I created a plugin that handles all security issues with Cake / Ajax requests.
Simply add a $this>_secureForm() which adds a _key and it adds a token to the form and on request the _key matches the users _lock Controller will generate a new key on every request. All though it will not handle dynamic fields if added. But if you have a form with set fields it will grab the field names, hash them and call it a lock and compare it to the key on every request...... Dave Maharaj Freelance Designer | Developer Description: header_logo www.movepixels.com | <mailto:d...@movepixels.com> d...@movepixels.com | 709.800.0852 From: cake-php@googlegroups.com [mailto:cake-php@googlegroups.com] On Behalf Of euromark Sent: Friday, August 16, 2013 5:10 PM To: cake-php@googlegroups.com Subject: Re: bootstrap twitter typeahead , dont work for me in cakephp Never create a new response object there is already one available in your controller just use $this->response->body($content); as documented Am Freitag, 16. August 2013 19:16:32 UTC+2 schrieb cesar calvo: I use this in my AppController public function jsonResponse($array) { return new CakeResponse(array('body' => json_encode($array))); } Then on a controller call jsonResponse Note: if you are usin Security component on beforeFilter: if ($this->request->is('ajax')) $this->Security->unlockedActions = array($this->request->action); On Thursday, August 15, 2013 11:03:34 PM UTC-3, Renato Bigliazzi wrote: Hi , I can not do the twitter bootstrap component typeahead work with cake. i use https://github.com/rudylee/cbunny , but dont work form me. In my view JS <script type="text/javascript"> $(document).ready(function(){ $('#itemdesc').typeahead({ source: function (query, process) { return $.ajax({ url:'<?php echo Router::url(array('controller'=>'Invoices','action'=>'localizaprodutos'));?> ', type: 'get', data: {q: query}, dataType: 'json', success: function (json) { return process(json); } }); } }); }); </script> HTML <input type="text" name="itemdesc[]" class="input-large" id="itemdesc" data-provide="typeahead"/> and controller public function localizaprodutos(){ $this->autoRender = false; $this->RequestHandler->respondAs('json'); // get the search term from URL $term = $this->request->query['q']; $users = $this->Invoice->Invoicedetail->Inventoryitem->find('all',array( 'conditions' => array( 'Inventoryitem.desc LIKE' => '%'.$term.'%' ) )); // Format the result for select2 $result = array(); foreach($produtos as $key => $produto) { array_push($result, $produto['Inventoryitem']['desc']); } $produtos = $result; echo json_encode($produtos); } Thanks Renato -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups "CakePHP" group. To unsubscribe from this group and stop receiving emails from it, send an email to cake-php+unsubscr...@googlegroups.com. To post to this group, send email to cake-php@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php. For more options, visit https://groups.google.com/groups/opt_out. -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups "CakePHP" group. To unsubscribe from this group and stop receiving emails from it, send an email to cake-php+unsubscr...@googlegroups.com. To post to this group, send email to cake-php@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php. For more options, visit https://groups.google.com/groups/opt_out.
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