Problem with ^ oprator
Hi, I have two number $a=6; #binary - 0110 $b=10; # 1010 I need work this operation a OR b 0110 - 6 OR 1010 - 10 - 1110 - 14 this is true; buy when I use this operator ^ in perl $a^$b then output is 12 0110 - 6 OR 1010 - 10 - 1100 - 12 false; Why ? How I make true output? Thanks. -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: Problem with ^ oprator
From: Rado Petrik [EMAIL PROTECTED] I have two number $a=6; #binary - 0110 $b=10; # 1010 I need work this operation a OR b 0110 - 6 OR 1010 - 10 - 1110 - 14 this is true; buy when I use this operator ^ in perl $a^$b then output is 12 0110 - 6 OR 1010 - 10 - 1100 - 12 false; Why ? ^ is XOR. That is exclisive OR ... the resul with have 1 only on those places where either one or the other argument had 1, but not both. 0 XOR 0 = 0 0 XOR 1 = 1 1 XOR 0 = 1 1 XOR 1 = 0 What you want is $a | $b Jenda = [EMAIL PROTECTED] === http://Jenda.Krynicky.cz = When it comes to wine, women and song, wizards are allowed to get drunk and croon as much as they like. -- Terry Pratchett in Sourcery -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: Problem with ^ oprator
On 4 Apr 2003, Rado Petrik wrote: I have two number $a=6; #binary - 0110 $b=10; # 1010 I need work this operation a OR b 0110 - 6 OR 1010 - 10 - 1110 - 14 this is true; buy when I use this operator ^ in perl $a^$b then output is 12 0110 - 6 OR 1010 - 10 - 1100 - 12 false; ^ is XOR, not OR. You want to use | for bitwise OR. $ perl -e 'print 6 | 10' 14 -- Brett -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
