 
 in 
 my Linux Kernel Module, but the handler is not being called for some 
 reason.

 My module code is -

 #define GPIO 54
 #define GPIO_INT_NAME  gpio_int

 #define GPIO_HIGH gpio_get_value(GPIO)
 #define GPIO_LOW (gpio_get_value(GPIO) == 0)
 short int irq_any_gpio= 0;
 int count =0;

 enum { falling, rising } type; 
 static irqreturn_t r_irq_handler(int irq, void *dev_id)
  {
   count++;
 printk(KERN_DEBUG interrupt received (irq: %d)\n, irq);
 if (irq == gpio_to_irq(GPIO)) 
 {

 type = GPIO_LOW ? falling : rising;

 if(type == falling)
 {
 printk(gpio pin is low\n);
 }
 else
 printk(gpio pin is high\n);

 }

 return IRQ_HANDLED;
 }


 void r_int_config(void) {

if (gpio_request(GPIO, GPIO_INT_NAME )) 
{
   printk(GPIO request failure: %s\n, GPIO_INT_NAME );
   return;
}

if ( (irq_any_gpio = gpio_to_irq(GPIO))  0 ) {
   printk(GPIO to IRQ mapping failure %s\n,GPIO_INT_NAME );
   return;
}

printk(KERN_NOTICE Mapped int %d\n, irq_any_gpio);

if (request_irq(irq_any_gpio,(irq_handler_t ) r_irq_handler, 
 IRQF_TRIGGER_HIGH, GPIO_INT_NAME, NULL)) 
{
   printk(Irq Request failure\n);
   return;
}

return;
 }

 void r_int_release(void) {

free_irq(gpio_to_irq(GPIO), NULL);
 gpio_free(GPIO);;
return;
 }

 int init_module(void)
 {
 printk(1Hello World\n); 
 r_int_config();
 return 0;
 }

 On calling insmod interrupt_test.ko, i get the following message

 [   76.594543] Hello World
   
 [   76.597137] Mapped int 214  

 But now when I start toggling the input into this gpio pin, the 
 interrupt handler doesn't get called and the message - interrupt 
 received 
 is not being displayed.

 How do I solve this ? What's causing the problem?

  -- 
 For more options, visit http://beagleboard.org/discuss
 --- 
 You received this message because you are subscribed to the Google 
 Groups BeagleBoard group.
 To unsubscribe from this group and stop receiving emails from it, send 
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[beagleboard] Re: detecting interrupt on GPIO in kernel module

2014-09-08 Thread neo star
Hi 

I see that some function definitions are missing in your code. Can you 
share those as well, so that i too can try and figure out the problem.
Especially the functions like gpio_to_irq() ...
Thanks.

On Tuesday, August 26, 2014 7:38:01 PM UTC+5:30, Siddarth Sharma wrote:

 I am toggling the input into a GPIO line on my BeagleBone from high to low 
 every 500 ms using an Atmel uC. I have registered a handler for this in my 
 Linux Kernel Module, but the handler is not being called for some reason.

 My module code is -

 #define GPIO 54
 #define GPIO_INT_NAME  gpio_int

 #define GPIO_HIGH gpio_get_value(GPIO)
 #define GPIO_LOW (gpio_get_value(GPIO) == 0)
 short int irq_any_gpio= 0;
 int count =0;

 enum { falling, rising } type; 
 static irqreturn_t r_irq_handler(int irq, void *dev_id)
  {
   count++;
 printk(KERN_DEBUG interrupt received (irq: %d)\n, irq);
 if (irq == gpio_to_irq(GPIO)) 
 {

 type = GPIO_LOW ? falling : rising;

 if(type == falling)
 {
 printk(gpio pin is low\n);
 }
 else
 printk(gpio pin is high\n);

 }

 return IRQ_HANDLED;
 }


 void r_int_config(void) {

if (gpio_request(GPIO, GPIO_INT_NAME )) 
{
   printk(GPIO request failure: %s\n, GPIO_INT_NAME );
   return;
}

if ( (irq_any_gpio = gpio_to_irq(GPIO))  0 ) {
   printk(GPIO to IRQ mapping failure %s\n,GPIO_INT_NAME );
   return;
}

printk(KERN_NOTICE Mapped int %d\n, irq_any_gpio);

if (request_irq(irq_any_gpio,(irq_handler_t ) r_irq_handler, 
 IRQF_TRIGGER_HIGH, GPIO_INT_NAME, NULL)) 
{
   printk(Irq Request failure\n);
   return;
}

return;
 }

 void r_int_release(void) {

free_irq(gpio_to_irq(GPIO), NULL);
 gpio_free(GPIO);;
return;
 }

 int init_module(void)
 {
 printk(1Hello World\n); 
 r_int_config();
 return 0;
 }

 On calling insmod interrupt_test.ko, i get the following message

 [   76.594543] Hello World
   
 [   76.597137] Mapped int 214  

 But now when I start toggling the input into this gpio pin, the interrupt 
 handler doesn't get called and the message - interrupt received is not 
 being displayed.

 How do I solve this ? What's causing the problem?


-- 
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Re: [beagleboard] Re: detecting interrupt on GPIO in kernel module

2014-09-08 Thread kavitha bk
Does cat /proc/interrupts give show anything for 214.

Check whether It is going to architecture specific impelemtation of gpio_to_irq


On Tue, Sep 9, 2014 at 8:26 AM, neo star prag.in...@gmail.com wrote:

 Hi

 I see that some function definitions are missing in your code. Can you
 share those as well, so that i too can try and figure out the problem.
 Especially the functions like gpio_to_irq() ...
 Thanks.


 On Tuesday, August 26, 2014 7:38:01 PM UTC+5:30, Siddarth Sharma wrote:

 I am toggling the input into a GPIO line on my BeagleBone from high to
 low every 500 ms using an Atmel uC. I have registered a handler for this in
 my Linux Kernel Module, but the handler is not being called for some reason.

 My module code is -

 #define GPIO 54
 #define GPIO_INT_NAME  gpio_int

 #define GPIO_HIGH gpio_get_value(GPIO)
 #define GPIO_LOW (gpio_get_value(GPIO) == 0)
 short int irq_any_gpio= 0;
 int count =0;

 enum { falling, rising } type;
 static irqreturn_t r_irq_handler(int irq, void *dev_id)
  {
   count++;
 printk(KERN_DEBUG interrupt received (irq: %d)\n, irq);
 if (irq == gpio_to_irq(GPIO))
 {

 type = GPIO_LOW ? falling : rising;

 if(type == falling)
 {
 printk(gpio pin is low\n);
 }
 else
 printk(gpio pin is high\n);

 }

 return IRQ_HANDLED;
 }


 void r_int_config(void) {

if (gpio_request(GPIO, GPIO_INT_NAME ))
{
   printk(GPIO request failure: %s\n, GPIO_INT_NAME );
   return;
}

if ( (irq_any_gpio = gpio_to_irq(GPIO))  0 ) {
   printk(GPIO to IRQ mapping failure %s\n,GPIO_INT_NAME );
   return;
}

printk(KERN_NOTICE Mapped int %d\n, irq_any_gpio);

if (request_irq(irq_any_gpio,(irq_handler_t ) r_irq_handler, 
 IRQF_TRIGGER_HIGH, GPIO_INT_NAME, NULL))
{
   printk(Irq Request failure\n);
   return;
}

return;
 }

 void r_int_release(void) {

free_irq(gpio_to_irq(GPIO), NULL);
 gpio_free(GPIO);;
return;
 }

 int init_module(void)
 {
 printk(1Hello World\n);
 r_int_config();
 return 0;
 }

 On calling insmod interrupt_test.ko, i get the following message

 [   76.594543] Hello World
 [   76.597137] Mapped int 214

 But now when I start toggling the input into this gpio pin, the interrupt
 handler doesn't get called and the message - interrupt received is not
 being displayed.

 How do I solve this ? What's causing the problem?

  --
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 ---
 You received this message because you are subscribed to the Google Groups
 BeagleBoard group.
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[beagleboard] Re: detecting interrupt on GPIO in kernel module

2014-08-26 Thread Siddarth Sharma
Does the problem have something to do with dev id paramter in the interrupt 
handler?

On Tuesday, August 26, 2014 3:08:01 PM UTC+1, Siddarth Sharma wrote:

 I am toggling the input into a GPIO line on my BeagleBone from high to low 
 every 500 ms using an Atmel uC. I have registered a handler for this in my 
 Linux Kernel Module, but the handler is not being called for some reason.

 My module code is -

 #define GPIO 54
 #define GPIO_INT_NAME  gpio_int

 #define GPIO_HIGH gpio_get_value(GPIO)
 #define GPIO_LOW (gpio_get_value(GPIO) == 0)
 short int irq_any_gpio= 0;
 int count =0;

 enum { falling, rising } type; 
 static irqreturn_t r_irq_handler(int irq, void *dev_id)
  {
   count++;
 printk(KERN_DEBUG interrupt received (irq: %d)\n, irq);
 if (irq == gpio_to_irq(GPIO)) 
 {

 type = GPIO_LOW ? falling : rising;

 if(type == falling)
 {
 printk(gpio pin is low\n);
 }
 else
 printk(gpio pin is high\n);

 }

 return IRQ_HANDLED;
 }


 void r_int_config(void) {

if (gpio_request(GPIO, GPIO_INT_NAME )) 
{
   printk(GPIO request failure: %s\n, GPIO_INT_NAME );
   return;
}

if ( (irq_any_gpio = gpio_to_irq(GPIO))  0 ) {
   printk(GPIO to IRQ mapping failure %s\n,GPIO_INT_NAME );
   return;
}

printk(KERN_NOTICE Mapped int %d\n, irq_any_gpio);

if (request_irq(irq_any_gpio,(irq_handler_t ) r_irq_handler, 
 IRQF_TRIGGER_HIGH, GPIO_INT_NAME, NULL)) 
{
   printk(Irq Request failure\n);
   return;
}

return;
 }

 void r_int_release(void) {

free_irq(gpio_to_irq(GPIO), NULL);
 gpio_free(GPIO);;
return;
 }

 int init_module(void)
 {
 printk(1Hello World\n); 
 r_int_config();
 return 0;
 }

 On calling insmod interrupt_test.ko, i get the following message

 [   76.594543] Hello World
   
 [   76.597137] Mapped int 214  

 But now when I start toggling the input into this gpio pin, the interrupt 
 handler doesn't get called and the message - interrupt received is not 
 being displayed.

 How do I solve this ? What's causing the problem?


-- 
For more options, visit http://beagleboard.org/discuss
--- 
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