regex capturing
$\ = \n;
$date = 20020731;
print join /, ($date =~ /(\d{4})(\d{2})(\d{2})/)[1,2,0]; # this works
print join /, ($date =~ /(\d{4})(\d{2}){2}/)[1,2,0]; # this doesn't
__END__
why did the second pattern not capture the second occurance of \d{2} ?
Is this the correct action? or should it capture the second one in the
second example?
Is there a way to capture like so (like second example as I expected it to
work)?
Nikola Janceski
If you enjoy what you do, you'll never work another day in your life.
-- Confucius
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Re: regex capturing
To capture the second occurance you have to surround the {2} with parens.
print join /, ($date =~ /(\d{4})(\d{2}{2})/)[1,2,0]
Tanton
- Original Message -
From: Nikola Janceski [EMAIL PROTECTED]
To: Beginners (E-mail) [EMAIL PROTECTED]
Sent: Wednesday, July 31, 2002 11:27 AM
Subject: regex capturing
$\ = \n;
$date = 20020731;
print join /, ($date =~ /(\d{4})(\d{2})(\d{2})/)[1,2,0]; # this works
print join /, ($date =~ /(\d{4})(\d{2}){2}/)[1,2,0]; # this doesn't
__END__
why did the second pattern not capture the second occurance of \d{2} ?
Is this the correct action? or should it capture the second one in the
second example?
Is there a way to capture like so (like second example as I expected it to
work)?
Nikola Janceski
If you enjoy what you do, you'll never work another day in your life.
-- Confucius
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RE: regex capturing
Nested quantifiers before HERE mark in regex m/(\d{4})(\d{2}{ HERE 2})/
at line.
when i do that, so that's not the answer.
print join /, ($date =~ /(\d{4})(\d{2}{2})/)[1,2,0];
-Original Message-
From: Tanton Gibbs [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, July 31, 2002 11:55 AM
To: Nikola Janceski; Beginners (E-mail)
Subject: Re: regex capturing
To capture the second occurance you have to surround the {2}
with parens.
print join /, ($date =~ /(\d{4})(\d{2}{2})/)[1,2,0]
Tanton
- Original Message -
From: Nikola Janceski [EMAIL PROTECTED]
To: Beginners (E-mail) [EMAIL PROTECTED]
Sent: Wednesday, July 31, 2002 11:27 AM
Subject: regex capturing
$\ = \n;
$date = 20020731;
print join /, ($date =~ /(\d{4})(\d{2})(\d{2})/)[1,2,0];
# this works
print join /, ($date =~ /(\d{4})(\d{2}){2}/)[1,2,0]; #
this doesn't
__END__
why did the second pattern not capture the second occurance
of \d{2} ?
Is this the correct action? or should it capture the second
one in the
second example?
Is there a way to capture like so (like second example as I
expected it to
work)?
Nikola Janceski
If you enjoy what you do, you'll never work another day in
your life.
-- Confucius
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RE: regex capturing
-Original Message-
From: Nikola Janceski [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, July 31, 2002 11:27 AM
To: Beginners (E-mail)
Subject: regex capturing
$\ = \n;
$date = 20020731;
print join /, ($date =~ /(\d{4})(\d{2})(\d{2})/)[1,2,0]; #
this works
print join /, ($date =~ /(\d{4})(\d{2}){2}/)[1,2,0]; # this doesn't
__END__
why did the second pattern not capture the second occurance of \d{2} ?
But it does capture the second occurrence (the 31). It doesn't capture
the first (the 07).
In the absence of /g, it would seem that since there are only two
sets of parens in the second regex, only two values can be captured.
The {2} quanitifier would simply cause $2 to be reused.
Is this the correct action? or should it capture the second one in the
second example?
Is there a way to capture like so (like second example as I
expected it to
work)?
I would think /g would have to be used somehow, but I do not know
how.
Of course, the simple:
/(\d{2})/g
works, returning '20', '02', '07', '31'.
But that's not what you're after.
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RE: regex capturing
Correct actually. It just didn't dawn on me that $2 was being reused but
that is unlike perl to do that.
I would have thought that it would know that I wanted 2 captures. So is this
just a new issue that hasn't come up before? or is it something seen just
nothing done about it?
I am using the first example anyway because I need it working now, but I was
curious to learn if this is a problem/bug or if this was the intended
result. Perldocs didn't have much about this kind of situation, so I don't
know what the intended result would be.
-Original Message-
From: Bob Showalter [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, July 31, 2002 12:21 PM
To: 'Nikola Janceski'; Beginners (E-mail)
Subject: RE: regex capturing
But it does capture the second occurrence (the 31). It doesn't capture
the first (the 07).
In the absence of /g, it would seem that since there are only two
sets of parens in the second regex, only two values can be captured.
The {2} quanitifier would simply cause $2 to be reused.
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Re: regex capturing
Nikola Janceski wrote at Wed, 31 Jul 2002 17:27:22 +0200:
$\ = \n;
$date = 20020731;
print join /, ($date =~ /(\d{4})(\d{2})(\d{2})/)[1,2,0]; # this works
print join /, ($date =~ /(\d{4})(\d{2}){2}/)[1,2,0]; # this doesn't
__END__
why did the second pattern not capture the second occurance of \d{2} ?
Is this the correct action? or should it capture the second one in the
second example?
The second pattern matches only these 12 days in a year:
Jan 01
Feb 02
Mar 03
Apr 04
May 05
Jun 06
Jul 07
Aug 08
Sep 09
Oct 10
Nov 11
Dec 12
Cheerio,
Janek
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RE: regex capturing
-Original Message-
From: Janek Schleicher [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, July 31, 2002 2:14 PM
To: [EMAIL PROTECTED]
Subject: Re: regex capturing
Nikola Janceski wrote at Wed, 31 Jul 2002 17:27:22 +0200:
$\ = \n;
$date = 20020731;
print join /, ($date =~ /(\d{4})(\d{2})(\d{2})/)[1,2,0];
# this works
print join /, ($date =~ /(\d{4})(\d{2}){2}/)[1,2,0]; #
this doesn't
__END__
why did the second pattern not capture the second occurance
of \d{2} ?
Is this the correct action? or should it capture the second
one in the
second example?
The second pattern matches only these 12 days in a year:
Jan 01
Feb 02
Mar 03
Apr 04
May 05
Jun 06
Jul 07
Aug 08
Sep 09
Oct 10
Nov 11
Dec 12
Huh?
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RE: regex capturing
Bob Showalter wrote at Wed, 31 Jul 2002 21:34:02 +0200:
$\ = \n;
$date = 20020731;
print join /, ($date =~ /(\d{4})(\d{2})(\d{2})/)[1,2,0];
# this works
print join /, ($date =~ /(\d{4})(\d{2}){2}/)[1,2,0]; #
this doesn't
The second pattern matches only these 12 days in a year:
.
Huh?
Oops, forget what I wrote.
I just read too quick and so I read it as something
like (\d{4})(\d{2})\1
Bye,
Janek
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