Re: Closing $ajax-form()
I can't get $ajax-submit() to work, only $form-end('Submit'). What's the difference between the two? On Jan 26, 7:59 am, Graham Weldon gra...@grahamweldon.com wrote: $ajax-submit() creates an ajax submit element. $form-end('something') creates a submit button, and ends the form. $ajax-form() starts a form. Your usage will depends very much on your implementation, and requirements. The simple reason for there not being an $ajax-formEnd() is because its super easy to do: $form-end(). Both output /form. here are some options to illustrate usage: $form-create(); $form-inputs(); $form-end('submit'); $ajax-form(); $form-inputs(); $form-end('submit'); $ajax-form(); $form-inputs(); $ajax-submit(); $form-end(); On Mon, 26 Jan 2009 05:55:02 -0800 (PST), Pyrite thelette...@gmail.com wrote: So what is the point/usage of $ajax-submit() then if it does not actually submit the form created with $ajax-form() ? On Jan 23, 8:05 am, Mono sirmonit...@gmail.com wrote: When u use the ajax-form, the only difference with a normal form is the first line. Normal Form: $form-create (...) $form-input () $form-input () $form-end ('Send') Ajax Form: $ajax-form (...) $form-input () $form-input () $form-end ('Send') On 22 Jan., 22:47, Pyrite thelette...@gmail.com wrote: How do you put the close tag in a form created by $ajax-form() ?? Why is there not an $ajax-formEnd() similar to the FormHelper's $form-end () ? Also, when I create a form with $ajax-form(), and I add a submit with $ajax-submit(), it does not submit the form. A usage example would be great. I can only get it to submit the form if I use $form-end ('Submit') instead of $ajax-submit().- Hide quoted text - - Show quoted text -- Hide quoted text - - Show quoted text - --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Closing $ajax-form()
$ajax-submit() will create a submit button. However, it will not end your form. You need to also end your form with $form-end(). $ajax-submit() will work, as indicated previously: $ajax-form(); $form-inputs(); $ajax-submit(); $form-end(); Cheers, Graham On Tue, 27 Jan 2009 06:21:45 -0800 (PST), Pyrite thelette...@gmail.com wrote: I can't get $ajax-submit() to work, only $form-end('Submit'). What's the difference between the two? On Jan 26, 7:59 am, Graham Weldon gra...@grahamweldon.com wrote: $ajax-submit() creates an ajax submit element. $form-end('something') creates a submit button, and ends the form. $ajax-form() starts a form. Your usage will depends very much on your implementation, and requirements. The simple reason for there not being an $ajax-formEnd() is because its super easy to do: $form-end(). Both output /form. here are some options to illustrate usage: $form-create(); $form-inputs(); $form-end('submit'); $ajax-form(); $form-inputs(); $form-end('submit'); $ajax-form(); $form-inputs(); $ajax-submit(); $form-end(); On Mon, 26 Jan 2009 05:55:02 -0800 (PST), Pyrite thelette...@gmail.com wrote: So what is the point/usage of $ajax-submit() then if it does not actually submit the form created with $ajax-form() ? On Jan 23, 8:05 am, Mono sirmonit...@gmail.com wrote: When u use the ajax-form, the only difference with a normal form is the first line. Normal Form: $form-create (...) $form-input () $form-input () $form-end ('Send') Ajax Form: $ajax-form (...) $form-input () $form-input () $form-end ('Send') On 22 Jan., 22:47, Pyrite thelette...@gmail.com wrote: How do you put the close tag in a form created by $ajax-form() ?? Why is there not an $ajax-formEnd() similar to the FormHelper's $form-end () ? Also, when I create a form with $ajax-form(), and I add a submit with $ajax-submit(), it does not submit the form. A usage example would be great. I can only get it to submit the form if I use $form-end ('Submit') instead of $ajax-submit().- Hide quoted text - - Show quoted text -- Hide quoted text - - Show quoted text - -- Cheers, Graham Weldon w. http://grahamweldon.com e. gra...@grahamweldon.com p. +61 407 017 293 --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Closing $ajax-form()
So what is the point/usage of $ajax-submit() then if it does not actually submit the form created with $ajax-form() ? On Jan 23, 8:05 am, Mono sirmonit...@gmail.com wrote: When u use the ajax-form, the only difference with a normal form is the first line. Normal Form: $form-create (...) $form-input () $form-input () $form-end ('Send') Ajax Form: $ajax-form (...) $form-input () $form-input () $form-end ('Send') On 22 Jan., 22:47, Pyrite thelette...@gmail.com wrote: How do you put the close tag in a form created by $ajax-form() ?? Why is there not an $ajax-formEnd() similar to the FormHelper's $form-end () ? Also, when I create a form with $ajax-form(), and I add a submit with $ajax-submit(), it does not submit the form. A usage example would be great. I can only get it to submit the form if I use $form-end ('Submit') instead of $ajax-submit().- Hide quoted text - - Show quoted text - --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Closing $ajax-form()
$ajax-submit() creates an ajax submit element. $form-end('something') creates a submit button, and ends the form. $ajax-form() starts a form. Your usage will depends very much on your implementation, and requirements. The simple reason for there not being an $ajax-formEnd() is because its super easy to do: $form-end(). Both output /form. here are some options to illustrate usage: $form-create(); $form-inputs(); $form-end('submit'); $ajax-form(); $form-inputs(); $form-end('submit'); $ajax-form(); $form-inputs(); $ajax-submit(); $form-end(); On Mon, 26 Jan 2009 05:55:02 -0800 (PST), Pyrite thelette...@gmail.com wrote: So what is the point/usage of $ajax-submit() then if it does not actually submit the form created with $ajax-form() ? On Jan 23, 8:05 am, Mono sirmonit...@gmail.com wrote: When u use the ajax-form, the only difference with a normal form is the first line. Normal Form: $form-create (...) $form-input () $form-input () $form-end ('Send') Ajax Form: $ajax-form (...) $form-input () $form-input () $form-end ('Send') On 22 Jan., 22:47, Pyrite thelette...@gmail.com wrote: How do you put the close tag in a form created by $ajax-form() ?? Why is there not an $ajax-formEnd() similar to the FormHelper's $form-end () ? Also, when I create a form with $ajax-form(), and I add a submit with $ajax-submit(), it does not submit the form. A usage example would be great. I can only get it to submit the form if I use $form-end ('Submit') instead of $ajax-submit().- Hide quoted text - - Show quoted text - --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Closing $ajax-form()
When u use the ajax-form, the only difference with a normal form is the first line. Normal Form: $form-create (...) $form-input () $form-input () $form-end ('Send') Ajax Form: $ajax-form (...) $form-input () $form-input () $form-end ('Send') On 22 Jan., 22:47, Pyrite thelette...@gmail.com wrote: How do you put the close tag in a form created by $ajax-form() ?? Why is there not an $ajax-formEnd() similar to the FormHelper's $form-end () ? Also, when I create a form with $ajax-form(), and I add a submit with $ajax-submit(), it does not submit the form. A usage example would be great. I can only get it to submit the form if I use $form-end ('Submit') instead of $ajax-submit(). --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Closing $ajax-form()
How do you put the close tag in a form created by $ajax-form() ?? Why is there not an $ajax-formEnd() similar to the FormHelper's $form-end () ? Also, when I create a form with $ajax-form(), and I add a submit with $ajax-submit(), it does not submit the form. A usage example would be great. I can only get it to submit the form if I use $form-end ('Submit') instead of $ajax-submit(). --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Closing $ajax-form()
i use $form-end(); and it does submit trough ajax updater successfully. see the code which is generated by ajax-form(); you will figure out that it just a normal new Ajax.Updater(). sometimes i meet my limitation when use ajax on cake, so i just write normal html and javascript on the view layer. From: Pyrite thelette...@gmail.com To: CakePHP cake-php@googlegroups.com Sent: Friday, January 23, 2009 6:47:09 AM Subject: Closing $ajax-form() How do you put the close tag in a form created by $ajax-form() ?? Why is there not an $ajax-formEnd() similar to the FormHelper's $form-end () ? Also, when I create a form with $ajax-form(), and I add a submit with $ajax-submit(), it does not submit the form. A usage example would be great. I can only get it to submit the form if I use $form-end ('Submit') instead of $ajax-submit(). --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---