Bernd,
Thank you so very much!!! I would have never figured that out
on my own. I went back to the Advanced Bash Scripting Guide
(by Mendel Cooper) to see if this example would make a good
addition. Searching on your use of Here Strings (e.g. ).
I found on page 326 (18.1. Here Strings) a the following method
that also works quite well.
read -r -a FileList $(ls -1)
I wish that I had noticed the Here Strings feature before. That
is a great feature.
Thank you both for your time and contributions!
Regards
Brad
Reference:
Advanced Bash Scripting Guide
http://personal.riverusers.com/~thegrendel/abs-guide.pdf
On Tue, 2008-02-12 at 10:13 +0100, Bernd Eggink wrote:
Brad Diggs schrieb:
In short the bug is the result of failure to expand the
subscript of an array if the subscript is a variable.
The following script should return a list of files with a
preceding (File #: ). However, it does not work that
way because the integer variable (${d}) used in the subscript
of the array statement (FileList[${d}]=${File}) does not get
properly expanded.
#!/bin/bash
declare -a FileList=('')
declare -i d=0
ls -1| while read File
do
FileList[${d}]=${File}
d=$((10#${d}+1))
done
This is normal bash behaviour, see FAQ E4. As bash executes _all_ parts
of a pipe in subshells (in contrast to ksh, where the last component is
executed in the current shell), the variable 'FileList' being assigned
here is local to the subshell. After the loop the variable 'FileList'
declared in line 1 (which happens to have the same name, but that
doesn't matter) is unchanged.
Try this instead:
while read File
do
FileList[d]=$File
(( d=d+1 ))
done $(ls -1)
Greetings,
Bernd
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