Output file name uses Data Parameter
I am creating an output file, and I want to use the date parameter passed in
as part of the output file name.
This is how I name my output file:
1. Assign the date param to ARGV - $active_date = $ARGV[0];
2. $outputfile = NEW_CUSTOMERS_after_$active_date;
When I run the task I get the following error:
Can't write to file: No such file or directory at
/xps_uat1/express/atai/loc/server/bin/new_customers_since.pl line 71.
Below is the section that is referenced:
if ($ARGV[0] ne '') {
$fetch_New_customers-execute($active_date) || die Can't execute file
handle: $DBI::errstr\n;
while (@raw = $fetch_New_customers-fetchrow)
{
$node_name = $raw[0];
$created_date = $raw[1];
$active_date= $raw[2];
open (FILE,$outputfile$active_date) || die Can't write to file:
$! ; ---LINE 71
write (FILE);
}
Is there a better way to incorporate a date parameter in the output file
name.
Thanks,
Kim
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Variable interpolation in a format
Below is my format: format FILE_TOP = New Customers Since Customer Name Creation DateActivation Date . format FILE = @ @ @ $node_name,$created_date,$active_date . My script is accepting a date parameter, and I want to print that date in the title. I tried that by adding $active_date to the New Customers Since title, and the variable was not interpolated. What's the best way to print my parameter inside of the output file? Kim Green Billing Systems Developer Madison River Communications 919.563.8385 [EMAIL PROTECTED] -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
FW: Variable interpolation in a format - Disregard
never mind. -Original Message- From: Kim Green Sent: Thursday, September 13, 2001 9:11 AM To: '[EMAIL PROTECTED]' Subject: Variable interpolation in a format Below is my format: format FILE_TOP = New Customers Since -- -- Customer Name Creation DateActivation Date . format FILE = @ @ @ $node_name,$created_date, $active_date . My script is accepting a date parameter, and I want to print that date in the title. I tried that by adding $active_date to the New Customers Since title, and the variable was not interpolated. What's the best way to print my parameter inside of the output file? Kim Green Billing Systems Developer Madison River Communications 919.563.8385 [EMAIL PROTECTED] -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
FW: Bind variables
My script has a statement handle that accepts only one parameter. I am assigning the parameter given to the $ARGV[0]. I run the script from the command line, also sending the parameter. I am also assigning all selected values to an array for output. I continue to get this message: Can't execute file handle: ORA-01008: not all variables bound (DBD: oexfet error) Here is most of the statement: $fetch_GLD_BILL_details= $dbh-prepare(select distinct substr(ne.general_18,82,1) CLASS, substr(ne.general_18,83,1) MSG_TYPE, c.charge AMOUNT, ne.c_party_id MAIN_BILL_NUM, SUBSTR(ne.a_party_id,1,3) CALLING_NPA, SUBSTR(ne.a_party_id, 4,3) CALLING_NXX, SUBSTR(ne.a_party_id,7,10) CALLING_LINE, rc2.abbreviation FROM_CITY_STATE, DECODE(SUBSTR(ne.a_party_id,1,3),SUBSTR(ne.b_party_id, 1,3), 'A', 'R') Inter_Intra, DECODE(NE.EVENT_SUB_TYPE_CODE,110, NE.C_PARTY_ID,'00') AUTH_CODE, DECODE(ne.event_sub_type_code,110, ne.general_14, '') PIN, NVL(cnda.index1_value, '') PAC_Code, substr(ne.general_18,4,2) category, SUBSTR(TO_CHAR(I.ISSUE_DATE,'DD-MON-'),8,11) Stmt_YEAR, TO_CHAR(I.ISSUE_DATE,'MM'), SUBSTR(TO_CHAR(I.ISSUE_DATE,'DD-MON-RR'),1,2) Stmt_DAY FROM customer_node_history cnh, customer_node_da_array cnda, product_instance_history pih, product_history ph, service_history sh, service_type st, charge c, invoice i, and SYSDATE between cnh.effective_start_date and cnh.effective_end_date and SYSDATE BETWEEN pih.effective_start_Date and pih.effective_end_Date and SYSDATE BETWEEN ph.effective_start_Date and ph.effective_end_Date and SYSDATE BETWEEN sh.effective_start_Date and sh.effective_end_Date and cnh.node_name_uppercase = ?); $customer_name = $ARGV[0]; Please advise, Kim Green Billing Systems Developer Madison River Communications 919.563.8385 [EMAIL PROTECTED] -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Command line vs. Application
I have a script that creates outputfile based on the rows returned from a select statement. I run the script from the command line, and the outputfile gets created. But, no file is created when I run the script from an application. Generally speaking, what kinds of things would cause this? Kim Kim Green Billing Systems Developer Madison River Communications 919.563.8385 [EMAIL PROTECTED] -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
FW: Optional Variables
I don't know how or where to put how to use this $option. What if my Default value is a sql statement? Can I just include the name of the file handle between the brackets? -Original Message- From: Brett W. McCoy [mailto:[EMAIL PROTECTED]] Sent: Friday, June 29, 2001 6:40 PM To: M.W. Koskamp Cc: Evgeny Goldin (aka Genie); [EMAIL PROTECTED] Subject: Re: Optional Variables On Fri, 29 Jun 2001, M.W. Koskamp wrote: my $option = @ARGV ? shift : DEFAULT VALUE; Above option only works for 1 parameter tho (and commandline arguments). For function calls i like to use 'named parameters' by accepting a hash of options. Well, yeah, but the topic *was* command-line arguments, not function arguments. You can easily loop through @ARGV, unshifting as you go, until @ARGV is depleted and default values assigned. -- Brett http://www.chapelperilous.net/btfwk/ A free society is one where it is safe to be unpopular. -- Adlai Stevenson
Optional Variables
What's the proper syntax to indicate that a variable is optional? The script that I have created works great when I pass in a variable, but the script need to execute the SQL even if I don't pass in a variable. Thanks, Kim
Formatting
What would cause this format for the output file to result in the error message Format not terminated at end of line : format OUTPUTFORMAT = @,@ ,@ ,@ $servicename,$filename ,$service_type_name ,$node_name . These values are assigned by an array that gets populated based on a select statement. I call it in the body of my code like this: write (OUTPUTFORMAT); Thanks, Kim
Optional Variables
My question pertains to using command line variables in Perl.
I created a script that uses SQL and runs from an application, and the only
parameter is optional. This script works well when the parameter is
required or not used at all.
I have altered the SQL script so that it can accept a variable or execute
the query without it, but I need to do the same in Perl.
I am using @ARGV and explicitly assigning it to a variable. Below is an
excerpt:
if (defined(@ARGV[1]))
{
$filename = @ARGV[1];
$sth-execute($filename) || die Couldn't execute statement
. $sth-errstr;
This is my first script, so I have been reading, researching and testing
what I find. However, I found nothing about this anywhere.
Please help!
Thanks,
Kim
