Re: Hi Folks : I'm trying to create a regular expression for finding a # wishing a dataset for only a number that is a multiple of 5
Thanks a lot
Gautam S Desai
On Sun, Sep 8, 2019 at 6:39 PM Mike wrote:
>
> It's probably best if you write a short script
> that reads a __DATA__ section of data.
> Then tell us what it does and what you expected
> it to do.
>
> Off hand I don't see anything wrong with your regex,
> but I don't know what you expect it to do.
>
>
> Mike
>
>
> On 9/8/2019 4:34 PM, Jim Gibson wrote:
> > On Sep 8, 2019, at 1:30 PM, Gautam Desai
> wrote:
> >> Do you guys have any pointers ?
> > $t =~ m{
> > ( # capture matched number in $1
> > \d* # match zero or more decimal digits
> > [05] # followed by a '0' or '5'
> > ) # end of capture
> > (?: # followed by either:
> > \D# a non-digit
> > | # or
> > $ # the end of the string
> > )
> > }x
> >
>
> --
> To unsubscribe, e-mail: beginners-unsubscr...@perl.org
> For additional commands, e-mail: beginners-h...@perl.org
> http://learn.perl.org/
>
>
>
Re: Hi Folks : I'm trying to create a regular expression for finding a # wishing a dataset for only a number that is a multiple of 5
> On Sep 8, 2019, at 6:36 PM, Olivier wrote:
>
> Jim Gibson writes:
>
>> On Sep 8, 2019, at 3:39 PM, Mike wrote:
>>>
>>>
>>> It's probably best if you write a short script
>>> that reads a __DATA__ section of data.
>>> Then tell us what it does and what you expected
>>> it to do.
>>>
>>> Off hand I don't see anything wrong with your regex,
>>> but I don't know what you expect it to do.
>>>
>>
>> I expect it to return a positive value if $t contains a number anywhere
>> within it and put that number in the $1 capture variable.
>
> Well, that is not what is in your regex: you look for a decimal number
> ending with 0 or 5, and it must be the last number of the line.
>
> What about something simple like:
>
>/(\d*[05])\D*$/
I prefer the explicit (?:…|…) structure that tells the reader that an alternate
expression is being used. Also, the “zero or more” * operator can be very slow
for long strings.
>
> The Regex Coach is your friend (and works well under wine).
>
> It alsways help to present with some sample data.
If you want to use this regex, then you should test it yourself. I did.
>
> Best regards,
>
> Olivier
>
>>>
>>> Mike
>>>
>>>
>>> On 9/8/2019 4:34 PM, Jim Gibson wrote:
On Sep 8, 2019, at 1:30 PM, Gautam Desai
wrote:
> Do you guys have any pointers ?
$t =~ m{
( # capture matched number in $1
\d* # match zero or more decimal digits
[05] # followed by a '0' or '5'
) # end of capture
(?: # followed by either:
\D# a non-digit
| # or
$ # the end of the string
)
}x
>>>
>>> --
>>> To unsubscribe, e-mail: beginners-unsubscr...@perl.org
>>> For additional commands, e-mail: beginners-h...@perl.org
>>> http://learn.perl.org/
>>>
>>>
>>
>> Jim Gibson
>> j...@gibson.org
>
> --
>
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Jim Gibson
j...@gibson.org
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Re: Hi Folks : I'm trying to create a regular expression for finding a # wishing a dataset for only a number that is a multiple of 5
Jim Gibson writes:
> On Sep 8, 2019, at 3:39 PM, Mike wrote:
>>
>>
>> It's probably best if you write a short script
>> that reads a __DATA__ section of data.
>> Then tell us what it does and what you expected
>> it to do.
>>
>> Off hand I don't see anything wrong with your regex,
>> but I don't know what you expect it to do.
>>
>
> I expect it to return a positive value if $t contains a number anywhere
> within it and put that number in the $1 capture variable.
Well, that is not what is in your regex: you look for a decimal number
ending with 0 or 5, and it must be the last number of the line.
What about something simple like:
/(\d*[05])\D*$/
The Regex Coach is your friend (and works well under wine).
It alsways help to present with some sample data.
Best regards,
Olivier
>>
>> Mike
>>
>>
>> On 9/8/2019 4:34 PM, Jim Gibson wrote:
>>> On Sep 8, 2019, at 1:30 PM, Gautam Desai
>>> wrote:
Do you guys have any pointers ?
>>> $t =~ m{
>>> ( # capture matched number in $1
>>> \d* # match zero or more decimal digits
>>> [05] # followed by a '0' or '5'
>>> ) # end of capture
>>> (?: # followed by either:
>>> \D# a non-digit
>>> | # or
>>> $ # the end of the string
>>> )
>>> }x
>>>
>>
>> --
>> To unsubscribe, e-mail: beginners-unsubscr...@perl.org
>> For additional commands, e-mail: beginners-h...@perl.org
>> http://learn.perl.org/
>>
>>
>
> Jim Gibson
> j...@gibson.org
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Re: Hi Folks : I'm trying to create a regular expression for finding a # wishing a dataset for only a number that is a multiple of 5
On Sep 8, 2019, at 3:39 PM, Mike wrote:
>
>
> It's probably best if you write a short script
> that reads a __DATA__ section of data.
> Then tell us what it does and what you expected
> it to do.
>
> Off hand I don't see anything wrong with your regex,
> but I don't know what you expect it to do.
>
I expect it to return a positive value if $t contains a number anywhere within
it and put that number in the $1 capture variable.
>
> Mike
>
>
> On 9/8/2019 4:34 PM, Jim Gibson wrote:
>> On Sep 8, 2019, at 1:30 PM, Gautam Desai
>> wrote:
>>> Do you guys have any pointers ?
>> $t =~ m{
>> ( # capture matched number in $1
>>\d* # match zero or more decimal digits
>>[05] # followed by a '0' or '5'
>> ) # end of capture
>> (?: # followed by either:
>>\D# a non-digit
>> | # or
>>$ # the end of the string
>> )
>> }x
>>
>
> --
> To unsubscribe, e-mail: beginners-unsubscr...@perl.org
> For additional commands, e-mail: beginners-h...@perl.org
> http://learn.perl.org/
>
>
Jim Gibson
j...@gibson.org
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Re: Hi Folks : I'm trying to create a regular expression for finding a # wishing a dataset for only a number that is a multiple of 5
It's probably best if you write a short script
that reads a __DATA__ section of data.
Then tell us what it does and what you expected
it to do.
Off hand I don't see anything wrong with your regex,
but I don't know what you expect it to do.
Mike
On 9/8/2019 4:34 PM, Jim Gibson wrote:
On Sep 8, 2019, at 1:30 PM, Gautam Desai wrote:
Do you guys have any pointers ?
$t =~ m{
( # capture matched number in $1
\d* # match zero or more decimal digits
[05] # followed by a '0' or '5'
) # end of capture
(?: # followed by either:
\D# a non-digit
| # or
$ # the end of the string
)
}x
--
To unsubscribe, e-mail: beginners-unsubscr...@perl.org
For additional commands, e-mail: beginners-h...@perl.org
http://learn.perl.org/
Re: Hi Folks : I'm trying to create a regular expression for finding a # wishing a dataset for only a number that is a multiple of 5
On Sep 8, 2019, at 1:30 PM, Gautam Desai wrote:
>
> Do you guys have any pointers ?
$t =~ m{
( # capture matched number in $1
\d* # match zero or more decimal digits
[05] # followed by a '0' or '5'
) # end of capture
(?: # followed by either:
\D# a non-digit
| # or
$ # the end of the string
)
}x
--
To unsubscribe, e-mail: beginners-unsubscr...@perl.org
For additional commands, e-mail: beginners-h...@perl.org
http://learn.perl.org/
