Re: ${variable@A} does not work for associative arrays

[Eli Schwartz]

On 2/19/20 3:05 PM, Arfrever Frehtes Taifersar Arahesis wrote:
> BASH 5.0.16.
> 
> $ VAR1=aaa
> $ declare -a VAR2=(aaa)
> $ declare -A VAR3=([aaa]=aaa)
> $ declare -p VAR{1,2,3}
> declare -- VAR1="aaa"
> declare -a VAR2=([0]="aaa")
> declare -A VAR3=([aaa]="aaa" )
> $ echo "${VAR1@A}"
> VAR1='aaa'
> $ echo "${VAR2@A}"
> declare -a VAR2='aaa'


Well, that looks a bit off.

$ VAR2=(aaa )
$ echo "${VAR2@A}"
declare -a VAR2='aaa'
$ echo "${VAR2[@]@A}"
declare -a VAR2=([0]="aaa" [1]="")

I suggest next time, do your tests with a multi-element indexed array,
since it will make it obvious when your test case is incorrectly
printing only one element.

> $ echo "${VAR3@A}"
> 
> $
> 
> --
> Arfrever Frehtes Taifersar Arahesis
> 


-- 
Eli Schwartz
Bug Wrangler and Trusted User



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Re: ${variable@A} does not work for associative arrays

[Chet Ramey]

On 2/19/20 3:05 PM, Arfrever Frehtes Taifersar Arahesis wrote:
> BASH 5.0.16.
> 
> $ VAR1=aaa
> $ declare -a VAR2=(aaa)
> $ declare -A VAR3=([aaa]=aaa)
> $ declare -p VAR{1,2,3}
> declare -- VAR1="aaa"
> declare -a VAR2=([0]="aaa")
> declare -A VAR3=([aaa]="aaa" )
> $ echo "${VAR1@A}"
> VAR1='aaa'
> $ echo "${VAR2@A}"
> declare -a VAR2='aaa'
> $ echo "${VAR3@A}"

Referring to an array variable without a subscript is equivalent to
referencing element 0.

-- 
``The lyf so short, the craft so long to lerne.'' - Chaucer
 ``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, UTech, CWRUc...@case.eduhttp://tiswww.cwru.edu/~chet/

${variable@A} does not work for associative arrays

[Arfrever Frehtes Taifersar Arahesis]

BASH 5.0.16.

$ VAR1=aaa
$ declare -a VAR2=(aaa)
$ declare -A VAR3=([aaa]=aaa)
$ declare -p VAR{1,2,3}
declare -- VAR1="aaa"
declare -a VAR2=([0]="aaa")
declare -A VAR3=([aaa]="aaa" )
$ echo "${VAR1@A}"
VAR1='aaa'
$ echo "${VAR2@A}"
declare -a VAR2='aaa'
$ echo "${VAR3@A}"

$

--
Arfrever Frehtes Taifersar Arahesis