RE: Foo (Bar)---I now see the light! (Or that which is made lig ht of)

2004-09-09 Thread Ichim, Adrian N.
Have a look at the Jargon File (google for an updated version). A
foobar-specific link  
is http://www.catb.org/%7Eesr/jargon/html/F/foobar.html

Adrian Ichim 

 -Original Message-
 From: jason corbett [mailto:[EMAIL PROTECTED] 
 Sent: Wednesday, September 08, 2004 8:14 PM
 To: perl beginners
 Subject: Foo (Bar)---I now see the light! (Or that which is 
 made light of)
 
  
  
  
 
 
 jason corbett [EMAIL PROTECTED] wrote:
 As a newbie, I have seen the statement foo (bar) mentioned 
 in books and and even on this site. I haven't yet seen what 
 this actually mean as I can assume that its just for 
 examples. If I am wrong please explain in detail what this is about.
 
 Thanks,
 JC
 

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Re: Foo (Bar)

2004-09-08 Thread Chris Devers
On Wed, 8 Sep 2004, jason corbett wrote:
As a newbie, I have seen the statement foo(bar) mentioned in books 
and and even on this site. I haven't yet seen what this actually mean 
as I can assume that its just for examples. If I am wrong please 
explain in detail what this is about.
Is your question about the names, or the syntax  construction?
The names foo and bar (and variants -- baz, bat, foobar, etc) 
are common stubs that are often used in throwaway code, for demos and 
examples, for names to be filled in later, etc.

Just as algebra problems often use x and n for arbitrary variables, 
many Perl programmers use foo and bar for arbitrary variables.

As for the construct, `this( that )` is a subroutine / function call, 
where the language defined function or the programmer defined sub (or 
library module defined method) called this is being called with the 
parameter / argument that. Or, in your example, foo and bar 
instead of this and that.

Generally, if you see the phrase foo(bar), exactly like that, in 
documentation, then the writer is just making some kind of example, 
perhaps about what typical subroutine calls look like. (Note though that 
this example probably wouldn't actually work, because 'bar' here is a 
bareword, rather than a quoted string or a variable, so Perl might 
complain about passing it as an argument because it's not clear what 
should be done with bar; if it should be treated as a string, it should 
be wrapped in single- or double-quotes, and if it is a variable then it 
needs a prefix ($ @ % ). )

Make sense, or is something still unclear ?
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RE: Foo (Bar)

2004-09-08 Thread Shaw, Matthew
Jason:

Foo  bar (or just foobar) are terms of varied origins simply meant to
express 'this thing' as in 'in function foo what will the output be
given argument bar'. (Compare also to: x (y)) There are many
explanations for the origin of the term, and most are captured at one of
the two following links:

FOLDOC (Free Online Dictionary Of Computing)
http://foldoc.doc.ic.ac.uk/foldoc/foldoc.cgi?query=foo

The Jargon File
http://catb.org/~esr/jargon/html/F/foo.html
http://catb.org/~esr/jargon/html/F/foobar.html

Hope this helps.

Matt



 -Original Message-
 From: jason corbett [mailto:[EMAIL PROTECTED]
 Sent: Wednesday, September 08, 2004 1:43 PM
 To: perl beginners
 Subject: Foo (Bar)
 
 As a newbie, I have seen the statement foo (bar) mentioned in books
and
 and even on this site. I haven't yet seen what this actually mean as I
can
 assume that its just for examples. If I am wrong please explain in
detail
 what this is about.
 
 Thanks,
 JC

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Re: Foo (Bar)

2004-09-08 Thread Bee
in short , foo bar baz etc. just mean 'something', 'another something'
whatever is discussing  about.for more, check results in google.com for
'metasyntactic variables'

HTH




- Original Message - 
From: jason corbett [EMAIL PROTECTED]
To: perl beginners [EMAIL PROTECTED]
Sent: Thursday, September 09, 2004 12:42 AM
Subject: Foo (Bar)


 As a newbie, I have seen the statement foo (bar) mentioned in books and
and even on this site. I haven't yet seen what this actually mean as I can
assume that its just for examples. If I am wrong please explain in detail
what this is about.

 Thanks,
 JC




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Re: Foo (Bar)

2004-09-08 Thread Wiggins d Anconia
 On Wed, 8 Sep 2004, jason corbett wrote:
 
  As a newbie, I have seen the statement foo(bar) mentioned in books 
  and and even on this site. I haven't yet seen what this actually mean 
  as I can assume that its just for examples. If I am wrong please 
  explain in detail what this is about.
 
 Is your question about the names, or the syntax  construction?
 
 The names foo and bar (and variants -- baz, bat, foobar, etc) 
 are common stubs that are often used in throwaway code, for demos and 
 examples, for names to be filled in later, etc.
 
 Just as algebra problems often use x and n for arbitrary variables, 
 many Perl programmers use foo and bar for arbitrary variables.


Not just Perl programmers:

http://jargon.watson-net.com/jargon.asp?w=metasyntactic%20variable
http://jargon.watson-net.com/jargon.asp?w=foo

 
 As for the construct, `this( that )` is a subroutine / function call, 
 where the language defined function or the programmer defined sub (or 
 library module defined method) called this is being called with the 
 parameter / argument that. Or, in your example, foo and bar 
 instead of this and that.
 
 Generally, if you see the phrase foo(bar), exactly like that, in 
 documentation, then the writer is just making some kind of example, 
 perhaps about what typical subroutine calls look like. (Note though that 
 this example probably wouldn't actually work, because 'bar' here is a 
 bareword, rather than a quoted string or a variable, so Perl might 
 complain about passing it as an argument because it's not clear what 
 should be done with bar; if it should be treated as a string, it should 
 be wrapped in single- or double-quotes, and if it is a variable then it 
 needs a prefix ($ @ % ). )


'Sigil' rather than 'prefix'...
(distinguishing the two will eventually become necessary it seems)
 
 Make sense, or is something still unclear ?
 
 

http://danconia.org


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Re: Foo (Bar)

2004-09-08 Thread M Senthil Kumar

Hi,

On Wed, 8 Sep 2004, jason corbett wrote:
 As a newbie, I have seen the statement foo (bar) mentioned in books
 and and even on this site. I haven't yet seen what this actually mean as
 I can assume that its justfor examples. If I am wrong please explain in
 detail what this is about.

I read somewhere, that it stands for  F**ked Beyond All Recognition. :)

Senthil



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RE: Foo (Bar)

2004-09-08 Thread Bob Showalter
jason corbett wrote:
 As a newbie, I have seen the statement foo (bar) mentioned in books
 and and even on this site. I haven't yet seen what this actually mean
 as I can assume that its just for examples. If I am wrong please
 explain in detail what this is about.   

http://www.catb.org/~esr/jargon/html/M/metasyntactic-variable.html

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Re: Foo (Bar)

2004-09-08 Thread Chris Devers
On Wed, 8 Sep 2004, Wiggins d Anconia wrote:
 On Wed, 8 Sep 2004, jason corbett wrote:
Just as algebra problems often use x and n for arbitrary variables,
many Perl programmers use foo and bar for arbitrary variables.
Not just Perl programmers:
http://jargon.watson-net.com/jargon.asp?w=metasyntactic%20variable
http://jargon.watson-net.com/jargon.asp?w=foo

[] if it should be treated as a string, it should be wrapped in 
single- or double-quotes, and if it is a variable then it needs a 
prefix ($ @ % ). )
'Sigil' rather than 'prefix'...
Well, yes, to both points.
I was trying to err on the side of minimal jargon  only Perl, but of 
course you're right: lots of languages use the foo/bar variable name 
idiom, and the term for the character that precedes one of Perl's 
nouns is sigil. (In this context, I'm treating a subroutine [that 
does something] as a noun, not thinking about how verby they are, in 
order to be consistent with the other uses of sigils.)


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RE: Foo (Bar)

2004-09-08 Thread Bob Showalter
Bob Showalter wrote:
 http://www.catb.org/~esr/jargon/html/M/metasyntactic-variable.html

Oops, sorry. Didn't realize someone already posted that link.

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RE: Foo (Bar)

2004-09-08 Thread Weaver, Walt


 -Original Message-
 From: M Senthil Kumar [mailto:[EMAIL PROTECTED] 
 Sent: Wednesday, September 08, 2004 9:53 AM
 To: jason corbett
 Cc: perl beginners
 Subject: Re: Foo (Bar)
 
 
 
 Hi,
 
 On Wed, 8 Sep 2004, jason corbett wrote:
  As a newbie, I have seen the statement foo (bar) 
 mentioned in books
  and and even on this site. I haven't yet seen what this 
 actually mean as
  I can assume that its justfor examples. If I am wrong 
 please explain in
  detail what this is about.
 
 I read somewhere, that it stands for  F**ked Beyond All 
 Recognition. :)
 
 Senthil

Yeah, FUBAR. F'd Up Beyond All Repair. It originated in the American
military in WWII. As an acronym it was a natural to be adapted to the
world of computing.   :)

--Walt


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Re: Foo (Bar)

2004-09-08 Thread Randal L. Schwartz
 Wiggins == Wiggins d Anconia [EMAIL PROTECTED] writes:

Wiggins Not just Perl programmers:

Wiggins http://jargon.watson-net.com/jargon.asp?w=metasyntactic%20variable
Wiggins http://jargon.watson-net.com/jargon.asp?w=foo

It's because of the overuse of Foo and Bar that I chose Fred and
Barney in the first edition of Learning Perl.

I had originally put Foo and Bar in many examples, but was watching
some cable network like WTBS (this was before Cartoon Network) in the
background and kept hearing Fred and Barney in place of Foo and Bar.
So, I did a global substitute of Fred for Foo, and Barney for Bar, and
then cleaned up the text.  Once that gelled out, I started using the
rest of the Flintstones as a theme for the examples that had not been
written.  And that's how it got started.

When Perl5 came along, the tradition continued into the manpages,
using Flintstones, Jetsons, and Simpsons.  And when Stonehenge
instructors wrote the other materials, we picked different themes,
like the Gilligan's Island references for the Alpaca (Learning Perl
volume 2).

So, there you have it.  Foo/Bar = Fred/Barney, and the rest is
history.

Eric Raymond once asked if I had invented this mapping, or if I had
copied it from some British documentation he had seen.  But my
response (roughly the above) has not yet made it into ESR's Hackers
Dictionary.

-- 
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[EMAIL PROTECTED] URL:http://www.stonehenge.com/merlyn/
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Re: Foo (Bar)---I now see the light! (Or that which is made light of)

2004-09-08 Thread Jose Alves de Castro
From dictionary.com :


jargon Another common metasyntactic variable; see foo.
Hackers do *not* generally use this to mean FUBAR in either
the slang or jargon sense.

According to a german correspondent, the term was coined
during WW2 by allied troops who could not pronounce the german
word furchtbar (horrible, terrible, awful).



Interesting :-) Because whenever I write foobar, I don't mean
horrible, terrible nor awful :-)


On Wed, 2004-09-08 at 18:13, jason corbett wrote:
   
  
 
 
 jason corbett [EMAIL PROTECTED] wrote:
 As a newbie, I have seen the statement foo (bar) mentioned in books and and even 
 on this site. I haven't yet seen what this actually mean as I can assume that its 
 just for examples. If I am wrong please explain in detail what this is about.
 
 Thanks,
 JC
-- 
José Alves de Castro [EMAIL PROTECTED]
  http://natura.di.uminho.pt/~jac


signature.asc
Description: This is a digitally signed message part


Re: Foo (Bar)---I now see the light! (Or that which is made light of)

2004-09-08 Thread Chris Devers
On Wed, 8 Sep 2004, Jose Alves de Castro wrote:
From dictionary.com :
jargon Another common metasyntactic variable; see foo.
Hackers do *not* generally use this to mean FUBAR in either
the slang or jargon sense.
According to a german correspondent, the term was coined
during WW2 by allied troops who could not pronounce the german
word furchtbar (horrible, terrible, awful).

Interesting :-) Because whenever I write foobar, I don't mean
horrible, terrible nor awful :-)
The Jargon File is a decent source of background information on what 
terms mean and where they may have come from, but when it branches out 
into speculation about what people do or don't mean, or think, or 
believe, or whatever, well, keep in mind that it is largely filtered 
through the prism of how Eric Raymond, self-appointed spokesperson  
anthropoligist for all things Free Software, sees things.

More often than not, he is dead wrong.
In this case, the definition is basically correct -- most people are 
aware of the foobar -- fubar -- 'f*cked up beyond all recognition 
idea, but it isn't what they're alluding to in selecting foo and bar 
as variable names. But the idea that it is a corruption of furchtbar 
is grasping a little -- it may be true, but it isn't the widely accepted 
origin of the term.

More broadly though, when the Jargon File starts going off about 
hackers think that... -- that's when you stop reading and go on to the 
next entry, because everything that follows should more accurately be 
prefixed with Eric Raymond thinks that... and, well, why bother? :-)


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Re: foo-bar

2002-09-02 Thread Gary Stainburn

On Monday 02 September 2002 5:54 am, Alex B. wrote:
 Hello list,

   this is a very simple question:

   what does FOO or BAR or FOOBAR mean???

   I've seen it on t-shirts (perl), my programming perl book,
   programming CGI with perl, and even learning perl...


   now, does FOO have any meaning?

   - sounds almost like: whuzup, foo(l)!  :)

Have a look at:

http://www.tuxedo.org/~esr/jargon/

Ttis is a very good source of information such highly technical terms as foo 
and bar
-- 
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This email does not contain private or confidential material as it
may be snooped on by interested government parties for unknown
and undisclosed purposes - Regulation of Investigatory Powers Act, 2000 


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Re: foo-bar

2002-09-02 Thread Steve Grazzini

Alex B. [EMAIL PROTECTED] wrote:
 
   this is a very simple question:
 
   what does FOO or BAR or FOOBAR mean???
 

  http://info.astrian.net/jargon/terms/f/foo.html

-- 
Steve

perldoc -qa.j | perl -lpe '($_)=m((.*))'

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RE: $foo

2002-02-15 Thread John Edwards

lol. This should help explain.

http://whatis.techtarget.com/definition/0,,sid9_gci212139,00.html

When you see something like 

$foo = $_;

It means that someone is taking the value of the default variable ($_) and
assiging in to another scalar. In this case, $foo, but it could just as
easily be $someName.

The default variable is more often than not invisible in scripts. For
example

@array = qw(one two three);

foreach (@array) {
print;
}

In that code, then default variable appears twice. Can't see it?? That's
because most of the perl operators default to working with the default
operator if no other is assigned.

The code above does exactly the same as this

@array = qw(one two three);

foreach $_ (@array) {
print $_;
}

And if you want make it clear which variable you are working with you can do
either

@array = qw(one two three);

foreach $someName (@array) {
print $somName;
}

which assigns each element in turn to $someName or...

@array = qw(one two three);

foreach (@array) {
$someName = $_;
print $someName;
}

which assigns each element in turn to $_, then you are taking that value and
assiging it to $someName within the loop and working with that new value.

HTH

John

-Original Message-
From: Susan Aurand [mailto:[EMAIL PROTECTED]]
Sent: 15 February 2002 14:49
To: [EMAIL PROTECTED]
Subject: $foo


I am learning Perl, so this may seem a dumb question to the advance Perl
Programmers.
What exact purpose does $foo do?
Example $foo=$_. What benefit do I get  from making the input string
$foo? Every place I look I
do not get a clear understanding or picture of $foo.
Thank you
Susan



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Re: $foo

2002-02-15 Thread Jenda Krynicky

From:   Susan Aurand [EMAIL PROTECTED]

 I am learning Perl, so this may seem a dumb question to the advance
 Perl Programmers. What exact purpose does $foo do? Example $foo=$_.
 What benefit do I get  from making the input string $foo? Every place
 I look I do not get a clear understanding or picture of $foo. Thank
 you Susan

I think it's good to think about $_ as if it was a pronoun You.

s/hello/hi/g;   === Hey you there change all hellos to his!
chomp;  === Hey you drop the end-fo-line!
...

Now it you only work with one variable and the part of code is short 
it's OK to use $_ ... since you'll know which you do you mean. 
But as soon as the code gets more complex, you pass the variable 
around or you have some internal loops with their own you ... 
you'll soon loose track who are you shouting at at the moment.

Then it's good to name the variable at last. So that you know when 
do you speak to Mary and when to Robin :-)

Jenda

P.S.: If the question was more about why the heck do they use 
foo, what does that name mean. ... then .. the name foo doesn't 
mean anything. Foo is used in place of a real name of variable in 
examples and similar places. Basicaly it's also kind of ... pronoun.

=== [EMAIL PROTECTED] == http://Jenda.Krynicky.cz ==
There is a reason for living. There must be. I've seen it somewhere.
It's just that in the mess on my table ... and in my brain.
I can't find it.
--- me

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Re: foo bar?

2001-05-16 Thread Francis Henry

actually, ww2 veterans are thought to have originated it.  'fucked up beyond all
recognition'.

Jos Boumans wrote:

 it comes from the vietnam war iirc (watch full metal jacket if you want some
 'insight' ;-)

 it is originally 'fubar' or Fucked Up Beyond Any Recognition (pardon the expletives)

 so, us perl geeks use 'foo' and 'bar' as standard variable names in examples now...

 So much for a short stroll thru history =)

 Regards,

 Jos Boumans

 ber kessels wrote:

  Hi,
 
  Maybe a silly question but where does foo-bar or foobar refer to?
 
  Everyone uses it in perl, but I cannot find the origin of it.
  I am not english (I am Duch), but even my english teacher didn't know it, he had
   even never heard of it.
 
  I am just curious that's all.
 
  Thanx for reading
 
  Ber
 
  _
STRUIKDUIK IS VERNIEUWD
(er staat nu dus iets)
http://struikduik.tripod.com
 
telefoon: ++31625181320
adres: Capadosestraat 51
  2623 AD
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Re: foo bar?

2001-05-16 Thread Brett W. McCoy

On Wed, 16 May 2001, ber kessels wrote:

 Maybe a silly question but where does foo-bar or foobar refer to?

 Everyone uses it in perl, but I cannot find the origin of it.
 I am not english (I am Duch), but even my english teacher didn't know it, he had
  even never heard of it.

foo and bar are, to put it simply, the canonical metasyntactic variables
used in programming examples. :-)  You see thenm used all the time in C
coding examples: Take function foo and pass it value bar...

The actual phrase supposedly derives from an old (probably US) Army term
FUBAR -- Fouled[0] Up Beyond All Recognition.

-- Brett

[0] Or any other F word you choose to use to indicate a bad situation




Re: foo bar?

2001-05-16 Thread Timothy Kimball


: Maybe a silly question but where does foo-bar or foobar refer to?
:
: Everyone uses it in perl, but I cannot find the origin of it.

See the entry in the Hacker Jargon file:

http://www.tuxedo.org/~esr/jargon/html/entry/foo.html

-- tdk



Re: foo bar?

2001-05-16 Thread Kevin Meltzer

This is in the jargon file:

http://www.tuxedo.org/~esr/jargon/html/entry/foobar.html

Cheers,
Kevin

On Wed, May 16, 2001 at 09:07:11AM -0400, Brett W. McCoy ([EMAIL PROTECTED]) 
spew-ed forth:
 On Wed, 16 May 2001, ber kessels wrote:
 
  Maybe a silly question but where does foo-bar or foobar refer to?
 
  Everyone uses it in perl, but I cannot find the origin of it.
  I am not english (I am Duch), but even my english teacher didn't know it, he had
   even never heard of it.
 
 foo and bar are, to put it simply, the canonical metasyntactic variables
 used in programming examples. :-)  You see thenm used all the time in C
 coding examples: Take function foo and pass it value bar...
 
 The actual phrase supposedly derives from an old (probably US) Army term
 FUBAR -- Fouled[0] Up Beyond All Recognition.
 
 -- Brett
 
 [0] Or any other F word you choose to use to indicate a bad situation
 

-- 
[Writing CGI Applications with Perl - http://perlcgi-book.com]
As the fletcher whittles and makes straight his arrows, so the master directs
his straying thoughts. 
-- Buddha



Re: foo bar? -Reply

2001-05-16 Thread Rod Suter

Actually, the American military acronym 'fubar' goes back at least to World War II.  
The use of 'foo' and 'bar' as metasyntactic variables  probably dates to the the lisp 
hackers at the MIT AI lab in the 50's or 60's , before unix.  Foo and bar function 
like 'x'  or 'n' in the traditional mathematical exposition 'let x = n.  They remain 
in common usage in the unix world and its derivatives, because of their brevity and 
style.

 Jos Boumans [EMAIL PROTECTED] 05/16 8:33 am 
it comes from the vietnam war iirc (watch full metal jacket if you want some
'insight' ;-)

it is originally 'fubar' or Fucked Up Beyond Any Recognition (pardon the expletives)

so, us perl geeks use 'foo' and 'bar' as standard variable names in examples now...

So much for a short stroll thru history =)

Regards,

Jos Boumans

ber kessels wrote:

 Hi,

 Maybe a silly question but where does foo-bar or foobar refer to?

 Everyone uses it in perl, but I cannot find the origin of it.
 I am not english (I am Duch), but even my english teacher didn't know it, he had
  even never heard of it.

 I am just curious that's all.

 Thanx for reading

 Ber

 _
   STRUIKDUIK IS VERNIEUWD
   (er staat nu dus iets)
   http://struikduik.tripod.com

   telefoon: ++31625181320
   adres: Capadosestraat 51
 2623 AD
 Den Haag

 Get your wireless addressbook at room33. http://room33.com