Re: Reg:Regular expression
>> I need to replace \/user\/cce\/g_tool with the variable $temp where
>> $temp=\/user\ /gowri\/rem2
$string =~ s{\\/user\\/cce\\/g_tool}{$temp}
HTH,
Thanks,
--Emen
AW: if statement being ignored
Brian wrote:
> could someone please help me with this little problem?
> I am trying to include an if statement part way through printing.
> When the program reaches the line if ($Lang = fr ) { print "
> that line gets ignored and the cgi keeps going to the end.
>
> thanks
> Brian
>
>
>
> #! c:\perl\bin\perl.exe -T
> use warnings;
> #use strict;
You should always "use strict;" unless you know why and when.
As to your if condition, a single "=" is an assignment, not a comparison.
And in any case, you'll want to use the "eq" operator for string comparisons.
Otherwise the comparison will be done numerically (0 == 0) and the code will
execute all of the time.
HTH,
Thomas
--
To unsubscribe, e-mail: beginners-unsubscr...@perl.org
For additional commands, e-mail: beginners-h...@perl.org
http://learn.perl.org/
Reg:Regular expression
Hi all, Please help in writing regular expression for the following scenario I need to replace \/user\/cce\/g_tool with the variable $temp where $temp=\/user\ /gowri\/rem2 Thanks and regards, Gowri DISCLAIMER: --- The contents of this e-mail and any attachment(s) are confidential and intended for the named recipient(s) only. It shall not attach any liability on the originator or HCL or its affiliates. Any views or opinions presented in this email are solely those of the author and may not necessarily reflect the opinions of HCL or its affiliates. Any form of reproduction, dissemination, copying, disclosure, modification, distribution and / or publication of this message without the prior written consent of the author of this e-mail is strictly prohibited. If you have received this email in error please delete it and notify the sender immediately. Before opening any mail and attachments please check them for viruses and defect. --- -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
if statement being ignored
Hi,
could someone please help me with this little problem?
I am trying to include an if statement part way through printing.
When the program reaches the line if ($Lang = fr ) { print "
that line gets ignored and the cgi keeps going to the end.
thanks
Brian
#! c:\perl\bin\perl.exe -T
use warnings;
#use strict;
use CGI qw/:all/;
use CGI::Carp qw/fatalsToBrowser/;
use HTMLTMPL;
my $t = HTMLTMPL->new();
my $q = new CGI;
my $val1 = $q->param('language');
my $val2 = $q->param('year');
#my $submit = $q->param('Submit');
chomp($Lang = $val1);
chomp($Year_in = $val2);
if ($Lang <= 0 ) {$Lang = en;}
{
# bunch of calcs that work perfectly #
}
$t->output( CGI::header );
{
print "
\"http:\/\/www.w3.org\/TR\/xhtml1\/DTD\/xhtml1-transitional.dtd\">
$Year_in<\/title>
SSL decrypt
Hi Camels, I wonder to know if there is a perl module that let me to decrypt ssl traffic (if I have already private key), like ssldump or tshark does. Best regards, LD -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
getSaveFile and warn?
The following bit of code: use Tk; use strict; . . . my $topl = $mw -> Toplevel(-title => 'File Selection'); my $fr1 = $topl -> Frame -> pack; $outfile = $fr1 -> getSaveFile(-filetypes => $types); warn "Over Write?"; open OUTFILE, ">$outfile"; works and pops up a warning when an attempt is made to open an existing file but, of course, also writes the warning to STDERR. I really just want the popup caution but I only get it when the warn statement is included. Should I just redirect the output for STDERR to oblivion or is there a neater way to do this? Tom -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
Re: Match and split on array help with output
John W. Krahn wrote:
p...@highdeck.com wrote:
Hi john,
Hello,
thanks for the prompt reply.
Ok, here's what I'd like it to do.
#!/usr/bin/perl
#
# Build Initial list and put into array.
@serverlist = `/usr/bin/wget -q -O - http://www.amazon.co.uk`;
for ($index = 0; $index <= $#serverlist; $index++) {
#replace http with newline, all .com etc should now be in 3rd
field "/"
$serverlist[$index] =~ s/http/\n/g;
print $serverlist[$index];
}
Now, if I run this as above and pipe it to grep thus
./webprog.pl |grep ://|cut -d"/" -f3
Then I get...
ecx.images-amazon.com
ecx.images-amazon.com
g-ecx.images-amazon.com
g-ecx.images-amazon.com
g-ecx.images-amazon.com
g-ecx.images-amazon.com
www.amazon.com">United States<
www.amazon.de">Germany<
www.amazon.fr">France<
BUT, I want to do it all in perl itself,
use LWP::Simple;
use Regexp::Common;
my @hosts = map m[https?://([^/]+)/], get( 'http://www.amazon.co.uk/' )
=~ /$RE{URI}/g;
print "$_\n" for @hosts;
That *should* be:
use LWP::Simple;
use Regexp::Common;
my @hosts = map m[https?://([^/]+)], get( 'http://www.amazon.co.uk/' )
=~ /$RE{URI}/g;
print "$_\n" for @hosts;
John
--
Those people who think they know everything are a great
annoyance to those of us who do.-- Isaac Asimov
--
To unsubscribe, e-mail: beginners-unsubscr...@perl.org
For additional commands, e-mail: beginners-h...@perl.org
http://learn.perl.org/
Re: reading files c vs perl
On Tue, Apr 14, 2009 at 11:49, Rick wrote:
> is it true that perl will be just as fast as c for reading files ?
>
> for example
>
> will below be as fast as if it were written in c?
> I said this because on random posts, I see that perl is optimized to work w/
> text files and it should be as fast as perl
>
> open FILE, $file or die "bad filename: $!";
> while (my $line = ) {
> #do something w $line
> }
snip
Why not test it?
With the file already in the filesystem's read-ahead buffer
cow...@amans:~$ time cat /usr/share/dict/words | perl wc.pl
234936
real0m0.083s
user0m0.062s
sys 0m0.015s
cow...@amans:~$ time cat /usr/share/dict/words | ./wc
234936
real0m0.028s
user0m0.013s
sys 0m0.012s
You can decide whether the .04 seconds is worth the extra time it
takes to write the C code.
#include
int main (int argc, char** argv) {
char buf[4096];
size_t i;
size_t bytes;
size_t count = 0;
while (bytes = fread(buf, 1, 4096, stdin))
for (i = 0; i < bytes; i++)
if (buf[i] == '\n')
count++;
printf("%d\n", count);
return 0;
}
#!/usr/bin/perl
use strict;
use warnings;
my $count = 0;
$/ = \4096;
while (<>) {
$count += tr/\n//;
}
print "$count\n";
--
Chas. Owens
wonkden.net
The most important skill a programmer can have is the ability to read.
--
To unsubscribe, e-mail: beginners-unsubscr...@perl.org
For additional commands, e-mail: beginners-h...@perl.org
http://learn.perl.org/
Re: Match and split on array help with output
p...@highdeck.com wrote:
Hi john,
Hello,
thanks for the prompt reply.
Ok, here's what I'd like it to do.
#!/usr/bin/perl
#
# Build Initial list and put into array.
@serverlist = `/usr/bin/wget -q -O - http://www.amazon.co.uk`;
for ($index = 0; $index <= $#serverlist; $index++) {
#replace http with newline, all .com etc should now be in 3rd field "/"
$serverlist[$index] =~ s/http/\n/g;
print $serverlist[$index];
}
Now, if I run this as above and pipe it to grep thus
./webprog.pl |grep ://|cut -d"/" -f3
Then I get...
ecx.images-amazon.com
ecx.images-amazon.com
g-ecx.images-amazon.com
g-ecx.images-amazon.com
g-ecx.images-amazon.com
g-ecx.images-amazon.com
www.amazon.com">United States<
www.amazon.de">Germany<
www.amazon.fr">France<
BUT, I want to do it all in perl itself,
use LWP::Simple;
use Regexp::Common;
my @hosts = map m[https?://([^/]+)/], get( 'http://www.amazon.co.uk/' )
=~ /$RE{URI}/g;
print "$_\n" for @hosts;
John
--
Those people who think they know everything are a great
annoyance to those of us who do.-- Isaac Asimov
--
To unsubscribe, e-mail: beginners-unsubscr...@perl.org
For additional commands, e-mail: beginners-h...@perl.org
http://learn.perl.org/
reading files c vs perl
is it true that perl will be just as fast as c for reading files ?
for example
will below be as fast as if it were written in c?
I said this because on random posts, I see that perl is optimized to
work w/ text files and it should be as fast as perl
open FILE, $file or die "bad filename: $!";
while (my $line = ) {
#do something w $line
}
--
To unsubscribe, e-mail: beginners-unsubscr...@perl.org
For additional commands, e-mail: beginners-h...@perl.org
http://learn.perl.org/
Re: output record separator in one liner
Chas. Owens wrote: On Mon, Apr 13, 2009 at 15:39, Rick wrote: perl -lane' print "$F[0] ", "$F[4]" , " $F[5]";' Is there anyway to incoporate $\ <- output record separtor to do this instead of printing out w/ manual spaces beteween the variables? snip No, you want to use $, or $". Since $" is already set to a space, you should probably use it: perl -lane 'print "@F[0,4,5]"' You can get it even shorter using -p: perl -lape '$_="@F[0,4,5]"' I forgot about putting " " around @F[0,4,5] and therefore it didn't have spaces between the items.. thanks!! -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
Re: Turn off $ anchor greedy behavior
On Tue, Apr 14, 2009 at 10:02, Michael Alipio wrote: > > >> >> Or use split and return the last field: >> >> $ perl -le' >> my $string = "boy, pig, 123, 123:412adbd, d0g, >> lajdlf134><<_ lkadsf !234,\n"; >> my $value = ( split /,\s+/, $string )[ -1 ]; > > Another mind bogling example... :-) > I thought I would do: > > my @value = ( split /,\s+/, $string ); > print $value[6]; snip That only works if you are certain you want the seventh item. If you always want the last item (regardless of how many items are in the array) you should say either print $value[$#value]; or print $value[-1]; Since you don't care about the other values it is probably better to index into the list than to store to a temporary array. -- Chas. Owens wonkden.net The most important skill a programmer can have is the ability to read. -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
Re: Turn off $ anchor greedy behavior
Aha, found it.. The split returned a list and you've just sliced it. giving [-1] means the list will start running through the elements backwards. --- On Tue, 4/14/09, Michael Alipio wrote: > From: Michael Alipio > Subject: Re: Turn off $ anchor greedy behavior > To: "Perl Beginners" , "John W. Krahn" > Date: Tuesday, April 14, 2009, 10:02 PM > > > > Or use split and return the last field: > > > > $ perl -le' > > my $string = "boy, pig, 123, 123:412adbd, d0g, > > lajdlf134><<_ lkadsf !234,\n"; > > my $value = ( split /,\s+/, $string )[ -1 ]; > > Another mind bogling example... :-) > I thought I would do: > > my @value = ( split /,\s+/, $string ); > print $value[6]; > > How could your example, have printed the last field using [ > -1 ]? > Can I also print say, the 3rd field using this trick? > > > > > > > > print $value; > > ' > > lajdlf134><<_ lkadsf !234 > > > > > > > > > > > > John > > -- Those people who think they know everything are a > great > > annoyance to those of us who do.-- Isaac > Asimov > > > > -- To unsubscribe, e-mail: > beginners-unsubscr...@perl.org > > For additional commands, e-mail: > beginners-h...@perl.org > > http://learn.perl.org/ > > > > > -- > To unsubscribe, e-mail: beginners-unsubscr...@perl.org > For additional commands, e-mail: beginners-h...@perl.org > http://learn.perl.org/ -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
Re: Turn off $ anchor greedy behavior
> > Or use split and return the last field: > > $ perl -le' > my $string = "boy, pig, 123, 123:412adbd, d0g, > lajdlf134><<_ lkadsf !234,\n"; > my $value = ( split /,\s+/, $string )[ -1 ]; Another mind bogling example... :-) I thought I would do: my @value = ( split /,\s+/, $string ); print $value[6]; How could your example, have printed the last field using [ -1 ]? Can I also print say, the 3rd field using this trick? > print $value; > ' > lajdlf134><<_ lkadsf !234 > > > > > > John > -- Those people who think they know everything are a great > annoyance to those of us who do.-- Isaac Asimov > > -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org > For additional commands, e-mail: beginners-h...@perl.org > http://learn.perl.org/ -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
could not connect to Mssqlserver
Hi Gurus,
I need to connect to MSSQL SERVER (express edition on remote system) through
a perl script. But I get the following error with the code below can any
body help me in that.
ERROR
Use of uninitialized value $Win32::ODBC::ErrConn in concatenation (.) or
string
at C:/Perl/lib/Win32/ODBC.pm line 785.
Unable to connect to DSN Databasesysadm:[17] [] "[Microsoft][ODBC SQL Server
Dri
ver][TCP/IP Sockets]SQL Server does not exist or access denied."
ERROR
## CODE SNIP
my $user="sqlserver";
my $pw="servertest";
my $dsn="Databasesysadm"; # name of the DSN we will be using
my $SERVER="remotemachine";
my $DB="projDB";
my %dsnavail;
my @cols;
my @dbs;
my $table;
my @tables;
die "Unable to query available DSN's".Win32::ODBC::Error( )."\n" unless
(%dsnavail = Win32::ODBC::DataSources( ));
foreach my $key (keys %dsnavail)
{
print "$key=$dsnavail{$key}\n";
}
if (!defined $dsnavail{$dsn})
{
die "unable to create DSN:".Win32::ODBC::Error( )."\n"
unless (Win32::ODBC::ConfigDSN(ODBC_ADD_DSN, "SQL Server",
("DSN=$dsn", "DESCRIPTION=DSN for PerlSysAdm", "SERVER=remotemachine",
"DATABASE=$DB", "NETWORK=DBMSSOCN",)));
}
my $dbh = new Win32::ODBC("DSN=$dsn;UID=$user;PWD=$pw;");
die "Unable to connect to DSN $dsn:".Win32::ODBC::Error( )."\n" unless
(defined $dbh);
# find the databases on the server
if (defined $dbh->Sql(q{SELECT name from sysdatabases}))
{
die "Unable to query databases:".Win32::ODBC::Error( )."\n";
}
$dbh->Close( );
die "Unable to delete DSN:".Win32::ODBC::Error( )."\n"unless
(Win32::ODBC::ConfigDSN(ODBC_REMOVE_DSN, "SQL Server","DSN=$dsn"));
## CODE SNIP
Thanks,
Siva
Re: Match and split on array help with output
p...@highdeck.com wrote:
Hi all,
Hello,
I have some basic code that I want to pull out the web addresses from web pages.
Would like to keep it as basic as possible for easy reading.
The line to replace http with newline seems to work ok.
however the "match" line doesnt seem to pull out the required lines
and I'm not to sure about the split either.
I think it's this line "if ($serverlist[$index] =~ /:\/\//)"
that's not giving me what I want.
If I comment out the program after $serverlist[$index] =~ s/http/\n/g;
and then pipe it to grep eg
./webprog.pl |grep ://|cut -d"/" -f3
I get the desired output, to a point, but I'd like to do it all in perl
Thanks for your time.
Alan.
#!/usr/bin/perl
#
#
# Build Initial list and put into array.
@serverlist = `/usr/bin/wget -q -O - http://www.anyserver.com`;
for ($index = 0; $index <= $#serverlist; $index++) {
#replace http with newline, all .com etc should now be in 3rd field "/"
$serverlist[$index] =~ s/http/\n/g;
#pull out all lines with :// like "grep"
# as these should contain web addresses.
if ($serverlist[$index] =~ /:\/\//) # does not seem to do what it should
{
#print $serverlist[$index];
# pull out 3rd field eg. ://my.server.com/
print ((split/\//, $serverlist[$index])[2]); # like cut -d"/"
-f3
# should now be my.server.com
}
}
It works for me:
$ /usr/bin/wget -q -O - http://www.anyserver.com | grep '://' | cut
-d"/" -f3 | wc
97 931656
$ perl -le'
my @serverlist = `/usr/bin/wget -q -O - http://www.anyserver.com`;
for ( my $index = 0; $index <= $#serverlist; $index++ ) {
$serverlist[ $index ] =~ s/http/\n/g;
if ( $serverlist[ $index ] =~ /:\/\// ) {
print( ( split /\//, $serverlist[ $index ] )[ 2 ] );
}
}
' | wc
98 941653
Or better as:
$ perl -le'
my @serverlist = `/usr/bin/wget -q -O - http://www.anyserver.com`;
for ( @serverlist ) {
if ( /:\/\// ) {
print( ( split /\// )[ 2 ] );
}
}
' | wc
97 931656
John
--
Those people who think they know everything are a great
annoyance to those of us who do.-- Isaac Asimov
--
To unsubscribe, e-mail: beginners-unsubscr...@perl.org
For additional commands, e-mail: beginners-h...@perl.org
http://learn.perl.org/
Re: Turn off $ anchor greedy behavior
Michael Alipio wrote: Hi, Hello, Subject: Turn off $ anchor greedy behavior Anchors are not greedy. Anchors don't even match characters. I have a $string that is separated by , and space; boy, pig, 123, 123:412adbd, d0g, lajdlf134><<_ lkadsf !234, Now I want to capture the string(s) between last two commas. It consists of anything upto 32 characters. that is, right after d0g,\s+ up to the last character before the last comma at the end of the line. if I do something like (my $value) = $_ ~= /,\s+(.*),\s+$/; The modifier * is greedy, but that is not your problem. Matches start searching at the left so ',\s+' will match the first comma-whitespace and then '(.*)' will match everthing except newline to the last ',\s+' comma-whitespace. The anchor is superfluous because '.*' is greedy. $value would start matching from "pig" because when I used $ and it looked back, the first thing it would match is ", pig upto the end of the line" I wonder how you could match only the pattern which is nearest to the end of the line having used $ anchor. To get around this, I could split the lines push each comma delimited string into an array and finally print the last element which is a lot of work to do. Is there some sort of turning of greedy behavior of the $ anchor? You could put a greedy match in front of your pattern: $ perl -le' my $string = "boy, pig, 123, 123:412adbd, d0g, lajdlf134><<_ lkadsf !234,\n"; my ( $value ) = $string =~ /.*,\s+(.*),\s+/; print $value; ' lajdlf134><<_ lkadsf !234 Or use split and return the last field: $ perl -le' my $string = "boy, pig, 123, 123:412adbd, d0g, lajdlf134><<_ lkadsf !234,\n"; my $value = ( split /,\s+/, $string )[ -1 ]; print $value; ' lajdlf134><<_ lkadsf !234 John -- Those people who think they know everything are a great annoyance to those of us who do.-- Isaac Asimov -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
Match and split on array help with output
Hi all,
I have some basic code that I want to pull out the web addresses from web pages.
Would like to keep it as basic as possible for easy reading.
The line to replace http with newline seems to work ok.
however the "match" line doesnt seem to pull out the required lines
and I'm not to sure about the split either.
I think it's this line "if ($serverlist[$index] =~ /:\/\//)"
that's not giving me what I want.
If I comment out the program after $serverlist[$index] =~ s/http/\n/g;
and then pipe it to grep eg
./webprog.pl |grep ://|cut -d"/" -f3
I get the desired output, to a point, but I'd like to do it all in perl
Thanks for your time.
Alan.
#!/usr/bin/perl
#
#
# Build Initial list and put into array.
@serverlist = `/usr/bin/wget -q -O - http://www.anyserver.com`;
for ($index = 0; $index <= $#serverlist; $index++) {
#replace http with newline, all .com etc should now be in 3rd field "/"
$serverlist[$index] =~ s/http/\n/g;
#pull out all lines with :// like "grep"
# as these should contain web addresses.
if ($serverlist[$index] =~ /:\/\//) # does not seem to do what it
should
{
#print $serverlist[$index];
# pull out 3rd field eg. ://my.server.com/
print ((split/\//, $serverlist[$index])[2]); # like cut -d"/"
-f3
# should now be my.server.com
}
}
--
To unsubscribe, e-mail: beginners-unsubscr...@perl.org
For additional commands, e-mail: beginners-h...@perl.org
http://learn.perl.org/
AW: AW: Turn off $ anchor greedy behavior
Michael Alipio asked:
> > my $string = 'boy, pig, 123, 123:412adbd, d0g,
> > lajdlf134><<_ lkadsf !234,';
> >
> > if( $string =~ m/,\s*([^,]*),[^,]*$/ ){
> > print "$1\n";
> > }
>
> How could you guys write this so simple? My regexp was twice this long.
Lots of practice? ;-)
> the regexp after \s* tells perl to match anything (0 or more) that is not
> a comma, right? how come it did not match pig? pig is also followed by
> comma, right? so pig should be captured by ([^,]*), right? I guess perl
> really looks for a match starting from the end of the line.
That would be cool, right? No, my RE is says, I want a comma and maybe some
whitespace after it, then I'll capture all of the following stuff that's not a
comma, then I want another comma and possibly some more stuff that's not a
comma right before the end of the line.
Perl's RE engine starts out by looking at ", pig" (capturing "pig") but the
part where I said "no further comma before the end of the line" prevents it
from matching, since there's a comma after 123 but before the end of the
string. For the same reasons it fails to match at 123, 123:... and d0g.
That's why I think that a "classic C" approach using rindex() and substr()
might be faster in your case:
#!/usr/bin/perl -w
use strict;
my $string = 'boy, pig, 123, 123:412adbd, d0g, lajdlf134><<_ lkadsf !234,';
my $rightComma = rindex( $string, ',' ) - 1;
my $leftComma = rindex( $string, ',', $rightComma );
print substr( $string, $leftComma + 2, $rightComma - $leftComma ), "\n";
__END__
HTH,
Thomas
--
To unsubscribe, e-mail: beginners-unsubscr...@perl.org
For additional commands, e-mail: beginners-h...@perl.org
http://learn.perl.org/
Re: AW: Turn off $ anchor greedy behavior
> my $string = 'boy, pig, 123, 123:412adbd, d0g,
> lajdlf134><<_ lkadsf !234,';
>
> if( $string =~ m/,\s*([^,]*),[^,]*$/ ){
> print "$1\n";
> }
How could you guys write this so simple? My regexp was twice this long.
the regexp after \s* tells perl to match anything (0 or more) that is not a
comma, right? how come it did not match pig? pig is also followed by comma,
right? so pig should be captured by ([^,]*), right? I guess perl really looks
for a match starting from the end of the line.
The string actually looks like this:
ABCD1:5C, 2009-04-14 13:01:24, 2009-04-14, 5, 23, ABC, , , -1, 187, 0, 1.2.3.4,
20, lkasd123 as_!23:<<>s @12ff,
My Regexp looks like this:
/\.\s+\d+,\s+\d+,\s+(.*),$/
It matches from the comma at the end of the line up to .4 when you go
backwards. By going as far as this, I can be assured that perl won't find any
more match, but the regexp looks ugly.
What is wrong with my version?
I think if in the future, if perl finds a line which is not ending in a pattern
exactly like my regexp then it will fail, however yours i guess won't.
>
> __END__
>
> Depending on the input data size it might worthwhile to
> look at rindex() and substr() instead of using a RE.
>
> HTH,
> Thomas
--
To unsubscribe, e-mail: beginners-unsubscr...@perl.org
For additional commands, e-mail: beginners-h...@perl.org
http://learn.perl.org/
Re: Text::Unidecode behaves differently on two machines
Kelly Jones wrote:
I "cpan Text::Unidecode" on 2 machines and then ran this code:
use utf8;
use Text::Unidecode;
print unidecode("\x{5317}\x{4EB0}")."\n";
print unidecode("\xd0\x90\xd0\xbb")."\n";
print unidecode("\xe3\x82\xa2")."\n";
On both machines, the first line correctly prints "Bei Jing", the
author's test case.
Second line: "Al" on one machine (correct), "DD>>" on the other.
Third line: "a" on one machine (correct), "aC/" on the other.
Thoughts?
$ perl -Mstrict -MEncode -MText::Unidecode -wle '
my $s = "\xe3\x82\xa2";
print Text::Unidecode::unidecode($s);
Encode::_utf8_on($s);
print Text::Unidecode::unidecode($s);
'
aC/
a
That is the output you should expect.
Text::Unidecode should not secretly "fix" the utf8-flag, for the same
reason that "_utf_on" starts with an underscore.
$ perl -MText::Unidecode -wle'print $Text::Unidecode::VERSION'
0.04
--
Ruud
--
To unsubscribe, e-mail: beginners-unsubscr...@perl.org
For additional commands, e-mail: beginners-h...@perl.org
http://learn.perl.org/
AW: Turn off $ anchor greedy behavior
Michael Alipio asked:
> I have a $string that is separated by , and space;
>
> boy, pig, 123, 123:412adbd, d0g, lajdlf134><<_ lkadsf !234,
>
>
> Now I want to capture the string(s) between last two commas. It consists
> of anything upto 32 characters. that is, right after d0g,\s+ up to the
> last character before the last comma at the end of the line.
#!/usr/bin/perl -w
use strict;
my $string = 'boy, pig, 123, 123:412adbd, d0g, lajdlf134><<_ lkadsf !234,';
if( $string =~ m/,\s*([^,]*),[^,]*$/ ){
print "$1\n";
}
__END__
Depending on the input data size it might worthwhile to look at rindex() and
substr() instead of using a RE.
HTH,
Thomas
--
To unsubscribe, e-mail: beginners-unsubscr...@perl.org
For additional commands, e-mail: beginners-h...@perl.org
http://learn.perl.org/
Turn off $ anchor greedy behavior
Hi, I have a $string that is separated by , and space; boy, pig, 123, 123:412adbd, d0g, lajdlf134><<_ lkadsf !234, Now I want to capture the string(s) between last two commas. It consists of anything upto 32 characters. that is, right after d0g,\s+ up to the last character before the last comma at the end of the line. if I do something like (my $value) = $_ ~= /,\s+(.*),\s+$/; $value would start matching from "pig" because when I used $ and it looked back, the first thing it would match is ", pig upto the end of the line" I wonder how you could match only the pattern which is nearest to the end of the line having used $ anchor. To get around this, I could split the lines push each comma delimited string into an array and finally print the last element which is a lot of work to do. Is there some sort of turning of greedy behavior of the $ anchor? -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
