Access the model name from a view
Hi again, my dear baker friends. Until now, when I've written this in a controller: $paginatedQuery = $this-paginate($this-modelClass); I've coded this in a view to access the information that it returns (inside a foreach loop, of course): $row['ModelName']['user_login'] That is, hard-coding the name of the model in the view. My doubt is: How can I access, from a view, the name of its associated model? I haven't been able to find this answer! Again, thanks a lot in advance for your time (I promise not to write more messages today ;-) --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Access the model name from a view
How about $modelName = key($this-params['paging']); That should do the trick. hth grigri On Jul 20, 11:47 am, jordicakephp jordicake...@gmail.com wrote: Hi again, my dear baker friends. Until now, when I've written this in a controller: $paginatedQuery = $this-paginate($this-modelClass); I've coded this in a view to access the information that it returns (inside a foreach loop, of course): $row['ModelName']['user_login'] That is, hard-coding the name of the model in the view. My doubt is: How can I access, from a view, the name of its associated model? I haven't been able to find this answer! Again, thanks a lot in advance for your time (I promise not to write more messages today ;-) --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Access the model name from a view
Thanks a lot, grigri. Your trick worked perfectly and I didn't know I can access the parameters of a view in the same way I access the parameters of a controller. What a disaster! Regards. On 20 jul, 14:19, grigri j...@hendersonwebdesign.com wrote: How about $modelName = key($this-params['paging']); That should do the trick. hth grigri On Jul 20, 11:47 am, jordicakephp jordicake...@gmail.com wrote: Hi again, my dear baker friends. Until now, when I've written this in a controller: $paginatedQuery = $this-paginate($this-modelClass); I've coded this in a view to access the information that it returns (inside a foreach loop, of course): $row['ModelName']['user_login'] That is, hard-coding the name of the model in the view. My doubt is: How can I access, from a view, the name of its associated model? I haven't been able to find this answer! Again, thanks a lot in advance for your time (I promise not to write more messages today ;-) --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
