Re: Arithmetic pow results incorrect in arithmetic expansion.
9 Ocak 2021 Cumartesi tarihinde Ilkka Virta yazdı: > > Note that binary minus doesn't really compare here. It has a lower > precedence, so gives a different result: > Yes, you are right, and not only that, but the example I gave doesn't even work on 5.1. $ (( 16#-10 )) bash: ((: 16#: invalid integer constant (error token is "16#") -- Oğuz
Re: Arithmetic pow results incorrect in arithmetic expansion.
On Sat, Jan 9, 2021 at 9:14 AM Robert Elz wrote: > Not "all" other shells, most don't implement exponentiation at all, > since it isn't a standard C operator. > Which also means that the statement about the operators being "same as in the C language" doesn't really help figure out how this particular one works. Which is probably why Zsh has explicitly mentioned it.
Re: Arithmetic pow results incorrect in arithmetic expansion.
On Sat, Jan 9, 2021 at 7:22 AM Oğuz wrote: > 9 Ocak 2021 Cumartesi tarihinde Hyunho Cho yazdı: > > $ echo $(( -2 ** 2 )) # only bash results in 4 > > 4 > `bc' does that too. Here's another trivial side effect of implementing > unary minus using binary minus: > Note that binary minus doesn't really compare here. It has a lower precedence, so gives a different result: $ echo $(( -3 ** 2 )) 9 $ echo $(( 0 - 3 ** 2 )) -9
