basic pattern match Question...newbie doesn't understand (!...@#$@$)

2010-08-01 Thread Linda Walsh 


I have:

w=/home/law/bin/package: line 5: type: xx: not found

The =~ operator is suppose to use the RH Expr as a ext.-regex.

So why doesn't this match and print not found?

if [[ $w =~ .*not found.* ]]; then echo not found; fi

It prints nothing.  Seems like such a basic concept.   Sorry, this newbie
needs help on such trivial matters. :-(


 echo $BASH_VERSION
4.0.35(1)-release

Re: basic pattern match Question...newbie doesn't understand (!...@#$@$)

2010-08-01 Thread Chris F.A. Johnson 

On Sun, 1 Aug 2010, Linda Walsh wrote:


I have:

w=/home/law/bin/package: line 5: type: xx: not found

The =~ operator is suppose to use the RH Expr as a ext.-regex.

So why doesn't this match and print not found?

if [[ $w =~ .*not found.* ]]; then echo not found; fi

It prints nothing.  Seems like such a basic concept.   Sorry, this newbie
needs help on such trivial matters. :-(


   When quoted, the right-hand argument is matched as a string, not an
   expression.

--
   Chris F.A. Johnson, http://cfajohnson.com
   Author:
   Pro Bash Programming: Scripting the GNU/Linux Shell (2009, Apress)
   Shell Scripting Recipes: A Problem-Solution Approach (2005, Apress)