Re: Cakephp CLI error
Solution is C:\wamp\www\myaapname\app>cake [command]
I was in a wrong folder, u dont need to call console
Sent from Samsung Mobile
Original message
From: Leandro Machado Pereira
Date:
To: cake-php@googlegroups.com
Subject: Re: Cakephp CLI error
Try
cd /path/to/cakephp/app
call console\cake bake all
2013/11/20 David Rochelet
Hi,
Seems you didn't configure your database.
Try this :
http://book.cakephp.org/2.0/fr/console-and-shells/code-generation-with-bake.html
It is mentionned that you have first to create a database.php file.
David
2013/11/20 Victor Musvibe
I am using cakephp 2.x and im trying Code Generation with Bake. When i try to
cake bake all. Below are the errors i am getting in command line.
I have posted this question on
http://stackoverflow.com/questions/20079795/cakephp-cli-error , im just hoping
to get a quicker response here.
I am using cakephp 2.x and im trying Code Generation with Bake. When i try to
cake bake all. Below are the errors i am getting in command line.
Microsoft Windows [Version 6.1.7601]
Copyright (c) 2009 Microsoft Corporation. All rights reserved.
C:\Users\victorm>cd c:\wamp\www\myappname\app\Console
c:\wamp\www\myappname\app\Console>cake bake all
Welcome to CakePHP v2.4.2 Console
---
App : Console
Path: c:\wamp\www\myappname\app\Console\
---
Bake All
---
Warning Error:
include_once(c:\wamp\www\myappname\app\Console\Config\database.php): failed to
open stream: No such file or directory in
[C:\wamp\www\myappname\lib\Cake\Model\ConnectionManager.php, line 69]
Warning Error: include_once(): Failed opening
'c:\wamp\www\myappname\app\Console\Config\database.php' for inclusion
(include_path='C:\wamp\www\myappname\lib;.;C:\php5\pear') in
[C:\wamp\www\myappname\lib\Cake\Model\ConnectionManager.php, line 69]
Error: The datasource configuration "default" was not found in
database.php
#0 C:\wamp\www\myappname\lib\Cake\Model\ConnectionManager.php(93):
Connection
Manager::_getConnectionObject('default')
#1
C:\wamp\www\myappname\lib\Cake\Console\Command\Task\ModelTask.php(929):
ConnectionManager::getDataSource('default')
#2
C:\wamp\www\myappname\lib\Cake\Console\Command\Task\ModelTask.php(866):
ModelTask->getAllTables('default')
#3
C:\wamp\www\myappname\lib\Cake\Console\Command\Task\ModelTask.php(955):
ModelTask->listAll('default')
#4 C:\wamp\www\myappname\lib\Cake\Console\Command\BakeShell.php(152):
ModelTask->getName('default')
#5 C:\wamp\www\myappname\lib\Cake\Console\Shell.php(433):
BakeShell->all()
#6 C:\wamp\www\myappname\lib\Cake\Console\ShellDispatcher.php(209):
Shell->runCommand('all', Array)
#7 C:\wamp\www\myappname\lib\Cake\Console\ShellDispatcher.php(68):
ShellDispatcher->dispatch()
#8 C:\wamp\www\myappname\app\Console\cake.php(37):
ShellDispatcher::run(Array)
#9 {main}
c:\wamp\www\myappname\app\Console>
Does anyone have an idea on how to fix this?
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Cakephp CLI error
I am using cakephp 2.x and im trying Code Generation with Bake. When i try
to cake bake all. Below are the errors i am getting in command line.
I have posted this question on
http://stackoverflow.com/questions/20079795/cakephp-cli-error , im just
hoping to get a quicker response here.
I am using cakephp 2.x and im trying Code Generation with Bake. When i try
to cake bake all. Below are the errors i am getting in command line.
*Microsoft Windows [Version 6.1.7601]*
* Copyright (c) 2009 Microsoft Corporation. All rights reserved.*
* C:\Users\victorm>cd c:\wamp\www\myappname\app\Console*
* c:\wamp\www\myappname\app\Console>cake bake all*
* Welcome to CakePHP v2.4.2 Console*
*---*
* App : Console*
* Path: c:\wamp\www\myappname\app\Console\*
*---*
* Bake All*
*---*
* Warning Error:
include_once(c:\wamp\www\myappname\app\Console\Config\database.php): failed
to open stream: No such file or directory in
[C:\wamp\www\myappname\lib\Cake\Model\ConnectionManager.php, line 69]*
* Warning Error: include_once(): Failed opening
'c:\wamp\www\myappname\app\Console\Config\database.php' for inclusion
(include_path='C:\wamp\www\myappname\lib;.;C:\php5\pear') in
[C:\wamp\www\myappname\lib\Cake\Model\ConnectionManager.php, line 69]*
* Error: The datasource configuration "default" was not found in
database.php*
* #0 C:\wamp\www\myappname\lib\Cake\Model\ConnectionManager.php(93):
Connection*
* Manager::_getConnectionObject('default')*
* #1
C:\wamp\www\myappname\lib\Cake\Console\Command\Task\ModelTask.php(929):
ConnectionManager::getDataSource('default')*
* #2
C:\wamp\www\myappname\lib\Cake\Console\Command\Task\ModelTask.php(866):
ModelTask->getAllTables('default')*
* #3
C:\wamp\www\myappname\lib\Cake\Console\Command\Task\ModelTask.php(955):
ModelTask->listAll('default')*
* #4 C:\wamp\www\myappname\lib\Cake\Console\Command\BakeShell.php(152):
ModelTask->getName('default')*
* #5 C:\wamp\www\myappname\lib\Cake\Console\Shell.php(433):
BakeShell->all()*
* #6 C:\wamp\www\myappname\lib\Cake\Console\ShellDispatcher.php(209):
Shell->runCommand('all', Array)*
* #7 C:\wamp\www\myappname\lib\Cake\Console\ShellDispatcher.php(68):
ShellDispatcher->dispatch()*
* #8 C:\wamp\www\myappname\app\Console\cake.php(37):
ShellDispatcher::run(Array)*
* #9 {main}*
* c:\wamp\www\myappname\app\Console>*
Does anyone have an idea on how to fix this?
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CakePHP bake command not working in CLI
I have got an application that i am working on built using Cakephp 1.3 problem that i am having is that i am failing to bake using CLI. I am using Windows 7 and xampp as my localserver. This is how i have added my Environment Variables. C:\xampp\php;C:\xampp\htdocs\myappname\cake\console\ When i type cake command in the CLI i get an error 'cake' is not recognized as an internal or external command, operable program or batch file. Does anyone have an idea on how to fix this. I have also asked the same question on SO and i dont seem to get answer - http://stackoverflow.com/questions/19094349/cakephp-bake-command-not-working-in-cli -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups "CakePHP" group. To unsubscribe from this group and stop receiving emails from it, send an email to cake-php+unsubscr...@googlegroups.com. To post to this group, send email to cake-php@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php. For more options, visit https://groups.google.com/groups/opt_out.
Writing data into a new worksheet using PHPExcel in Cakephp
I am using PHPExcel to generate reports for my application in cakephp. The
first worksheet is perfectly done but when I want to write on the same
workbook different new worksheet, phpexcel just creates the worksheet but
does not post data. For example record with id = 1 shows on its worksheet
and id =2 shows on its worksheet...etc
Here is my code for my addsheet that inserts a new tab
/**
* Create new worksheet
*/
public function createWorksheet() {
$this->loadEssentials();
$this->xls = new PHPExcel();
}
public function addSheet($tab) {
$newWorksheet = new PHPExcel_Worksheet($this->xls, $tab);
$this->xls->addSheet($newWorksheet);
}
//other code
and here is my view for the worksheet
PhpExcel->createWorksheet();
$this->PhpExcel->setDefaultFont('Calibri', 12);
// define table cells
$table = array(
array('label' => __('id'), 'width' => 'auto', 'filter' => true),
array('label' => __('name'), 'width' => 'auto', 'filter' => true),
array('label' => __('type'), 'width' => 'auto', 'filter' => true),
array('label' => __('comment'), 'width' => 'auto', 'filter' => true),
array('label' => __('status type'), 'width' => 'auto', 'filter' =>
true),
array('label' => __('created'), 'width' => 'auto', 'filter' => true),
);
// heading
$this->PhpExcel->addTableHeader($table, array('name' => 'Cambria',
'bold' => true));
foreach ($itQueries as $d) {
$this->PhpExcel->addSheet($d['ItQuery']['id']);
$this->PhpExcel->addTableRow(array(
$d['ItQuery']['id'],
$d['ItQuery']['hr_employee_id'],
$d['ItQuery']['it_query_type_id'],
$d['ItQuery']['comment'],
$d['ItQuery']['status_type'],
$d['ItQuery']['created'],
));
}
$this->PhpExcel->addTableFooter();
$this->PhpExcel->output();
$this->PhpExcel->exit();
?>
Its my first time using the helper
I have posted this question on OS as well, hoping to get a quick response
on this group -
http://stackoverflow.com/questions/15501509/writing-data-into-a-new-worksheet-using-phpexcel-in-cakephp
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Re: Multiple excel sheet download
Hi Cricket
Did you manage to have records opening in different tabs?
On Thursday, 25 November 2010 18:08:47 UTC+2, the plumpNation wrote:
>
> Hi guys,
>
> I have a sales report in excel which is generated using cakephp and
> PHPExcel. I am very happy with both of these frameworks/libraries. I
> am really starting to feel very comfortable using them both and am
> finally getting to the stage of being able to 'rapidly develop', the
> whole point of cake.
>
> Currently, the sales are generated from customers who share
> distributors. So the logic goes
>
> foreach(distributor){
>// create excel of sales using this distributor;
>// send email with sales to this distributor;
> }
>
> Then I added functionality to allow the sales manager to download the
> sheet just to check it, before the cron ran and sent it to the
> distributors.
>
> foreach(distributor){
>// create excel of sales using this distributor;
> if(!browserOutput){
>// send email with sales to this distributor;
> }else{
> // output the excel sheet to the browser;
> }
> }
>
> Now it all works fine except that I only receive the first sheet,
> probably because you can't do a looping download. I was just wondering
> if anyone had an elegant solution to this that didn't involve me
> writing the sheets to different tabs in the same excel sheet, but
> allows the manager to receive all the sheets from the browser one at a
> time. Maybe opening the output in different tabs or windows might
> work, but not sure how to do this. At the moment I set headers to the
> correct mime type like so
>
> if($browserOutput){
>
> $message .= 'for output to browser';
> header( 'Content-Type:
> application/vnd.ms-excel' );
> header( 'Content-Disposition:
> attachment;filename="' . $filename .
> '"');
> header( 'Cache-Control: max-age=0' );
>
> }
>
> and then use PHPExcel like so
>
> $thisSheet->save('php://output');
>
> Whatcha fink? Is this possible or should I write all the sheets into
> one file to download?
>
> Cheers for reading
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Re: How to hide id input and give it a value in cakephp
Thanks will keep that in mind next time i post a question
On Thu, Mar 7, 2013 at 2:35 PM, euromark wrote:
> If you feel the need to crosspost all over the www, it would be nice to
> link those other posts - like
>
> http://stackoverflow.com/questions/15269787/how-to-hide-id-input-and-give-it-a-value-in-cakephp
>
> this way people can take a look there if the answer might already be
> answered and avoid giving the exact same answer again
>
>
>
> Am Donnerstag, 7. März 2013 12:59:05 UTC+1 schrieb Victor Musvibe:
>
>> I have 2 models that are related and what i would like to do is in my add
>> view i would like to set the id field as a hidden field so that it doesnt
>> show on my add view, when i set it to hidden the form doesn't submit. Is
>> there a way of passing the id value as a hidden field?
>>
>> here is my add view
>>
>> Form->create('**ItQueryComment'); ?>
>>
>> > echo $this->Form->hidden('it_query_**id');
>> echo $this->Form->input('comment');
>> ?>
>>
>> Form->end(__('Submit'))**; ?>
>>
>> and here is add function for the ItQueries Controller
>>
>> public function add() {
>> if ($this->request->is('post')) {
>> $this->ItQuery->create();
>> if ($this->ItQuery->save($this->**request->data)) {
>> $this->Session->setFlash(__('**The it query has been saved'));
>> $this->redirect(array('action' => 'index'));
>> } else {
>> $this->Session->setFlash(__('**The it query could not be saved.
>> Please, try again.'));
>> }
>> }
>> $itQueryTypes = $this->ItQuery->ItQueryType->**find('list');
>> $this->set(compact('**itQueryTypes'));
>> }
>>
>> Thank you in advance
>>
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How to hide id input and give it a value in cakephp
I have 2 models that are related and what i would like to do is in my add
view i would like to set the id field as a hidden field so that it doesnt
show on my add view, when i set it to hidden the form doesn't submit. Is
there a way of passing the id value as a hidden field?
here is my add view
Form->create('ItQueryComment'); ?>
Form->hidden('it_query_id');
echo $this->Form->input('comment');
?>
Form->end(__('Submit')); ?>
and here is add function for the ItQueries Controller
public function add() {
if ($this->request->is('post')) {
$this->ItQuery->create();
if ($this->ItQuery->save($this->request->data)) {
$this->Session->setFlash(__('The it query has been saved'));
$this->redirect(array('action' => 'index'));
} else {
$this->Session->setFlash(__('The it query could not be saved. Please,
try again.'));
}
}
$itQueryTypes = $this->ItQuery->ItQueryType->find('list');
$this->set(compact('itQueryTypes'));
}
Thank you in advance
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Re: Redirecting to a different controller view in Cakephp
Hi
I solved it by doing this
$this->request->data['ItQueryComment']['it_query_id']
On Thu, Mar 7, 2013 at 1:42 PM, Jerome Walitzek wrote:
> Hi,
>
> i solve the problem with following
>
> $this->redirect(array('controller' =>
> 'posts', 'action'=>'view',$this->Post->id));
>
>
>
> Am Donnerstag, 7. März 2013 11:32:47 UTC+1 schrieb Victor Musvibe:
>
>> I have to 2 models that are related ItQuery and ItQueryComment. When a
>> user adds a ItQuery other users should be able to comment on it. What i am
>> trying to achieve is when other users add comments on a query they should
>> be redirect to the view of the query not the index page for the
>> it_query_comments
>>
>> here is my code for my comments add view
>>
>> Form->create('**ItQueryComment'); ?>
>>
>>
>> > echo $this->Form->input('it_query_**id');
>> echo $this->Form->input('comment');
>> ?>
>>
>> Form->end(__('Submit'))**; ?>
>>
>> and here is my add function in the controller
>>
>> public function add() {
>> if ($this->request->is('post')) {
>> $this->ItQueryComment->create(**);
>> if ($this->ItQueryComment->save($**this->request->data)) {
>> $this->Session->setFlash(__('**The it query comment has been
>> saved'));
>> $this->redirect(array('**controller' => 'it_queries','action' =>
>> 'view', $itQuery['ItQuery']['id']));
>> } else {
>> $this->Session->setFlash(__('**The it query comment could not be
>> saved. Please, try again.'));
>> }
>> }
>> $itQueries = $this->ItQueryComment->**ItQuery->find('list');
>> $this->set(compact('itQueries'**));
>> }
>>
>> If anyone could show me how to do this, that would be awesome. Thanks in
>> advance
>>
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Redirecting to a different controller view in Cakephp
I have to 2 models that are related ItQuery and ItQueryComment. When a user
adds a ItQuery other users should be able to comment on it. What i am
trying to achieve is when other users add comments on a query they should
be redirect to the view of the query not the index page for the
it_query_comments
here is my code for my comments add view
Form->create('ItQueryComment'); ?>
Form->input('it_query_id');
echo $this->Form->input('comment');
?>
Form->end(__('Submit')); ?>
and here is my add function in the controller
public function add() {
if ($this->request->is('post')) {
$this->ItQueryComment->create();
if ($this->ItQueryComment->save($this->request->data)) {
$this->Session->setFlash(__('The it query comment has been saved'));
$this->redirect(array('controller' => 'it_queries','action' => 'view',
$itQuery['ItQuery']['id']));
} else {
$this->Session->setFlash(__('The it query comment could not be saved.
Please, try again.'));
}
}
$itQueries = $this->ItQueryComment->ItQuery->find('list');
$this->set(compact('itQueries'));
}
If anyone could show me how to do this, that would be awesome. Thanks in
advance
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Re: How to define a checkbox variable in Cakephp
Thanks euromark. I am on it
On Wed, Mar 6, 2013 at 10:34 AM, euromark wrote:
> You already got your answer at SO.
>
> Am Mittwoch, 6. März 2013 08:50:35 UTC+1 schrieb Victor Musvibe:
>
>> I have a form in my Plugin elements and what i would like to insert the
>> checkbox value into a table named it_queries and field status_type and its
>> giving me an error Undefined variable: variableValue
>> [APP\Plugin\Feedback\View\**Elements\comment_add.ctp, line 37] .I have
>> declared the variable in my controller like this
>>
>> $this->set('**variableValueStatus', 'Pending');
>>
>> and this is line 37 thats giving me the error
>>
>> Below is the Controller code
>>
>> class CommentsController extends FeedbackAppController
>> {
>> public $components = array('Feedback.Comments');
>>
>> public function add($foreign_model = null, $foreign_id = null)
>> {
>> if (empty($foreign_model) ||
>> empty($foreign_id) ||
>> !$this->request->is('post')
>> )
>> {
>> $this->set('**variableValueStatus', 'Pending');
>> return $this->redirect('/');
>> }
>> //Other code
>>
>> }
>>
>> and in the add view in my element here is how i am trying to accessing
>> the variable value
>>
>> echo $this->Form->checkbox('**ItQuery.status_type', array('type' =>
>> 'hidden', 'value'=>$variableValueStatus)**);
>>
>> If someone can show me how to fix this, that would be awesome
>>
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How to define a checkbox variable in Cakephp
I have a form in my Plugin elements and what i would like to insert the
checkbox value into a table named it_queries and field status_type and its
giving me an error Undefined variable: variableValue
[APP\Plugin\Feedback\View\Elements\comment_add.ctp, line 37] .I have
declared the variable in my controller like this
$this->set('variableValueStatus', 'Pending');
and this is line 37 thats giving me the error
Below is the Controller code
class CommentsController extends FeedbackAppController
{
public $components = array('Feedback.Comments');
public function add($foreign_model = null, $foreign_id = null)
{
if (empty($foreign_model) ||
empty($foreign_id) ||
!$this->request->is('post')
)
{
$this->set('variableValueStatus', 'Pending');
return $this->redirect('/');
}
//Other code
}
and in the add view in my element here is how i am trying to accessing the
variable value
echo $this->Form->checkbox('ItQuery.status_type', array('type' =>
'hidden', 'value'=>$variableValueStatus));
If someone can show me how to fix this, that would be awesome
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How to insert a checkbox value into a table from plugin in Cakephp
I am using a feedback plugin for my app and on the add view i am putting a
checkbox with value Pending. I was wondering if they is a away that when
the checkbox is ticket it will insert the checkbox value into a table named
it_queries and field name status_type.
Here is how i am declaring my variable name in the plugin controller
$this->set('variableValueStatus', 'Pending');
and here is the Plugin controller code
set('variableValueStatus', 'Pending');
if (empty($foreign_model) ||
empty($foreign_id) ||
!$this->request->is('post')
)
{
return $this->redirect('/');
}
App::uses($foreign_model, 'Model');
$Model = ClassRegistry::init($foreign_model);
if (!($Model instanceof Model))
{
return $this->redirect('/');
}
if ($Model->hasAny(array($Model->primaryKey => $foreign_id)) == false)
{
return $this->redirect('/');
}
if (!isset($this->request->data['Comment']['foreign_model']) ||
!isset($this->request->data['Comment']['foreign_id']) ||
$this->request->data['Comment']['foreign_model'] != $foreign_model ||
$this->request->data['Comment']['foreign_id'] != $foreign_id)
{
return $this->redirect('/');
}
$user_id = null;
if (isset($this->Auth))
{
$user_id = $this->Auth->user('id');
}
$this->request->data['Comment']['foreign_model'] = $Model->name;
$this->request->data['Comment']['foreign_id'] = $foreign_id;
$this->request->data['Comment']['user_id'] = $user_id;
$this->request->data['Comment']['author_ip'] =
$this->request->clientIp();
$this->Comment->create();
if (!$this->Comment->save($this->request->data))
{
$this->set('validation_errors', $this->Comment->validationErrors);
return;
}
$this->redirect($this->request->referer().'#comment-'.$this->Comment->id);
}
}
and here is my code for the checkbox in the plugin add view
Form->checkbox('ItQuery.status_type', array('type' =>
'hidden', 'value'=>$variableValueStatus)); ?>
Can some please show me how to fix this
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Re: How to define a variable in Cakephp
Yes you right. I have removed public $variableValue = 'Open'; and did
exactly what you did
On Tue, Mar 5, 2013 at 2:12 PM, Jeremy Burns | Class Outfit <
jeremybu...@classoutfit.com> wrote:
> I'm pleased it works, but I'm confused why you need this line:
>
> public $variableValue = 'Open';
>
> Why not just do this:
>
> $this->set('variableValue', 'Open');
>
>
> Jeremy Burns
> Class Outfit
>
> http://www.classoutfit.com
>
> On 5 Mar 2013, at 12:08:43, Victor Musvibe wrote:
>
> Thank you, now it works. What i did was in my controller i put this line
>
> public $variableValue = 'Open';
>
> Then in my add function
>
> $this->set('variableValue', $this->variableValue);
>
> And lastly in my add view
>
> echo $this->Form->input('status_type', array('type' => 'hidden',
> 'value'=>$variableValue));
>
> Hope this will help out someone with the same challenge
>
> On Tue, Mar 5, 2013 at 1:08 PM, Jeremy Burns | Class Outfit <
> jeremybu...@classoutfit.com> wrote:
>
>> Correction (sorry):
>>
>> Then in your view you can refer to *$myVariableName*.
>>
>> Jeremy Burns
>> Class Outfit
>>
>> http://www.classoutfit.com
>>
>> On 5 Mar 2013, at 11:03:15, Jeremy Burns | Class Outfit <
>> jeremybu...@classoutfit.com> wrote:
>>
>> To pass a variable through to a view, simply do this in your controller
>> function:
>>
>> $this->set('myVariableName', $variableValue);
>>
>> Then in your view you can refer to $variableValue.
>>
>> Jeremy Burns
>> Class Outfit
>>
>> http://www.classoutfit.com
>>
>> On 5 Mar 2013, at 10:59:50, Victor Musvibe wrote:
>>
>> Hi Euromark
>>
>> I am the one who posted that. Was hoping to get a quicker response on the
>> cakephp group
>>
>> On Tue, Mar 5, 2013 at 12:57 PM, euromark wrote:
>>
>>>
>>> http://stackoverflow.com/questions/15221467/how-to-define-a-variable-in-cakephp
>>>
>>>
>>> Am Dienstag, 5. März 2013 11:55:37 UTC+1 schrieb Victor Musvibe:
>>>
>>>> I trying to pass a variable in cakephp to a view and getting error
>>>> Undefined variable: view [APP\View\ItQueries\add.ctp, line 9] and line 9 is
>>>> this
>>>>
>>>> Form->hidden('status_**type',
>>>> array('value'=>$view)); ?>
>>>>
>>>> Here is how im defining my variable in the controller
>>>>
>>>> class ItQueriesController extends AppController {
>>>>
>>>> var $view = 'Open';
>>>>
>>>> public function index() {
>>>> $this->ItQuery->recursive = 0;
>>>> $this->set('view', $this->view);
>>>>
>>>> }
>>>>
>>>> //Other Code
>>>>
>>>> }
>>>>
>>>> and here is where im trying to pass the variable as a hidden field
>>>>
>>>> Form->create('ItQuery')**; ?>
>>>>
>>>> >>> echo $this->Form->input('status_**type', array('type' => 'hidden',
>>>> 'value'=>$view));
>>>> ?>
>>>> Form->end(__('Submit'))**; ?>
>>>>
>>>> Can some please show me how to fix this
>>>>
>>>>
>>> --
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>>
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Re: How to define a variable in Cakephp
Thank you, now it works. What i did was in my controller i put this line
public $variableValue = 'Open';
Then in my add function
$this->set('variableValue', $this->variableValue);
And lastly in my add view
echo $this->Form->input('status_type', array('type' => 'hidden',
'value'=>$variableValue));
Hope this will help out someone with the same challenge
On Tue, Mar 5, 2013 at 1:08 PM, Jeremy Burns | Class Outfit <
jeremybu...@classoutfit.com> wrote:
> Correction (sorry):
>
> Then in your view you can refer to *$myVariableName*.
>
> Jeremy Burns
> Class Outfit
>
> http://www.classoutfit.com
>
> On 5 Mar 2013, at 11:03:15, Jeremy Burns | Class Outfit <
> jeremybu...@classoutfit.com> wrote:
>
> To pass a variable through to a view, simply do this in your controller
> function:
>
> $this->set('myVariableName', $variableValue);
>
> Then in your view you can refer to $variableValue.
>
> Jeremy Burns
> Class Outfit
>
> http://www.classoutfit.com
>
> On 5 Mar 2013, at 10:59:50, Victor Musvibe wrote:
>
> Hi Euromark
>
> I am the one who posted that. Was hoping to get a quicker response on the
> cakephp group
>
> On Tue, Mar 5, 2013 at 12:57 PM, euromark wrote:
>
>>
>> http://stackoverflow.com/questions/15221467/how-to-define-a-variable-in-cakephp
>>
>>
>> Am Dienstag, 5. März 2013 11:55:37 UTC+1 schrieb Victor Musvibe:
>>
>>> I trying to pass a variable in cakephp to a view and getting error
>>> Undefined variable: view [APP\View\ItQueries\add.ctp, line 9] and line 9 is
>>> this
>>>
>>> Form->hidden('status_**type',
>>> array('value'=>$view)); ?>
>>>
>>> Here is how im defining my variable in the controller
>>>
>>> class ItQueriesController extends AppController {
>>>
>>> var $view = 'Open';
>>>
>>> public function index() {
>>> $this->ItQuery->recursive = 0;
>>> $this->set('view', $this->view);
>>>
>>> }
>>>
>>> //Other Code
>>>
>>> }
>>>
>>> and here is where im trying to pass the variable as a hidden field
>>>
>>> Form->create('ItQuery')**; ?>
>>>
>>> >> echo $this->Form->input('status_**type', array('type' => 'hidden',
>>> 'value'=>$view));
>>> ?>
>>> Form->end(__('Submit'))**; ?>
>>>
>>> Can some please show me how to fix this
>>>
>>>
>> --
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>>
>>
>
>
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Re: How to define a variable in Cakephp
Hi Euromark
I am the one who posted that. Was hoping to get a quicker response on the
cakephp group
On Tue, Mar 5, 2013 at 12:57 PM, euromark wrote:
>
> http://stackoverflow.com/questions/15221467/how-to-define-a-variable-in-cakephp
>
>
> Am Dienstag, 5. März 2013 11:55:37 UTC+1 schrieb Victor Musvibe:
>
>> I trying to pass a variable in cakephp to a view and getting error
>> Undefined variable: view [APP\View\ItQueries\add.ctp, line 9] and line 9 is
>> this
>>
>> Form->hidden('status_**type',
>> array('value'=>$view)); ?>
>>
>> Here is how im defining my variable in the controller
>>
>> class ItQueriesController extends AppController {
>>
>> var $view = 'Open';
>>
>> public function index() {
>> $this->ItQuery->recursive = 0;
>> $this->set('view', $this->view);
>>
>> }
>>
>> //Other Code
>>
>> }
>>
>> and here is where im trying to pass the variable as a hidden field
>>
>> Form->create('ItQuery')**; ?>
>>
>> > echo $this->Form->input('status_**type', array('type' => 'hidden',
>> 'value'=>$view));
>> ?>
>> Form->end(__('Submit'))**; ?>
>>
>> Can some please show me how to fix this
>>
>> --
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How to define a variable in Cakephp
I trying to pass a variable in cakephp to a view and getting error
Undefined variable: view [APP\View\ItQueries\add.ctp, line 9] and line 9 is
this
Form->hidden('status_type', array('value'=>$view)); ?>
Here is how im defining my variable in the controller
class ItQueriesController extends AppController {
var $view = 'Open';
public function index() {
$this->ItQuery->recursive = 0;
$this->set('view', $this->view);
}
//Other Code
}
and here is where im trying to pass the variable as a hidden field
Form->create('ItQuery'); ?>
Form->input('status_type', array('type' => 'hidden',
'value'=>$view));
?>
Form->end(__('Submit')); ?>
Can some please show me how to fix this
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Changing table field using 2 different models
I have an IT query system were by users can add their queries, when they
add their query the IT department then replies/comments on the query.
How is should work is when the user adds a query it must change the
query_type field in the it_queries table to OPEN and when the IT department
views the query they reply/comment on it and must change query_type field
from OPEN to PENDING then finally when the user has been helped/assisted
they should be able to mark the query as closed using a checkbox, that will
then change the status from PENDING TO CLOSE.
Not sure if they is a way of setting the constants in the add views and
insert in the table.
Obviously i am learning and can someone please guide me on the steps i must
take.
Here is my code for the add it_query for the users
Form->create('ItQuery'); ?>
Form->hidden('hr_employee_id',array('value'=>$loggedInId));
echo $this->Form->input('it_query_type_id');
echo $this->Form->input('comment');
echo $this->Form->input('it_status_query_id');
?>
Form->end(__('Submit')); ?>
Here is the code for my comments for IT Department
Form->create
(
'Feedback.Comment',
array
(
'url' => array
(
'plugin' => 'feedback',
'controller' => 'comments',
'action' => 'add',
$foreign_model,
$foreign_id
)
)
);
?>
Form->input('Comment.author_name', array('label' =>
__('Name'))); ?>
Form->input('Comment.hairy_pot', array('type' =>
'hidden')); ?>
Form->input('Comment.content', array('label' =>
__('Comments'))); ?>
Form->input('Comment.foreign_model', array('type' =>
'hidden', 'value' => $foreign_model)); ?>
Form->input('Comment.foreign_id', array('type' =>
'hidden', 'value' => $foreign_id)); ?>
Form->end(__('Save comment')); ?>
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Send email when you edit a field in Cakephp
I have employee application where users standing can be resigned, active,
new and transferred. What i would like to achieve is that when the standing
of an employee is changed/edited from active (standing_id = 1) it should be
able to send through an email but its not. I have put a email function in
the EmployeeController. Below is my code.
function _sendNewEmployeeEditMail($id) {
$Employee = $this->Employee->read(null,$id);
$email = new CakeEmail();
$email->from(array('no-re...@test.com' => 'Testing App'));
$email->to(array('xxx...@gmail.com' => 'Name Surname'));
$email->subject('New Employee');
$email->template('employee_email');
$email->viewVars(compact('Employee'));
$email->emailFormat('html');
$_sendNewEmployeeEditMail = true;
$current_status = $this->Employee->field('standing_id');
if($current_status==1) {
$_sendNewEmployeeEditMail = false;
}
}
and in my edit save function here is how i am trying to send the email
public function edit($id = null) {
$this->Employee->id = $id;
if (!$this->Employee->exists()) {
throw new NotFoundException(__('Invalid employee'));
}
if ($this->request->is('post') || $this->request->is('put')) {
if ($this->Employee->save($this->request->data)) {
$this->Session->setFlash(__('The employee has been
saved'),'default',array('class' => 'notification'));
$this->_sendNewEmployeeEditMail($this->Employee->getLastInsertID() );
$this->redirect(array('action' => 'index'));
} else {
$this->Session->setFlash(__('The employee could not be saved. Please,
try again.'),'default',array('class' => 'error'));
}
} else {
$this->request->data = $this->Employee->read(null, $id);
}
$standings = $this->Employee->Standing->find('list');
$this->set(compact('standings'));
If anyone could help me out on this, that would be awesome
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Utils Plugin for CakePHP not inserting records into table
I am using the Utils Plugin for CakePHP on this link - https://github.com/CakeDC/utils. However the problem that i am having right now is that when i upload the csv its counting the correct number of records from my csv using setFlash e.g (Successfully imported 3 records from test.csv), but doesnt insert any records into the database. Does anyone have any idea on what might be causing this. I didnt change anything from the link provided. Thanks in advance -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups "CakePHP" group. To unsubscribe from this group and stop receiving emails from it, send an email to cake-php+unsubscr...@googlegroups.com. To post to this group, send email to cake-php@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php?hl=en. For more options, visit https://groups.google.com/groups/opt_out.
How to echo and play videos in Cakephp
I have an application were by users can upload images and should be able to
echo and play videos. My upload function works fine but challenge that i am
having now is to echo and play the video. Here is how i am uploading the
file
function uploadFile() {
$file = $this->data['CpdVideo']['file'];
if ($file['error'] === UPLOAD_ERR_OK) {
$id = String::uuid();
if (move_uploaded_file($file['tmp_name'], WWW_ROOT . 'files/videos/' .
$file['name'])) {
$this->request->data['CpdVideo']['filename'] = $file['name'];
$this->request->data['CpdVideo']['filesize'] = $file['size'];
$this->request->data['CpdVideo']['filemime'] = $file['type'];
return true;
}
}
return false;
}
Here is how i am saving the video
if ($this->uploadFile() && $this->CpdVideo->save($this->data))
This how i am trying to echo and play the video in my view.ctp
Html->media('files/videos'.
$cpdVideo['CpdVideo']['filename'], array('fullBase' => true));
If any one could help me out that would be awesome
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Viewing 2 or more elements in the same view in Cakephp
I am using Google API for displaying charts on my app. I am trying to view
more than two elements on the same view page (index.ctp). Meaning i am
trying to have more than 2 Charts on the same view page. The index page is
only showing the policies_accessible2012.ctp element.
Here is how i am calling the elements in my index.ctp
element('SurveyResults/2011/policies_accessible2011'); ?>
element('SurveyResults/2012/policies_accessible2012'); ?>
I do understand that if i have the following code, this will result in
SurveyResults/2012/policies_accessible2012 rendered as the parent view to
the current view
element('SurveyResults/2011/policies_accessible2011'); ?>
element('SurveyResults/2012/policies_accessible2012'); ?>
I am just wondering if they is a way to show the 2 or more elements on the
same view. Thank you in advance
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Passing record from element to a view using different models
Hi Bakers
I have an app were users can add their queries(ItQueries/add). When the IT
department views the query (ItQueries/view/1) they should be able to
comment/respond to it. What i have done so far is.
In the view of the IT query i have called an element for the IT department
to add a response. below is how im calling the element
Element('/ItQueryResponses/add'); ?>
On submit of the ItQueryResponses i would like the action to redirect to
the view page of the ItQueris with its comment underneath it.
Here is my code for my element
Form->create('ItQueryResponse', array('action' =>
'add')); ?>
Form->input('it_query_id');
echo $this->Form->input('response');
?>
Form->end(__('Submit')); ?>
Here is my add function for the ItQueryResponseController
public function add() {
if ($this->request->is('post')) {
$this->ItQueryResponse->create();
if ($this->ItQueryResponse->save($this->request->data)) {
$this->Session->setFlash(__('The it query response has been saved'));
$this->redirect(array('Controller' => 'ItQueryResponses', 'action' =>
'view'));
} else {
$this->Session->setFlash(__('The it query response could not be saved.
Please, try again.'));
}
}
}
Here is my code for the ItQueryResponses view
If anyone can show me how i redirect to the ItQueryResponses view and have
the ItQueryResponse underneath the view that would be awesome.
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Re: Inserting records into a table from an element
Its now working create() method should be like this:
$this->Form->create('ItQueryResponse', array('action' => 'add'));,
otherwise the form submits to the view() method of your controller.
On Thursday, 21 February 2013 09:07:51 UTC+2, Victor Musvibe wrote:
>
> Hi there
>
> I have an element that i am calling with a view file. The element is a add
> view that is add.ctp, challenge that im having now is that the element is
> not inserting form input into the table (it_query_responses).
>
> here is how i am calling my element within the view -
>
> Element('ItQueryResponses/add'); ?>
>
> and here is the code for the element
>
> Form->create('ItQueryResponse'); ?>
>
> echo $this->Form->input('it_query_id');
> echo $this->Form->input('hr_employee_id');
> echo $this->Form->input('response');
> echo $this->Form->input('it_query_status_id');
> ?>
> Form->end(__('Submit')); ?>
>
> and here is add function in ItQueryResponsesController
>
> public function add() {
> if ($this->request->is('post')) {
> $this->ItQueryResponse->create();
> if ($this->ItQueryResponse->save($this->request->data)) {
> $this->Session->setFlash(__('The it query response has been saved'));
> $this->redirect(array('action' => 'index'));
> } else {
> $this->Session->setFlash(__('The it query response could not be saved.
> Please, try again.'));
> }
> }
> $itQueries = $this->ItQueryResponse->ItQuery->find('list');
> $hrEmployees = $this->ItQueryResponse->HrEmployee->find('list');
> $itQueryStatuses = $this->ItQueryResponse->ItQueryStatus->find('list');
> $this->set(compact('itQueries', 'hrEmployees', 'itQueryStatuses'));
> }
>
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Inserting records into a table from an element
Hi there
I have an element that i am calling with a view file. The element is a add
view that is add.ctp, challenge that im having now is that the element is
not inserting form input into the table (it_query_responses).
here is how i am calling my element within the view -
Element('ItQueryResponses/add'); ?>
and here is the code for the element
Form->create('ItQueryResponse'); ?>
Form->input('it_query_id');
echo $this->Form->input('hr_employee_id');
echo $this->Form->input('response');
echo $this->Form->input('it_query_status_id');
?>
Form->end(__('Submit')); ?>
and here is add function in ItQueryResponsesController
public function add() {
if ($this->request->is('post')) {
$this->ItQueryResponse->create();
if ($this->ItQueryResponse->save($this->request->data)) {
$this->Session->setFlash(__('The it query response has been saved'));
$this->redirect(array('action' => 'index'));
} else {
$this->Session->setFlash(__('The it query response could not be saved.
Please, try again.'));
}
}
$itQueries = $this->ItQueryResponse->ItQuery->find('list');
$hrEmployees = $this->ItQueryResponse->HrEmployee->find('list');
$itQueryStatuses = $this->ItQueryResponse->ItQueryStatus->find('list');
$this->set(compact('itQueries', 'hrEmployees', 'itQueryStatuses'));
}
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Passing form values from an element to a table in cakephp
I have a IT query system where users add their queries. When i view the
query i should be able to add a response to the query. The response should
be added to table named it_query_responses and Model name is
ItQueryResponse.
Through an element i am including the add response in the view.ctp for the
IT queries. Challenge that i am having now is that the element is not
saving the response into the it_query_responses table.
Here is my add function for response controller
public function add() {
if ($this->request->is('post')) {
$this->ItQueryResponse->create();
if ($this->ItQueryResponse->save($this->request->data)) {
$this->Session->setFlash(__('The it query response has been saved'));
$this->redirect(array('action' => 'index'));
} else {
$this->Session->setFlash(__('The it query response could not be saved.
Please, try again.'));
}
}
$itQueries = $this->ItQueryResponse->ItQuery->find('list');
$hrEmployees = $this->ItQueryResponse->HrEmployee->find('list');
$itQueryStatuses = $this->ItQueryResponse->ItQueryStatus->find('list');
$this->set(compact('itQueries', 'hrEmployees', 'itQueryStatuses'));
}
and here is how i am calling my element after the closing div in view.ctp
element('ItQueryResponses/add'); ?>
here is the code for my element
Form->create('ItQueryResponse'); ?>
Form->input('it_query_id');
echo $this->Form->input('hr_employee_id');
echo $this->Form->input('response');
echo $this->Form->input('it_query_status_id');
?>
Form->end(__('Submit')); ?>
Thank you in advance.
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Viewing a PDF file in Cakephp
Hi Bakers
I am trying to view a PDF file within the body of my cakephp application
after uploading it, more like an iframe. The upload works fine but the
challenge that i have now is opening the pdf file.
Here is my upload function in my controller which is working fine
function uploadFile() {
$file = $this->data['QmsProcedureKnowledgeManagement']['file'];
if ($file['error'] === UPLOAD_ERR_OK) {
$id = String::uuid();
if (move_uploaded_file($file['tmp_name'], APP . 'qms_procedure_km/' .
$file['name'])) {
$this->request->data['QmsProcedureKnowledgeManagement']['filename'] =
$file['name'];
$this->request->data['QmsProcedureKnowledgeManagement']['filesize'] =
$file['size'];
$this->request->data['QmsProcedureKnowledgeManagement']['filemime'] =
$file['type'];
return true;
}
}
return false;
}
and here is how i am trying to view the pdfin view.ctp
Html->link(APP.'qms_procedure_km/'.
$qmsProcedureKnowledgeManagement['QmsProcedureKnowledgeManagement']['filename']);
?>
Thank you in advance.
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Re: Cake PHP Search Component not working and giving an error
Hi Euromark
I am using the search plugin on https://github.com/cakedc/search. I am
trying to search for records using the ID field only, that is if i type in
1 on my form input it must show a record with user ID 1. The challenge that
i am having now is when i specify that the input should be the id field,
the input field for the search functionality disappears on my index view,
strange thing is when i specify a different field name the input field
shows.
Below is my code for my Model
public $actsAs = array('Search.Searchable');
public $filterArgs = array(
'id' => array('type' => 'like', 'field' => 'ItSupportRequest.id'),
);
public function findByTags($data = array()) {
$this->Tagged->Behaviors->attach('Containable', array('autoFields'
=> false));
$this->Tagged->Behaviors->attach('Search.Searchable');
$query = $this->Tagged->getQuery('all', array(
'conditions' => array('Tag.name' => $data['tags']),
'fields' => array('foreign_key'),
'contain' => array('Tag')
));
return $query;
}
public function orConditions($data = array()) {
$filter = $data['filter'];
$cond = array(
'OR' => array(
$this->alias . '.id LIKE' => '%' . $filter . '%',
));
return $cond;
}
and here is my controller code.
public $components = array('Search.Prg');
public $presetVars = true; // using the model configuration
public function find() {
$this->Prg->commonProcess();
$this->paginate['conditions'] =
$this->ItSupportRequest->parseCriteria($this->passedArgs);
$this->set('articles', $this->paginate());
}
and in my index.ctp file i have this code.
Form->create('ItSupportRequest', array(
'url' => array_merge(array('action' => 'find'), $this->params['pass'])
));
echo $this->Form->label('Query ID:') . "";
echo $this->Form->input('name', array('div' => false, 'label' =>
false));
echo $this->Form->submit(__('Search'), array('div' => false));
echo $this->Form->end();
?>
Thanks
Victor
On Mon, Feb 18, 2013 at 1:10 PM, euromark wrote:
> You would need to properly upgrade the component and make it work with
> your version of cake.
>
> I propose you try https://github.com/cakedc/search
> It is up to date, more sophisticated and does the job with less
> configuration
>
>
>
> Am Montag, 18. Februar 2013 09:43:46 UTC+1 schrieb Victor Musvibe:
>
>> Hi Bakers
>>
>> I implemented a search component from this url http://www.designaeon.com/
>> **cake-php-search-component/<http://www.designaeon.com/cake-php-search-component/>but
>> I have a few problems. At first Cake didn’t recognize the component.
>> After I renamed search.php in SearchComponent.php
>>
>> I got another Error: Declaration of SearchComponent::initialize() should
>> be compatible with Component::initialize(**Controller $controller)
>> [APP/Controller/Component/**SearchComponent.php, line 40]
>>
>> Below is my code for SearchComponent
>>
>> > class SearchComponent extends Component {
>>
>> var $controller = null;
>>
>> function initialize(&$controller)
>> {
>> $this->controller = $controller;
>> }
>>
>> function getConditions(){
>> $conditions = array();
>> $data= empty($this->controller->**params['named']) ?
>> $this->controller->params['**url'] : $this->controller->params['**named']
>> ;
>> $this->controller->{$this->**controller->modelClass}->**schema();
>>
>> foreach($data as $key=>$value){
>>
>> if(isset($this->controller->{$**this->controller->modelClass}-**>_schema[$key])
>> && !empty($value)){
>> switch($this->controller->{$**this->controller->modelClass}-**
>> >_schema[$key]['type']){
>> case "string":
>> $conditions[$this->controller-**>modelClass . "." .$key . " LIKE"]
>> = "%".trim($value)."%";
>> break;
>> case "integer":
>> $conditions[$this->controller-**>modelClass . ".&
Cake PHP Search Component not working and giving an error
Hi Bakers
I implemented a search component from this url
http://www.designaeon.com/cake-php-search-component/ but I have a few
problems. At first Cake didn’t recognize the component. After I renamed
search.php in SearchComponent.php
I got another Error: Declaration of SearchComponent::initialize() should be
compatible with Component::initialize(Controller $controller)
[APP/Controller/Component/SearchComponent.php, line 40]
Below is my code for SearchComponent
controller = $controller;
}
function getConditions(){
$conditions = array();
$data= empty($this->controller->params['named']) ?
$this->controller->params['url'] : $this->controller->params['named'] ;
$this->controller->{$this->controller->modelClass}->schema();
foreach($data as $key=>$value){
if(isset($this->controller->{$this->controller->modelClass}->_schema[$key])
&& !empty($value)){
switch($this->controller->{$this->controller->modelClass}->_schema[$key]['type']){
case "string":
$conditions[$this->controller->modelClass . "." .$key . " LIKE"] =
"%".trim($value)."%";
break;
case "integer":
$conditions[$this->controller->modelClass . "." .$key] = $value;
break;
case "date":
if(isset($this->controller->params['named'][$key."_fromdate"])){
$from = date("Y-m-d", strtotime(
$this->controller->params['named'][$key."_fromdate"] ));
$conditions[$this->controller->modelClass.".".$key." >="] = trim($from);
}
if(isset($this->controller->params['named'][$key."_todate"])){
$to = date("Y-m-d", strtotime($this->params['named'][$key."_todate"]));
$conditions[$this->controller->modelClass.".".$key." <="] = $to;
}
}
}
}
return $conditions;
}
}
?>
and in my index view i am using this code
element('SearchForm/set_pagination_named');?>//set
pagination named element
element('SearchForm/form') ?>//search form element
Paginator->sort('id');?>
Html->link(__('Edit', true), array('action' =>
'edit', $itSupportRequest['ItSupportRequest']['id'])); ?>
Html->link(__('Delete', true), array('action' =>
'delete', $itSupportRequest['ItSupportRequest']['id']), null,
sprintf(__('Are you sure you want to delete # %s?', true),
$itSupportRequest['ItSupportRequest']['id'])); ?>
I have created 2 Elements SearchForm/form.ctp and
SearchForm/set_pagination_named.ctp
/*form.ctp*/
Search params['controller'] ?>
Form->create(array('action' => 'index', 'type' =>
'GET')); ?>
Form->input('id', array(
'label'=>'ID','type'=>'text'));
echo $this->Form->submit('Search',array('class'=>'button'));
?>
Form->end(); ?>
and here is my set_pagination_named.ctp
params['url']) || isset($this->params['named'])){
$data=isset($this->params['named'] ) && !empty($this->params['named'])
? $this->params['named']:$this->params['url'];
$possibledata=array('id');//possible fields
foreach($data as $key=>$value){
if(in_array($key,$possibledata) && !empty($value)){
$data_arr[$key]=$data[$key];
}
}
}
?>
Paginator->options(array(
'evalScripts' => true,
'url'=>$data_arr
));
?>
Thank you in advance.
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Retrieving Records Based On Field In Related Model?
I have an employees table with status that is active, new and resigned. In my drop down menu for the application i have all 3 different statuses that is active, new and resigned,now i wanna link to each different status, that is when i click on active it only shows me the active users in the employee table. Please not status table is linked to the employees table. Thank you in advance. -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups "CakePHP" group. To unsubscribe from this group and stop receiving emails from it, send an email to cake-php+unsubscr...@googlegroups.com. To post to this group, send email to cake-php@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php?hl=en. For more options, visit https://groups.google.com/groups/opt_out.
Re: Echo a image in cakephp after uploading it
You simply the best..Yes it works.
On Thu, Feb 14, 2013 at 11:46 AM, Marcus James wrote:
> Html->image('logos/'. $logo['Logo']['filename']); ?>
>
>
>
>
>
>
> --
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>
>
>
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Re: Echo a image in cakephp after uploading it
Hi Marcus
I have changed my uploadFile function to
function uploadFile() {
$file = $this->data['Logo']['file'];
if ($file['error'] === UPLOAD_ERR_OK) {
$id = String::uuid();
if (move_uploaded_file($file['tmp_name'], WWW_ROOT .
'img/logos/' . $file['name'])) {
$this->request->data['Logo']['filename'] = $file['name'];
$this->request->data['Logo']['filesize'] = $file['size'];
$this->request->data['Logo']['filemime'] = $file['type'];
return true;
}
}
return false;
}
and its uploading correctly to the webroot img folder using the filename.
Now im trying to echo the image in my view using
Html->image('logos'. $logo['Logo']['filename']); ?>
Still does not echo.
Any idea why it doesnt wanna work?
On Thu, Feb 14, 2013 at 11:32 AM, Marcus James wrote:
> what you wrote above, are you saving 511ca905-f170-49d5-90a0-055083176c8c
> value?
>
>
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Re: Echo a image in cakephp after uploading it
Hi Marcus
Please note that when saving the image in the logos folder its manually
generating an ID which i use as a safe filesystem name for storage.
This eliminates any issues that users may attempt to introduce with weird
and potentially system-damaging filenames that would otherwise be directly
stored on your filesystem.
So in my logos folder it saves an image as
511ca905-f170-49d5-90a0-055083176c8c which is also the ID value in the
database and the filename saves it as Jellyfish.jpg.
Hope this makes sense.
Any idea on how i can fix this?
Thanks
On Thursday, 14 February 2013 11:01:35 UTC+2, marco metal wrote:
>
> you should write :-
>
> Html->image('/logos/'. $logo['Logo']['filename']); ?>
>
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Re: Echo a image in cakephp after uploading it
Hi Marcus
Please note that when saving the image in the logos folder its manually
generating an ID which i use as a safe filesystem name for storage.
This eliminates any issues that users may attempt to introduce with weird
and potentially system-damaging filenames that would otherwise be directly
stored on your filesystem.
So in my logos folder it saves an image as
511ca905-f170-49d5-90a0-055083176c8c which is also the ID value in the
database and the filename saves it as Jellyfish.jpg.
Hope this makes sense.
Any idea on how i can fix this?
Thanks
On Thu, Feb 14, 2013 at 11:01 AM, Marcus James wrote:
> you should write :-
>
> Html->image('/logos/'. $logo['Logo']['filename']); ?>
>
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>
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Echo a image in cakephp after uploading it
I am trying to echo an image after i upload to logos folder which is under
the app folder. The uploading is working but the challenge that i have
right now is to echo the image in the view. Below is my upload function and
the view code
function uploadFile() {
$file = $this->data['Logo']['file'];
if ($file['error'] === UPLOAD_ERR_OK) {
$id = String::uuid();
if (move_uploaded_file($file['tmp_name'], APP.'logos'.DS.$id)) {
$this->request->data['Logo']['filename'] = $file['name'];
$this->request->data['Logo']['filesize'] = $file['size'];
$this->request->data['Logo']['filemime'] = $file['type'];
return true;
}
}
return false;
}
and for the view code, i using this code.
Html->image(APP. 'logos' . DS.
$logo['Logo']['filename']); ?>
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cakephp download hanging in browser
I am trying to download a file thats already uploaded in cakephp app
folder. I am using the function below in my controller but it just opens a
blank page without even downloading the file
public function download($id = null) {
$this->viewClass = 'Media';
// Download app/outside_webroot_dir/example.pdf
$adminProcedure = $this->AdminProcedure->findById($id);
$filename = $adminProcedure['AdminProcedure']['filename'];
$this->request->params = array(
'id' => $adminProcedure['AdminProcedure']['id'],
'name' => substr($filename, 0, strrpos($filename, '.')),
'extension' => substr(strrchr($filename, '.'), 1),
'ext'=>'pdf',
'download' => true,
'path' => APP.'admin_procedures'.DS,
);
$this->set($params);
}
In my view i have used this bit of code to link to the file im trying to
download.
?php echo $this->Html->link(__('Download', true), array('action' =>
'download', $adminProcedure['AdminProcedure']['id'])); ?>
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Re: Cakephp download function not working
Hi lowpass
I managed to get the files to be uploaded into the admin_procedures folder
under my app folder and also insert into my table.The current problem that
im having now is when i try to download the file. Its giving me 2 errors
C:\xampp\htdocs\intraweb\app\admin_procedures\5113458e-9570-4f22-a1aa-07f483176c8c
was not found
and
Error: The requested address
'/intraweb/admin_procedures/download/5113458e-9570-4f22-a1aa-07f483176c8c'
was not found on this server.
Please not intraweb is the name of my application.
below is my code for the uploadFile and download functions
function uploadFile() {
$file = $this->request->data['AdminProcedure']['file'];
if ($file['error'] === UPLOAD_ERR_OK) {
$id = String::uuid();
if (move_uploaded_file($file['tmp_name'],
APP.'admin_procedures'.DS.$id)) {
$this->request->data['AdminProcedure']['id'] = $id;
$this->request->data['AdminProcedure']['user_id'] =
$this->Auth->user('id');
$this->request->data['AdminProcedure']['filename'] = $file['name'];
$this->request->data['AdminProcedure']['filesize'] = $file['size'];
$this->request->data['AdminProcedure']['filemime'] = $file['type'];
return true;
}
}
return false;
}
function download($id = null) {
$adminProcedure = $this->AdminProcedure->findById($id);
$this->viewClass = 'Media';
$filename = $adminProcedure['AdminProcedure']['filename'];
$this->set(array(
'id' => $adminProcedure['AdminProcedure']['id'],
'name' => substr($filename, 0, strrpos($filename, '.')),
'extension' => substr(strrchr($filename, '.'), 1),
'path' => APP.'admin_procedures'.DS,
'ext'=>'pdf',
'download' => true,
));
}
and here is my view file code where im trying to download the file -
Html->link(__('Download', true), array('action' =>
'download', $adminProcedure['AdminProcedure']['id'])); ?>
On Thu, Feb 7, 2013 at 2:32 AM, lowpass wrote:
> It's not clear what you mean by "when i view the index.ctp manually
> its not inserting any record in the table". Is a record being added to
> the DB? If not, post your add() action in full.
>
> But before doing that, check that the file is being uploaded.
>
> if (!empty($this->request->data))
> {
> die(debug($this->request->data)); // or log it
>
> Make sure that the form create options include 'type' => 'file' if the
> file array isn't there.
>
> On Wed, Feb 6, 2013 at 3:37 AM, Victor Musvibe
> wrote:
> > I am struggling with a download functionality for cakephp2.x. Here is
> what i
> > am trying to achieve.
> >
> > I am uploading my files to a folder named procedures_uploads after i
> upload
> > the file i should be able to download it.
> >
> > Currently when i upload the file from my add.ctp its not redirecting to
> the
> > index.ctp and when i view the index.ctp manually its not inserting any
> > record in the table . Below is my code for the download functionality and
> > the add function
> >
> > /** download functionality */
> >
> > function download($id = null) {
> > $adminProcedure = $this->AdminProcedure->findById($id);
> > $this->viewClass = 'Media';
> > $filename = $adminProcedure['AdminProcedure']['filename'];
> > $this->set(array(
> > 'id' => $adminProcedure['AdminProcedure']['id'],
> > 'name' => substr($filename, 0, strrpos($filename,
> > '.')),
> > 'extension' => substr(strrchr($filename,
> '.'),
> > 1),
> > 'path' => APP.'procedures_uploads'.DS,
> > 'ext'=>'pdf',
> > 'download' => true,
> >
> > )); }
> >
> > And this is how i am saving the data in my add function
> >
> > if ($this->uploadFile() &&
> > $this->AdminProcedure->save($this->request->data))
> >
> > Does anyone know how to solve this proplem?
> >
> > your assistance would be greatly appreciated.
> >
> > --
> > Like Us on FaceBook https://ww
Cakephp download function not working
I am struggling with a download functionality for cakephp2.x. Here is what
i am trying to achieve.
I am uploading my files to a folder named procedures_uploads after i upload
the file i should be able to download it.
Currently when i upload the file from my add.ctp its not redirecting to the
index.ctp and when i view the index.ctp manually its not inserting any
record in the table . Below is my code for the download functionality and
the add function
/** download functionality */
function download($id = null) {
$adminProcedure = $this->AdminProcedure->findById($id);
$this->viewClass = 'Media';
$filename = $adminProcedure['AdminProcedure']['filename'];
$this->set(array(
'id' => $adminProcedure['AdminProcedure']['id'],
'name' => substr($filename, 0, strrpos($filename,
'.')),
'extension' => substr(strrchr($filename, '.'),
1),
'path' => APP.'procedures_uploads'.DS,
'ext'=>'pdf',
'download' => true,
)); }
And this is how i am saving the data in my add function
if ($this->uploadFile() &&
$this->AdminProcedure->save($this->request->data))
Does anyone know how to solve this proplem?
your assistance would be greatly appreciated.
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Re: ACL - Error Messages after Add New User
Hi Karthi
I have the same problem as the person who posted the errors. I truncated
the the 2 tables and still doesn't work.
Do you perhaps have another solution to this?
Thanks
Victor
On Wednesday, 21 March 2012 19:28:17 UTC+2, karthik wrote:
>
> First truncate all data's in GROUP and USER table then add data's once
> again.
> Make sure whether you have linked GROUP and USER model correctly using
> $actsAs requester. and its relations GROUP hasMany USER and USER
> belongsTo GROUP
>
> -karthi
>
> On Mar 18, 9:26 am, Passivhaus Experte
> wrote:
> > Hi,
> >
> > I'm a newbie.
> >
> > I use the CakePHP Version 2.1.0 and followed the following
> descriptionhttp://
> book.cakephp.org/2.0/en/tutorials-and-examples/simple-acl-cont...
> >
> > Currently I'm at the point "Acts As a Requester" and have the source
> > code added to the Models User and Group. Also, I've successfully created
> > 3 groups. When I add a user to the User table the user is created, but
> > in the table Aros was no record is added...
> >
> > I am a little puzzled, hope you can help me.
> >
> > Error Messages:
> >
> --
>
>
> >
> > Notice (8): Array to string conversion
> > [CORE/Cake/Model/Datasource/DboSource.php, line 436]
> > Code Context
> >
> > $sql= 'node'
> > $params = array(
> > (int) 0 => array(
> > )
> > )
> > $prepareOptions = array()
> > $this = object(Mysql) {}
> > $query = object(PDOStatement) {}
> >
> > PDOStatement::execute() - [internal], line ??
> > DboSource::_execute() - CORE/Cake/Model/Datasource/DboSource.php, line
> > 436
> > DboSource::execute() - CORE/Cake/Model/Datasource/DboSource.php, line
> > 403
> > DboSource::fetchAll() - CORE/Cake/Model/Datasource/DboSource.php, line
> > 646
> > DboSource::query() - CORE/Cake/Model/Datasource/DboSource.php, line 588
> > Model::__call() - CORE/Cake/Model/Model.php, line 776
> > Aro::node() - CORE/Cake/Model/Behavior/AclBehavior.php, line 88
> > AclBehavior::node() - CORE/Cake/Model/Behavior/AclBehavior.php, line 88
> > AclBehavior::afterSave() - CORE/Cake/Model/Behavior/AclBehavior.php,
> > line 106
> > ObjectCollection::trigger() - CORE/Cake/Utility/ObjectCollection.php,
> > line 130
> > call_user_func - [internal], line ??
> > CakeEventManager::dispatch() - CORE/Cake/Event/CakeEventManager.php,
> > line 246
> > Model::save() - CORE/Cake/Model/Model.php, line 1730
> > UsersController::add() - APP/Controller/UsersController.php, line 68
> > ReflectionMethod::invokeArgs() - [internal], line ??
> > Controller::invokeAction() - CORE/Cake/Controller/Controller.php, line
> > 488
> > Dispatcher::_invoke() - CORE/Cake/Routing/Dispatcher.php, line 103
> >
> >
> --
>
>
> >
> > Database Error
> >
> > Error: SQLSTATE[42000]: Syntax error or access violation: 1064 You have
> > an error in your SQL syntax; check the manual that corresponds to your
> > MySQL server version for the right syntax to use near 'node' at line 1
> >
> > SQL Query: node
> >
> > Notice: If you want to customize this error message, create
> > app/View/Errors/pdo_error.ctp
> > Stack Trace
> >
> > CORE/Cake/Model/Datasource/DboSource.php line 436 →
> > PDOStatement->execute(array)
> > CORE/Cake/Model/Datasource/DboSource.php line 403 →
> > DboSource->_execute(string, array)
> > CORE/Cake/Model/Datasource/DboSource.php line 646 →
> > DboSource->execute(string, array, array)
> > CORE/Cake/Model/Datasource/DboSource.php line 588 →
> > DboSource->fetchAll(string, array, array)
> > CORE/Cake/Model/Model.php line 776 → DboSource->query(string,
> > array, Aro)
> > CORE/Cake/Model/Behavior/AclBehavior.php line 88 →
> > Model->__call(string, array)
> > CORE/Cake/Model/Behavior/AclBehavior.php line 88 → Aro->node(array)
> > CORE/Cake/Model/Behavior/AclBehavior.php line 106 →
> > AclBehavior->node(User, array, string)
> > [internal function] → AclBehavior->afterSave(User, boolean, array)
> > CORE/Cake/Utility/ObjectCollection.php line 130 →
> > call_user_func_array(array, array)
> > [internal function] → ObjectCollection->trigger(CakeEvent)
> > CORE/Cake/Event/CakeEventManager.php line 246 →
> > call_user_func(array, CakeEvent)
> > CORE/Cake/Model/Model.php line 1730 →
> > CakeEventManager->dispatch(CakeEvent)
> > APP/Controller/UsersController.php line 68 → Model->save(array)
> > [internal function] → UsersController->add()
> > CORE/Cake/Controller/Controller.php line 488 →
> > ReflectionMethod->invokeArgs(UsersController, array)
> > CORE/Cake/Routing/Dispatcher.php line 103 →
> > Controller->invokeAction(CakeRequest)
> > CORE/Cake/Routing/Dispatcher.php line 85 →
> > Dispatcher->_invoke(UsersCo
