On Fri, 2015-01-16 at 12:52 -0800, Parke wrote:
> It appears that if there are no normal prerequisites, $< will ignore
> any order-only prerequisites.
>
> This is not the behavior I expected, and I could not find
> documentation describing this behavior.
I agree it should be documented explicitly, but I don't necessarily
think it's wrong.
You may note that the $^ variable doesn't contain order-only
prerequisites either. The idea is that prerequisites that are
order-only are qualitatively different than normal prerequisites;
they're there only to ensure things happen in a particular order. The
manual gives a hint:
http://www.gnu.org/software/make/manual/html_node/Prerequisite-Types.html
when it says that order-only prerequisites don't create a "dependency
relationship"; because of this they aren't included in the normal
dependency variables like $^ and $<.
If the prerequisite needed to be both ordered AND create a dependency
relationship, then it would be a normal prerequisite not an order-only
prerequisite.
> foo bar:
> @ echo $@ $<
If you really want this behavior, you can write:
foo bar:
@ echo $@ $(firstword $< $|)
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