Re: Delimiter for string..
From: Singh, Ajit p [EMAIL PROTECTED]
I am running a perl script as below which is working perfectly and
want to replace the hardcoded values with variables. (the script
accepts space as the delimiter)
@respon = $placesock-print(./test.pl \7741266\ \DEM EXPO\
\255.255.255.255\ \n);
and i am doing this
@respon = $placesock-print(./test.pl. .$param1. .$param2.
.$param3 \n);
I'm sure you'll like the qq operator:
@respon = $placesock-print(
qq{./test.pl $param1 $param2 $param3\n}
);
or
@respon = $placesock-print(
qq./test.pl $param1 $param2 $param3\n
);
or
@respon = $placesock-print(
qq#./test.pl $param1 $param2 $param3\n#
);
or
...
The qq (as well as it's brother q and relatives qx, qr, qw and even m
and s) allows you to use any delimiter you like. Which means that if
you select well you do not have to escape any quotes.
See the Quote and Quote-like Operators section of the perlop
manpage:
perldoc perlop
Jenda
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Re: Delimiter for string..
Ajitpal, [EMAIL PROTECTED] wrote: Friends, I am running a perl script as below which is working perfectly and want to replace the hardcoded values with variables. (the script accepts space as the delimiter) @respon = $placesock-print(./test.pl \7741266\ \DEM EXPO\ \255.255.255.255\ \n); and i am doing this @respon = $placesock-print(./test.pl. .$param1. .$param2. .$param3 \n); Try doing this instead: (untested) @respon = $placesock-print(./test.pl \$param1\ \$param2\ \$param3\\n); Whats the mistake i am commiting. i m getting the following error message... String found where operator expected at mybly.pl line 263, near ./test.pl . . $param1. (Missing operator before . $param1.?) panic: realloc at mybly.pl line 263. regards, Ajitpal Singh, HTH, Chuck -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/ http://learn.perl.org/first-response
RE: Delimiter for string..
I am running a perl script as below which is working perfectly and want to
replace the hardcoded values with variables.
(the script accepts space as the delimiter)
@respon = $placesock-print(./test.pl \7741266\ \DEM EXPO\
\255.255.255.255\ \n);
and i am doing this
@respon = $placesock-print(./test.pl. .$param1. .$param2. .$param3
\n);
Whats the mistake i am commiting.
The simple answer is that you are forgetting to escape
Really, I think you're getting confused about when you are in the s and
when you aren't.
The more complicated answer is how to get what you want. I'll give it a
try:
@respon = $placesock-print(./test.pl \.$param1.\ \.$param2.\
\.$param3.\ \n);
but that is way more complicated than it needs to be, since will replace
$var with it's value, so you should be able to do:
@respon = $placesock-print(./test.pl \$param1\ \$param2\ \$param3\
\n);
for me, that's a little hard to read, but others may prefer it. Another
option, if you don't put anything in s that needs to be replaced would be:
@respon = $placesock-print('./test.pl '.$param1.' '.$param2.'
'.$param3.' '.\n);
All three of these produce the same output as the hardcoded version that you
gave us when given proper values for $params
i m getting the following error message...
String found where operator expected at mybly.pl line 263, near
./test.pl
. . $param1.
(Missing operator before . $param1.?)
panic: realloc at mybly.pl line 263.
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