Dynamic Div styling question
So I am working on a helper which I want to dynamically set the div's size.
I am using this:
echo $this->Html->style(array('height' => '200px',));
But only getting this:
height: 200px;
Where as I want something like this:
div#mycontainer{ height: 200px; }
Does anyone know how to use the HTML->style function with div's &
brackets? Thanks
~Michael
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Re: pagination problem, please help
thank you Ivan,... I have tried that by the book,... and probably missed
something on its way in a first place,...
well,... this is what I got now, and it's working,
function category($id = null)
{
if($this->is_user())
{
$this->set('user_obj', $user =
$this->User->findById($this->user['id']));
}
$filter = $this->params['pass'];
$this->set('url_options', $filter);
$category = $id;
$cat_id = array_search($category,
Configure::read('Blog.blog_category'));
$this->set('category', $category);
$this->paginate = array('Blog' => array('conditions' =>
array('Blog.categories' => $cat_id), 'limit' => 12, 'recursive' => 1));
$blogs = $this->paginate('Blog');
$this->set('blogs', $blogs);
}
On Sunday, November 18, 2012 1:52:17 PM UTC-8, ivnrmc wrote:
>
> i think this is your answer:
>
> function category($id = null){
>
> if($this->is_user()) {
> $this->set('user_obj', $user =
> $this->User->findById($this->user['id']));
> }
>
> $category = $id;
> $cat_id = array_search($category,
> Configure::read('Blog.blog_category'));
>
> $this->paginate = array('Blog' => array('conditions' =>
> array('Blog.categories' => $cat_id), 'limit' => 12, 'recursive' => -1));
> $blogs = $this->paginate('Blog');
>
> $this->set(compact('blogs', 'category'));
> }
>
>
> On Sun, Nov 18, 2012 at 9:05 PM, Chris >wrote:
>
>> hi guys,... I have a problem with pagination in a controller,... can
>> someone help me please,...
>> I'm getting an error: SQL Error: 1054: Unknown column 'limit' in 'where
>> clause'
>>
>> how can I do this,...?
>>
>> function category($id = null)
>> {
>> if($this->is_user())
>> {
>> $this->set('user_obj', $user =
>> $this->User->findById($this->user['id']));
>> }
>>
>> $category = $id;
>>
>> $cat_id = array_search($category,
>> Configure::read('Blog.blog_category'));
>>
>> $this->set('category', $category);
>>
>> $blogs = $this->Blog->find('all', array('conditions' =>
>> array('Blog.categories' => $cat_id)));
>>
>> $this->set('blogs', $blogs, $this->paginate('Blog', array('limit'
>> => 12) ));
>>
>> thanks in advance,
>> chris
>>
>> --
>> Like Us on FaceBook https://www.facebook.com/CakePHP
>> Find us on Twitter http://twitter.com/CakePHP
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>> ---
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>> .
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>> Visit this group at http://groups.google.com/group/cake-php?hl=en.
>>
>>
>>
>
>
>
> --
> *Ivan Rimac***
> mail: ivn...@gmail.com
> *tel: +385 95 555 99 66*
> *http://ivanrimac.com*
>
>
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Re: Cake php
write the stored proceedure, use $this->model->query() to invoke it? On Mon, Nov 19, 2012 at 1:11 AM, John james wrote: > i want to use storedprocedure in cake php can any body tell me how to do > it ? > > -- > Like Us on FaceBook https://www.facebook.com/CakePHP > Find us on Twitter http://twitter.com/CakePHP > > --- > You received this message because you are subscribed to the Google Groups > "CakePHP" group. > To post to this group, send email to cake-php@googlegroups.com. > To unsubscribe from this group, send email to > cake-php+unsubscr...@googlegroups.com. > Visit this group at http://groups.google.com/group/cake-php?hl=en. > > > -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups "CakePHP" group. To post to this group, send email to cake-php@googlegroups.com. To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php?hl=en.
Re: how to implement Smarty 3?
hi, for cool views can use this framework http://twitter.github.com/bootstrap/ and cakephp views. And check this to http://angularjs.org/ regards 2012/11/17 Martin Aguilar > For years I've been working on my own framework but now I wan't to migrate > to cakephp. > On my framework I used smarty for themes and to separate code from views. > I always find smarty clean, nice and with a very good performance. > Now I want to use it on cake but I found people saying that it has no > purpose. > And couldn't find a good article about implementing it. The only thing > that I found it's for cake 1.3 and smarty 2 and the article it's damage. > > http://bakery.cakephp.org/articles/tclineks/2006/10/27/how-to-use-smarty-with-cake-smartyviewOn > point 4, I see a lot of unreadable symbols. > > Any help on implementing smarty 3 on cake 2? > What it's your opinion on implementing smarty or any other template system? > > Thanks a lot > > -- > Like Us on FaceBook https://www.facebook.com/CakePHP > Find us on Twitter http://twitter.com/CakePHP > > --- > You received this message because you are subscribed to the Google Groups > "CakePHP" group. > To post to this group, send email to cake-php@googlegroups.com. > To unsubscribe from this group, send email to > cake-php+unsubscr...@googlegroups.com. > Visit this group at http://groups.google.com/group/cake-php?hl=en. > > > -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups "CakePHP" group. To post to this group, send email to cake-php@googlegroups.com. To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php?hl=en.
Accessing fields of 'Events' model to compare user_id.
Hi all
I am fairly new to CakePHP, I am trying to only allow those users who
created an event to be able to edit or delete an event, so I am comparing
the current user id, with the 'user_id' field of the event the current
event (saved when a user creates an event). Any help would be appreciated
thanks, my code(Andrew Perk) is as follows:
public function isAuthorized($user) {
$this->loadModel('User');
if ($user['role'] == 'admin') {
return true;
}
if (in_array($this->action, array('edit', 'delete'))) {
if ($user['id'] != $this->request->data['Event']['user_id']) {
THIS IS THE LINE I FEEL IS WRONG - PLEASE ADVISE
//echo debug($event['user_id']);
//$this->Session->setFlash(__('You are not allowed to edit
someones event'));
return false;
}
}
return true;
}
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Re: Tab index
This is a really old post, but just in case anyone else is searching and
finds this (like I did)...
Here's how you add *tabindex* with the Form Helper:
$this->Form->input('foo', array(*'tabindex' => '1'*, [other options...]));
$this->Form->input('bar', array(*'tabindex' => '2'*, [other options...]));
On Thursday, September 16, 2010 1:14:23 PM UTC-5, Jeremy Burns wrote:
>
> I'm having a bad form day. My forms, built using the form helper and
> using $this->Form->input have no sensible tab order. It seems that
> inputs that result in a select list (for example, date fields) cannot
> be tabbed into at all. I have tried setting the tabindex values, but
> they do not control form flow. I have tested this in Firefox, Chrome
> and Safari - all produce the same result.
>
> Any clues?
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Cake php
i want to use storedprocedure in cake php can any body tell me how to do it ? -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups "CakePHP" group. To post to this group, send email to cake-php@googlegroups.com. To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php?hl=en.
how to implement Smarty 3?
For years I've been working on my own framework but now I wan't to migrate to cakephp. On my framework I used smarty for themes and to separate code from views. I always find smarty clean, nice and with a very good performance. Now I want to use it on cake but I found people saying that it has no purpose. And couldn't find a good article about implementing it. The only thing that I found it's for cake 1.3 and smarty 2 and the article it's damage. http://bakery.cakephp.org/articles/tclineks/2006/10/27/how-to-use-smarty-with-cake-smartyviewOn point 4, I see a lot of unreadable symbols. Any help on implementing smarty 3 on cake 2? What it's your opinion on implementing smarty or any other template system? Thanks a lot -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups "CakePHP" group. To post to this group, send email to cake-php@googlegroups.com. To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php?hl=en.
Re: Calling MySQL5 Stored Procedures
I have to call a store procedure on my cakephp can anybpdy tell me how to
do it ?
On Tuesday, October 16, 2007 8:11:46 PM UTC+5, beverly.guillermo wrote:
>
> Hi all,
>
> Just thought I'd post my workaround based on some of the posts here
> but I didn't see a consistent answer to the issue. My environment is
> PHP 5.2.3, Apache 2.2.6, and MySQL 5.0.41-community.
>
> So, here's the problem, I have a stored procedure that I want to call
> in Cake. When I try to run the $this->model->query("call
> sp_mine(params)"); or $this->model->_call, I don't get anything back
> and an mysql error occurs.
>
>Error 1312 - PROCEDURE <...> can't return a result set in the given
> context: nothing returned
>
> To resolve this, I had to modify the connect call to the database in
> dbo_mysql.php to include a client flag, specifically
> CLIENT_MULTI_RESULTS or CLIENT_MULTI_STATEMENTS or 65536. But after
> implementing this and calling my stored procedure I go another mysql
> error:
>
> Error 2014 - Commands out of sync; you can't run this command now
>
> I get this for any query or execute that I attempt to call. And per a
> post from blunt, I added this function
>
> function releaseDB() {
> $db =& ConnectionManager::getDataSource($this->useDbConfig);
> $db->disconnect();
> $db->connect();
> }
>
> to my model_php5.php. After every sp call, I call that method.
>
>
> If anyone has a better resolution or if it's fixed in the current cake
> version and I'm not doing something right, then let me know. :P
>
> Thanks,
> Beverly
>
>
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Re: pagination problem, please help
i think this is your answer:
function category($id = null){
if($this->is_user()) {
$this->set('user_obj', $user =
$this->User->findById($this->user['id']));
}
$category = $id;
$cat_id = array_search($category,
Configure::read('Blog.blog_category'));
$this->paginate = array('Blog' => array('conditions' =>
array('Blog.categories' => $cat_id), 'limit' => 12, 'recursive' => -1));
$blogs = $this->paginate('Blog');
$this->set(compact('blogs', 'category'));
}
On Sun, Nov 18, 2012 at 9:05 PM, Chris wrote:
> hi guys,... I have a problem with pagination in a controller,... can
> someone help me please,...
> I'm getting an error: SQL Error: 1054: Unknown column 'limit' in 'where
> clause'
>
> how can I do this,...?
>
> function category($id = null)
> {
> if($this->is_user())
> {
> $this->set('user_obj', $user =
> $this->User->findById($this->user['id']));
> }
>
> $category = $id;
>
> $cat_id = array_search($category,
> Configure::read('Blog.blog_category'));
>
> $this->set('category', $category);
>
> $blogs = $this->Blog->find('all', array('conditions' =>
> array('Blog.categories' => $cat_id)));
>
> $this->set('blogs', $blogs, $this->paginate('Blog', array('limit' =>
> 12) ));
>
> thanks in advance,
> chris
>
> --
> Like Us on FaceBook https://www.facebook.com/CakePHP
> Find us on Twitter http://twitter.com/CakePHP
>
> ---
> You received this message because you are subscribed to the Google Groups
> "CakePHP" group.
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> cake-php+unsubscr...@googlegroups.com.
> Visit this group at http://groups.google.com/group/cake-php?hl=en.
>
>
>
--
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mail: ivn...@gmail.com
*tel: +385 95 555 99 66*
*http://ivanrimac.com*
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pagination problem, please help
hi guys,... I have a problem with pagination in a controller,... can
someone help me please,...
I'm getting an error: SQL Error: 1054: Unknown column 'limit' in 'where
clause'
how can I do this,...?
function category($id = null)
{
if($this->is_user())
{
$this->set('user_obj', $user =
$this->User->findById($this->user['id']));
}
$category = $id;
$cat_id = array_search($category,
Configure::read('Blog.blog_category'));
$this->set('category', $category);
$blogs = $this->Blog->find('all', array('conditions' =>
array('Blog.categories' => $cat_id)));
$this->set('blogs', $blogs, $this->paginate('Blog', array('limit' =>
12) ));
thanks in advance,
chris
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Re: Session is not expiring when browser is closed
you really should not rely on that! this is a browser-specific setting and most people have their browser in "default" mode - meaning: the session will not expire anyway so there is no point in forcing this - IMO Am Sonntag, 18. November 2012 15:33:47 UTC+1 schrieb Chandru M: > > Thanks for the response. > > However the issue is only with the settings. > > Set "On Startup" setting to "Continue where I left off" > (chrome://chrome/settings/) > > But I am using the setting > > "On Startup" setting to "Open the New Tab page" > > I am not sure where the problem starts. > > I didn't get much support for this issue till now. > > > > > On Sunday, November 11, 2012 1:09:47 PM UTC+5:30, Andras Kende wrote: >> >> In Chrome thats a settings unfortunately not cakephp related: >> >> http://code.google.com/p/chromium/issues/detail?id=130291 >> >> not sure about Mozilla... >> >> Andras Kende >> http://www.kende.com >> >> >> On Nov 10, 2012, at 3:15 AM, Chandru M wrote: >> >> Hi all, >> >> I am struck with this peculiar problem for a long time. >> >> I have created a simple login page using the auth component. >> >> It seems the session is not getting expired when the browser is closed. >> >> The user gets automatically logged in when the browser is open again. >> >> I have used the suggestions given in the following URL. But still the >> problem persists. >> >> http://bakery.cakephp.org/articles/admad/2...g-to-your-needs >> >> I also tried by changing the Security.level property to High. >> >> I am using CAKephp 2.1.3 >> >> PHP 5.3.10 >> >> I am not sure where i am missing the configuration. >> >> I have also tried with the default settings >> >> I have tried this in the browsers Mozilla and Chrome. >> >> Any help? >> >> -- >> Like Us on FaceBook https://www.facebook.com/CakePHP >> Find us on Twitter http://twitter.com/CakePHP >> >> --- >> You received this message because you are subscribed to the Google Groups >> "CakePHP" group. >> To post to this group, send email to cake...@googlegroups.com. >> To unsubscribe from this group, send email to >> cake-php+u...@googlegroups.com. >> Visit this group at http://groups.google.com/group/cake-php?hl=en. >> >> >> >> >> -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups "CakePHP" group. To post to this group, send email to cake-php@googlegroups.com. To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php?hl=en.
Re: Session is not expiring when browser is closed
Thanks for the response. However the issue is only with the settings. Set "On Startup" setting to "Continue where I left off" (chrome://chrome/settings/) But I am using the setting "On Startup" setting to "Open the New Tab page" I am not sure where the problem starts. I didn't get much support for this issue till now. On Sunday, November 11, 2012 1:09:47 PM UTC+5:30, Andras Kende wrote: > > In Chrome thats a settings unfortunately not cakephp related: > > http://code.google.com/p/chromium/issues/detail?id=130291 > > not sure about Mozilla... > > Andras Kende > http://www.kende.com > > > On Nov 10, 2012, at 3:15 AM, Chandru M > > wrote: > > Hi all, > > I am struck with this peculiar problem for a long time. > > I have created a simple login page using the auth component. > > It seems the session is not getting expired when the browser is closed. > > The user gets automatically logged in when the browser is open again. > > I have used the suggestions given in the following URL. But still the > problem persists. > > http://bakery.cakephp.org/articles/admad/2...g-to-your-needs > > I also tried by changing the Security.level property to High. > > I am using CAKephp 2.1.3 > > PHP 5.3.10 > > I am not sure where i am missing the configuration. > > I have also tried with the default settings > > I have tried this in the browsers Mozilla and Chrome. > > Any help? > > -- > Like Us on FaceBook https://www.facebook.com/CakePHP > Find us on Twitter http://twitter.com/CakePHP > > --- > You received this message because you are subscribed to the Google Groups > "CakePHP" group. > To post to this group, send email to cake...@googlegroups.com > . > To unsubscribe from this group, send email to > cake-php+u...@googlegroups.com . > Visit this group at http://groups.google.com/group/cake-php?hl=en. > > > > > -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups "CakePHP" group. To post to this group, send email to cake-php@googlegroups.com. To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php?hl=en.
Re: Bad Request "URL not found" - after an JQuery change event
A. To debug, I'd insert the line:
console.log(load + _this.find('option:selected').val());
just above your $.ajax() call. Then watch your Javascript console when
running the page to see what URL is being submitted and try submitting it
manually.
- Rob
On Friday, November 16, 2012 1:53:13 AM UTC-5, Benjamin Such wrote:
>
> Hey guys, I am really stuck with that problem. I have a JQuery Dialog
> which contains a selectbox. When I change the option inside this selectbox,
> another selectbox shows up with options generated from an .ajax() event.
> Anyway... everything works fine, but when I submit the form CakePHP says:
> 404 Bad Request - URL was not found, but it DOES EXISTS 100%. I tested it
> several times to be sure, but another thing is: When submit the form
> WITHOUT selecting any option from the first selectbox the form is submitted
> correctly. I dont know what to post really but here is my Javascript:
>
> $('select[data-onchange=true]').live("change", function() {
>>
>> var _this = $(this);
>> var element = $('select[data-onchange-trigger=' +
>> _this.attr("id") + ']:first');
>>
>> if (typeof element == "object") {
>> if (_this.attr("data-onchange-load")) {
>> var options = element.prop("options");
>> var load = _this.attr("data-onchange-load");
>> $.ajax({
>> dataType: "json",
>> url: load + _this.find('option:selected').val(),
>> beforeSend: function() {
>> $('.ajax-loader').show();
>> element.find('option').remove();
>> element.parent().hide();
>> },
>> success: function(data) {
>> $.each(data, function(index, _data) {
>> if (typeof _data == "object") {
>> $.each(_data, function(index, _data) {
>> options[options.length] = new Option(_
>> data.name, _data.id);
>> });
>> }
>> });
>> element.parent().show();
>> },
>> complete: function() {
>> $('.ajax-loader').hide();
>> }
>> });
>> }
>> }
>> });
>>
>
> The error occurs only when I submit the form after I change the option on
> the selectbox.
>
>
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