Re: Login
Very thanks Norman thats a smarter solution On Jul 22, 12:38 am, Norman Paniagua normanpania...@gmail.com wrote: I think you want to access the login something likehttp://localhost/login(ifcake is in your webroot folder) then you need to add a rule in the config/routes.php Router::connect('/login', array('controller'='users', 'action'='login')); --- Norman Paniagua Desarrollo / WSDcamp + 595 981 184 430www.webcamp.com Este correo contiene información confidencial y NO debe ser reenviada a otro destinatario sin la autorización del remitente. Si Ud. recibe este correo por error favor informe al remitente y elimine completamente la información recibida. 2010/7/21 Germano germano.c...@gmail.com I can create a model and define it as Auth userModel on beforeFielter callback of your AppController. function beforeFilter() { $this-Auth-userModel = 'Login'; . . . } and you can define inflections on bootstrap.php for pural of login become login to, and create LoginController as your user authentication controller. On 21 jul, 14:19, Velmurugan Kuberan vkube...@gmail.com wrote: Hi, I just want to create a login controller in cake.. the url will probably like thishttp://localhost/cake/login/ifi named the controller like loginshttp://localhost/cake/logins/it'll not sounds good... is there any way of making the standalone controller for login... i don't want it to be like thishttp://localhost/cakephp/users/login.. Thanks Check out the new CakePHP Questions sitehttp://cakeqs.organd help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.comcake-php%2bunsubscr...@googlegroups.c omFor more options, visit this group at http://groups.google.com/group/cake-php?hl=en Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en
Login
Hi, I just want to create a login controller in cake.. the url will probably like this http://localhost/cake/login/ if i named the controller like logins http://localhost/cake/logins/ it 'll not sounds good... is there any way of making the standalone controller for login... i don't want it to be like this http://localhost/cakephp/users/login.. Thanks Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en
Javascript include error
I create a default layout and added css and javascript into it like the following, For CSS I added the following lines in the head section of the default.ctp in layout folder echo $html-css('reset', 'stylesheet', array(media=screen)).\r \n; echo $html-css('style', 'stylesheet', array(media=screen)).\r \n; echo $html-css('invalid', 'stylesheet', array(media=screen)).\r \n\r\n; It worked finely. Then I need to add javascript functionality So I added a line like this after the above code !-- Javascripts -- !-- jQuery -- ?php echo $javascript-link(array('jquery-1.3.2.min')); ? I copy jquery-1.3.2.min to the default webroot/js folder (followed the cakephp convention) But I got a warning message like this: Notice (8): Undefined variable: javascript [APP\views\layouts \default.ctp, line 26] Fatal error: Call to a member function link() on a non-object in D: \xampp\htdocs\cakephp127\app\views\layouts\default.ctp on line 26 I even use $javascript-includeScript() but again I got the same warning I can't able to use the javascript functionality, I am new to cakephp, so I want to know where I am making mistake. Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en