Re: dprofpp
On Fri, 13 Jan 2006, Gerard Robin wrote: > And, what are exactly Elapsed Time and User+System Time ? > > If i run time ./dprof1.pl the outputs are: > > real0m0.033s > user0m0.011s > sys 0m0.002s > > If i run time ./dprof3.pl the outputs are: > > real0m0.059s > user0m0.018s > sys 0m0.004s > > What relation exists between the times of "time" an te times of dprofpp ? The `times` manpage may help, as might `getrusage`: http://www.hmug.org/man/3/times.php http://www.hmug.org/man/2/getrusage.php http://publib16.boulder.ibm.com/pseries/en_US/libs/basetrf1/getrusage_64.htm The way that IBM version of the manpage is more oriented towards C programmers using the call, but the basic idea still gets through: This information is read from the calling process as well as from each completed child process for which the calling process executed a wait subroutine. tms_utime The CPU time used for executing instructions in the user space of the calling process tms_stime The CPU time used by the system on behalf of the calling process. tms_cutime The sum of the tms_utime and the tms_cutime values for all the child processes. tms_cstime The sum of the tms_stime and the tms_cstime values for all the child processes. Note: The system measures time by counting clock interrupts. The precision of the values reported by the times subroutine depends on the rate at which the clock interrupts occur. Helpful? -- Chris Devers DO NOT LEAVE IT IS NOT REAL -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] <http://learn.perl.org/> <http://learn.perl.org/first-response>
dprofpp
Hello, I am runing an example (in Debbugging Perl of Martin Brown) there are two scripts which product the same output but one contains three subroutines and the other only one subroutine. The outputs: "3 subroutines" ~~ Total Elapsed Time = 0.199198 Seconds User+System Time = 0.029198 Seconds Exclusive Times %Time ExclSec CumulS #Calls sec/call Csec/c Name 34.2 0.010 0.009 1 0.0098 0.0092 main::process 0.00 - -0.000 1- - warnings::BEGIN 0.00 - -0.000 1- - warnings::import 0.00 - -0.000 1- - strict::bits 0.00 - -0.000 1- - strict::import 0.00 - -0.000 2- - main::BEGIN 0.00 - -0.000197- - main::add_to_datetime 0.00 - -0.001197- - main::process_fields "1 subroutine" ~ Total Elapsed Time = 0.189979 Seconds User+System Time = 0.009979 Seconds Exclusive Times %Time ExclSec CumulS #Calls sec/call Csec/c Name 100. 0.010 0.010 1 0.0100 0.0100 warnings::BEGIN 0.00 - -0.000 1- - warnings::import 0.00 - -0.000 1- - strict::bits 0.00 - -0.000 1- - main::process 0.00 - -0.000 1- - strict::import 0.00 - 0.010 2- 0.0050 main::BEGIN the man dprofpp is enough clear, but: In "1 subroutine" I understand %time 100 % but in "3 subroutines" I see %time 34.2 in main::process, where are the 65.8 % ? And, what are exactly Elapsed Time and User+System Time ? If i run time ./dprof1.pl the outputs are: real0m0.033s user0m0.011s sys 0m0.002s If i run time ./dprof3.pl the outputs are: real0m0.059s user0m0.018s sys 0m0.004s What relation exists between the times of "time" an te times of dprofpp ? tia -- Gérard -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] <http://learn.perl.org/> <http://learn.perl.org/first-response>
