Re: $this-action = images ??
THANK YOU! On Jul 30, 12:08 am, Grant Cox [EMAIL PROTECTED] wrote: Or, are you referring to any images in your view that have a relative path (and you aren't using the HTML helper image() function)? If you view localhost/users/index, and there is a relative image images/yourimage.jpg, then your browser will actually request localhost/users/images/yourimage.jpg. This is why you should always use a full path, or preferably use the HTML helper image() function, which does this for you. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups Cake PHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
$this-action = images ??
Sorry, I'm such a noob and I'm swimming through batter. I'm getting a weird action... After my expected action runs, I get a second action of 'images' for some weird reason (I have no idea). My process is really simple (no components, vendors, elements, etc). Basically, I have this in a controller: function beforeFilter() { $actionCheck; if (!$this-Session-check('Username')) { $this-Session-write('Username', 'Anon'); } switch($this-action) { case 'view': case 'vote': $actionCheck= null; break; default: $actionCheck= 'update'; break; } if (!empty($action)) { $this-access = @$this-Acl-check($this-Session- read('Username'), $this-name, $actionCheck); } else { $this-access = true; } if (!$this-access) { if ('Anon' != $this-Session-read('Username')) { $this-redirect('/login/denied'); } else { $this-Session-write('next_page','/'.$this-name.'/'. $this-action); $this-redirect('/login'); } die(); } } The first time through $this-action is 'view' or some other expected action. Then (after my action completes) it will run again with the action of 'images'. In other words, if I set a breakpoint on the switch in this controller it will hit that breakpoint twice, the first with the expected action and the second with action set to 'images.' Any ideas? Is this the expected operation of Cake? Thanks, Shawn --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups Cake PHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: $this-action = images ??
Or, are you referring to any images in your view that have a relative path (and you aren't using the HTML helper image() function)? If you view localhost/users/index, and there is a relative image images/yourimage.jpg, then your browser will actually request localhost/users/images/yourimage.jpg. This is why you should always use a full path, or preferably use the HTML helper image() function, which does this for you. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups Cake PHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---